LOCAL CONTEST - TRIG-STAR PROBLEM

Sep 15, 2026

Local Trig-Star contest materials for a boundary surveying problem involving lot 109. The scenario describes an owner seeking a building permit and a land surveyor reestablishing missing corner point C using existing monuments at points A, B, and D. Trees obstruct visibility along lot lines, so a control point at F is set to observe all four corner locations, with additional geometric constraints including parallel lines and collinearity of C with D and E.

LanguageEnglish

CategoryExam

FormatPDF

Pages6

Reading Time15 min

AccessFree to download

LOCAL CONTEST

TRIG-STAR PROBLEM

REQUIRED ANSWER FORMAT

TRIG-STAR MISCELLANEOUS DATA

TRIG-STAR ANSWER KEY LOCAL CONTEST

# SAMPLE | TRIG-STAR PROBLEM LOCAL CONTEST
PRINT NAME:
Al
KNOWN:DISTANCE AC=381.25 DISTANCE BC=431.23
REQUIRED ANSWER FORMAT
FIND:
≤ACB=_ (5 POINTS)
DISTANCES:NEAREST HUNDREDTH
ANGLES:DEGREES-MINUTES-SECONDS
DISTANCE AB= ___ (5 POINTS)
TO THE NEAREST SECOND | | | | --- | --- | --- | | TRIG-STAR PROBLEM LOCAL
F
E
KNOWN:DISTANCE EF =193.314EFG =12131'30” FEG =4150'1
FIND:
4EGF=_____ _(6 POINTS)
DISTANCE EH =— (6 POINTS)
DISTANCE FH=______(6 POINTS)
DISTANCE FG=_ __ (6 POINTS)
DISTANCE GH =_ __(6 POINTS)
PA | CONTEST
4” | | | | REQUIRED ANSWER FORMAT
DISTANCES:NEAREST HUNDREDTH
ANGLES:DEGREES-MINUTES-SECONDS
TO THE NEAREST SECOND
GE TOTAL:__________POINTS | | SHEET10F 3 COPYRIGHT-NSPS | TRIG-STAR PROBLEM LOCAL CONTEST
510.55
261.30
A
KNOWN:DISTANCE BC =510.55 DISTANCE CD =261.30
4BAD=8321'02”
— _(10 POINTS)
FIND: DISTANCE AB =.
REQUIRED ANSWER FORMAT
DISTANCES:NEAREST HUNDREDTH
DISTANCE AD=___ __(10 POINTS)
DISTANCE AC=__ __(10 POINTS)
______POINTS
PAGE TOTAL:_ | | --- | | | | --- | COPYRIGHT-NSPS SHEET 2 OF 3 # LOCAL CONTEST TRIG-STAR PROBLEM THE OWNER OF LOT 109,SHOWN AS FGURE ABCD,WANTS TO OBTAIN A BUILDING PERMIT,ANDHIRES A LAND SURVEYOR TO COMPLETE A BOUNDARY SURVEY THE SURVEYOR FINDS EXISTNG MONUMENTS AT POINTS A,B,AND D,AND NEEDS TO REESTABLISHPOINT C.TREES OBSTRUCT THE VEW ALONG LOT LINES AS SHOWN,SO THE SURVEYOR SETS ACONTROL POINT AT POINTF FROM WHICH ALL FOUR LOT CORNER LOCATONS CAN BE SEEN.THESURVEYOR ALSO FINDS A MONUMENT AT POINT E,AND NOTES THAT POINT C WOULD BE ON ASTRAGHT LINE CONNECTNG POINTS D AND E.IT IS ALSO NOTED THAT LINE AD IS PARALLEL TO LINEBC. THE SURVEYOR's MEASURED ANGLES AND DISTANCES ARE SHOWN BELOW BD DISTANCE DA= (6 POINTS) DISTANCE FC=. (6 POINTS)DISTANCE DC=. (6 POINTS)ANGLE BFC =. (6 POINTS)AREA ABCD=. (6 POINTS) | REQUIRED ANSWER FORMAT
DISTANCES:NEAREST HUNDREDTH
NEAREST WHOLE UNIT
AREA: | | --- | PAGE TOTAL:. POINTSCOPYRIGHT-NSPSSHEET 30F 3 | TRIG-STAR MISCELLANEOUS DATA
RIGHT TRIANGLE FORMULAS
PYTHAGOREAN THEOREM:a²+b²=c²
AREA:2ab
TRIGONOMETRIC FUNCTIONS:sin A=8,cos A=,
OBLIQUE TRIANGLE FORMULAS
LAW OF COSINES:a²=b²+c²-2bcCos A
AREA:2bh
CIRCLE FORMULAS
RADIUS =r
DIAMETER =d
CIRCUMFERENCE:2πr or πd
AREA:πr²
ONE DEGREE(1)OF ARC =60 MINUTES(60')OF ARC
ONE MINUTE(1')OF ARC =60 SECONDS(60")OF ARC
THEREFORE ONE DEGREE OF ARC(1)=3600 SECONDS
OF ARC. | | --- | | TRIG-STAR ANSWER KEY LOCAL CONTEST
PAGE 1
2751'33”
ACB =
DISTANCE AB =
201.51
PAGE 1
16°38'16”
EGF
DISTANCE EH
144.02
DISTANCE FH
128.94
DISTANCE FG
450.34
431.48
DISTANCE GH
PAGE 2
DISTANCE AB:
322.59
544.47
DISTANCE AD =
603.92
DISTANCE AC =
PAGE 3
121.90
DISTANCE DA
二
89.47
DISTANCE FC=
123.78
DISTANCE DC=
79*58'42”
BFC=
15,287
AREA ABCD = | | --- | COPYRIGHT-NSPS

FAQs

What is the main task of the Trig-Star local contest problem?

The surveyor must reestablish the location of point C and determine requested distances, angles, and area based on measured geometry and constraints.

Why is point F introduced in the problem?

Trees block the view along the lot lines, so point F is used as a control point from which the four lot corner locations can be seen.

What geometric relationships are given for the boundary layout?

Point C is noted to lie on a straight line connecting points D and E, and line AD is stated to be parallel to line BC.

Sep 15, 2026

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