[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"detail-sidebar-cat-1-en-105":3,"doc-seo-572898-105":53,"doc-detail-572898-en":127},{"code":4,"msg":5,"data":6},0,"success",[7,14,19,24,29,34,39,44,49],{"id":8,"doc_module":9,"doc_module_name":10,"category_name":11,"show_sort_weight":12,"slug":13},11,1,"Template","Presentations",90,"presentations",{"id":15,"doc_module":9,"doc_module_name":10,"category_name":16,"show_sort_weight":17,"slug":18},12,"Resumes",80,"resumes",{"id":20,"doc_module":9,"doc_module_name":10,"category_name":21,"show_sort_weight":22,"slug":23},14,"Invoices",70,"invoices",{"id":25,"doc_module":9,"doc_module_name":10,"category_name":26,"show_sort_weight":27,"slug":28},15,"Posters",60,"posters",{"id":30,"doc_module":9,"doc_module_name":10,"category_name":31,"show_sort_weight":32,"slug":33},16,"Social Media",50,"social-media",{"id":35,"doc_module":9,"doc_module_name":10,"category_name":36,"show_sort_weight":37,"slug":38},17,"Forms",40,"forms",{"id":40,"doc_module":9,"doc_module_name":10,"category_name":41,"show_sort_weight":42,"slug":43},18,"Letters",30,"letters",{"id":45,"doc_module":9,"doc_module_name":10,"category_name":46,"show_sort_weight":47,"slug":48},21,"Paper Templates",5,"papers-templates",{"id":50,"doc_module":9,"doc_module_name":10,"category_name":51,"show_sort_weight":4,"slug":52},158,"General","general-158",{"code":4,"msg":54,"data":55},"ok",{"site_id":56,"language":57,"slug":58,"title":59,"keywords":60,"description":61,"schema_data":62,"social_meta":120,"head_meta":122,"extra_data":124,"updated_unix":126},105,"en","eightfold-mcat-acid-base-concept-map-study-guide","Eightfold MCAT Acid-Base Concept Map - Study Guide","","This document provides a comprehensive concept map and procedural guide for solving acid-base chemistry problems, specifically designed for MCAT preparation. It delineates the mathematical relationships between pH, pOH, hydrogen ion concentration [H+], hydroxide concentration [OH-], acid dissociation constants (Ka), and base dissociation constants (Kb). The guide offers a structured three-step method for students to identify variables, map the conversion path, and execute calculations to determine unknown acidity or alkalinity levels in a solution. It serves as an essential reference for mastering stoichiometric and logarithmic chemistry calculations required in medical entrance examinations.",{"@graph":63,"@context":119},[64,80,102],{"@type":65,"itemListElement":66},"BreadcrumbList",[67,71,74,77],{"item":68,"name":69,"@type":70,"position":9},"https://docshare.wps.com","Home","ListItem",{"item":72,"name":10,"@type":70,"position":73},"https://docshare.wps.com/template/",2,{"item":75,"name":51,"@type":70,"position":76},"https://docshare.wps.com/template/general/",3,{"item":78,"name":59,"@type":70,"position":79},"https://docshare.wps.com/template/eightfold-mcat-acid-base-concept-map-study-guide/572898/",4,{"url":78,"name":59,"@type":81,"image":82,"author":87,"headline":59,"publisher":90,"fileFormat":93,"inLanguage":57,"description":61,"dateModified":94,"datePublished":95,"encodingFormat":93,"isAccessibleForFree":96,"interactionStatistic":97},"DigitalDocument",{"url":83,"@type":84,"width":85,"height":86},"https://docshare.wps.com/thumbnails/eightfold-mcat-acid-base-concept-map-study-guide/572898.png","ImageObject",442,249,{"name":88,"@type":89},"Margaret","Person",{"url":68,"name":91,"@type":92},"DocShare","Organization","application/pdf","2026-10-19","2026-10-13",true,{"@type":98,"interactionType":99,"userInteractionCount":101},"InteractionCounter",{"@type":100},"ViewAction",6,{"@type":103,"mainEntity":104},"FAQPage",[105,111,115],{"name":106,"@type":107,"acceptedAnswer":108},"What is the relationship between pH and pOH?","Question",{"text":109,"@type":110},"The sum of pH and pOH in a solution is always equal to 14, as expressed by the formula pH + pOH = 14.","Answer",{"name":112,"@type":107,"acceptedAnswer":113},"How do you calculate pH from a given hydroxide concentration?",{"text":114,"@type":110},"First, calculate the pOH by taking the negative log of the hydroxide concentration (-log[OH-]), then subtract the resulting pOH value from 14 to find the pH.",{"name":116,"@type":107,"acceptedAnswer":117},"What formula is used to relate Ka and Kb?",{"text":118,"@type":110},"The product of the acid dissociation constant (Ka) and the base dissociation constant (Kb) is equal to 10^-14.","https://schema.org",{"og:url":78,"og:type":121,"og:title":59,"og:site_name":91,"og:description":61},"article",{"robots":123,"canonical":78},"index,follow",{"doc_id":125,"site_id":56},572898,1792019195,{"code":4,"msg":5,"data":128},{"doc_id":125,"user_id":129,"nickname":88,"user_avatar":130,"doc_module":9,"category_id":50,"category_name":51,"doc_title":59,"doc_description":61,"doc_content":131,"file_id":132,"file_url":133,"file_type":134,"file_size":135,"view_count":101,"is_deleted":4,"is_public":9,"is_downloadable":9,"audit_status":9,"page_count":9,"language":136,"language_code":57,"site_id":56,"html_lang":57,"table_of_contents":137,"faqs":138,"seo_title":139,"seo_description":61,"update_tm":140,"read_time":4},137451207643,"https://ap-avatar.wpscdn.com/davatar_3d24733baf745e90a7e4bdd5f77d97b2","Eightfold MCAT Acid-Base Concept Map  \n| pH\u003Cbr>pH + pOH = 14\u003Cbr>pOH\u003Cbr>\u003Cbr>-log[H+]\u003Cbr>10-pH\u003Cbr>-log[OH- ]\u003Cbr>10-pOH\u003Cbr> [H+]\u003Cbr>[H+] x [OH- ] = 10-14\u003Cbr>[OH-]\u003Cbr>Ka = x2/[Weak Acid] x = [H+]\u003Cbr>Ka x Kb = 10-14\u003Cbr>x = [OH- ]\u003Cbr>Kb = x2/[Weak Base]\u003Cbr>K\u003Cbr>a\u003Cbr>\u003Cbr>Kb\u003Cbr>\u003Cbr>\u003Cbr>\u003Cbr>\u003Cbr>\u003Cbr>| | pKa |  |\n| --- | --- | --- | --- |\n|  |  | | pKa + pKb = 14 |\n|  |  | pKb |  |\n\nHow To Use  \n1) Determine what the question asks for and what you have been given  \nWhat is the pH of a solution if the hydroxide concentration is 10-9 M?  \nGiven [OH-] but the question wants pH  \n2) Plot out the path from given to the answer on the concept map (when possible convert between p-scales rather than concentrations or K values)  \npH  \npH + pOH = 14  \npOH  -log[OH- ]  [OH-]  \n3) Calculate the math as indicated in each step of the path you have plotted out on the map  \n-log[OH- ]  \npH + pOH = 14  \n[OH- ] = 10-9  \npOH = -log(10-9) = 9  \npH + pOH = 14  \npH + 9 = 14  \npH = 5","cbCaispz1OwN1E4O","https://ap.wps.com/l/cbCaispz1OwN1E4O","pdf",737359,"English","# Acid-Base Concept Map\n## How To Use","[{\"question\":\"What is the relationship between pH and pOH?\",\"answer\":\"The sum of pH and pOH in a solution is always equal to 14, as expressed by the formula pH + pOH = 14.\"},{\"question\":\"How do you calculate pH from a given hydroxide concentration?\",\"answer\":\"First, calculate the pOH by taking the negative log of the hydroxide concentration (-log[OH-]), then subtract the resulting pOH value from 14 to find the pH.\"},{\"question\":\"What formula is used to relate Ka and Kb?\",\"answer\":\"The product of the acid dissociation constant (Ka) and the base dissociation constant (Kb) is equal to 10^-14.\"}]","Eightfold MCAT Acid-Base Concept Map - Study Guide | PDF",1791929931]