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Secondly, we are aware that Dan also did not place last, so we know that he was either third, fourth or fifth, while we also now know that Adam had to have placed in the top three. Thirdly, we are sure that Fred placed ahead of Brad – this means that Brad couldn’t be first and Fred couldn’t be last. Curiously, the fact that Adam didn’t finish last is irrelevant here (this often occurs in UMAT questions, as extraneous information forces you to spend more time reading the question) . Fourthly, we know that Brad placed third – this is a crucial piece of knowledge as it confirms that Frank and Adam had to be in the top two, and that Cale and Eric therefore have to finish in the bottom three.  \nThe following table gives us a graphical description of the knowledge we have:  \n\n|  | 1 | 2 | 3 | 4 | 5 | 6 |\n| --- | --- | --- | --- | --- | --- | --- |\n| Adam |  |  | X | X | X | X |\n| Brad | X | X | ✓ | X | X | X |\n| Cale | X | X | X |  |  |  |\n| Dan | X | X | X |  |  | X |\n| Eric | X | X | X |  |  |  |\n| Fred |  |  | X | X | X | X |\n\nNow we can test each answer against the table:  \nA Dan finished after Eric.  \nDoes this have to be false? The table shows that Dan can finish fifth while Eric can finish fourth – therefore it is possible and isn’t necessarily false. This answer is incorrect.  \nB Adam finished three spots before Cale.  \nThis is possible as Cale can finish fifth or fourth and Adam could be second or first in that order, which satisfies the option. This answer is incorrect.  \nC Fred did not win the triathlon.  \nFred can come first, so this is incorrect.  \nD Cale and Eric finished fifth and fourth respectively.  \nThis answer may seem possible at first, as Cale and Eric can both finish in either fourth or fifth. However, it is vital to recognise that they cannot place in fourth or fifth (regardless of who takes which position) at the same time, as this would mean that Dan has to place last – which is impossible. Therefore, the table proves this answer must be false, and it is therefore the correct answer.  \nQuestion 2  \nThe Answer is A  \nTo answer this question, number the cross-breeding timings 1-5. Start with the known information, such as Foompy will be at number cross-bred last, that is, it will be at number 5. Rig-zig is either on 2, 3 or 4. Pittiti must be cross-bred before Gromepy and Goodell, and will obviously not be cross-bred last, like Foompy fish. Rig-zig cannot be used first. Therefore, Pittiti must be cross-bred first; hence ‘A’ is the correct answer choice.  \nQuestion 3  \nThe Answer is B  \nFlexibility is crucial in answering this question. That is, certain fish species have to be cross-bred at certain times of the day (inflexible cross-breeding) and others are flexible, that is such fish species can be cross-bred at various times of the day. Pittiti is not a flexible cross-breeding specie. Gromepy and Goodell are only somewhat flexible. Rigzig on the other hand, can be cross-bred second, third, or fourth. The best way for this to be determined is to write down as many combinations as possible, in terms of crossbreeding order. From here you will clearly see that ‘B’ is the key.  \nQuestion 4  \nThe answer is A  \nOption ‘B’ is incorrect because the graph does not show the individual effects of smoking and alcohol consumption on relative risk of developing laryngeal cancer. So, it is out of the scope of this diagram. Option ‘C’ is incorrect – as someone who smokes on average 11 cigarettes a day and drinks 90g/day of alcohol has a relative risk of 10 -which is used to compare their risk against other categorie","cbCaifasHQQag0dr","https://ap.wps.com/l/cbCaifasHQQag0dr","pdf",373614,"English","# Question 1\n## Answer D (positions and constraints)\n# Question 2\n## Answer A (ordering cross-breeding timings)\n# Question 3\n## Answer B (flexible vs inflexible cross-breeding)\n# Question 4\n## Answer A (non-linear relative risk from graph)\n# Question 5\n## Answer D (calculation of diarrhoea incidence and option testing)","[{\"question\":\"Why does Question 4 conclude option A is correct?\",\"answer\":\"The graph indicates risk does not increase linearly; instead, it shows more rapid, exponential-like growth as cigarette and alcohol use rises, implying a multiplying rather than additive effect.\"}]","UMAT NIE Q and A - Practice Questions | PDF",25]