[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"detail-sidebar-cat-0-en-105":3,"doc-seo-297677-105":59,"doc-detail-297677-en":131},{"code":4,"msg":5,"data":6},0,"success",[7,13,18,23,28,33,38,43,48,51,55],{"id":8,"doc_module":4,"doc_module_name":9,"category_name":10,"show_sort_weight":11,"slug":12},1,"Document","Story & Novel",90,"story-novel",{"id":14,"doc_module":4,"doc_module_name":9,"category_name":15,"show_sort_weight":16,"slug":17},2,"Literature",80,"literature",{"id":19,"doc_module":4,"doc_module_name":9,"category_name":20,"show_sort_weight":21,"slug":22},4,"Exam",70,"exam",{"id":24,"doc_module":4,"doc_module_name":9,"category_name":25,"show_sort_weight":26,"slug":27},5,"Comic",60,"comic",{"id":29,"doc_module":4,"doc_module_name":9,"category_name":30,"show_sort_weight":31,"slug":32},6,"Technology",50,"technology",{"id":34,"doc_module":4,"doc_module_name":9,"category_name":35,"show_sort_weight":36,"slug":37},7,"Healthcare",40,"healthcare",{"id":39,"doc_module":4,"doc_module_name":9,"category_name":40,"show_sort_weight":41,"slug":42},8,"Research & Report",30,"research-report",{"id":44,"doc_module":4,"doc_module_name":9,"category_name":45,"show_sort_weight":46,"slug":47},9,"Religion & Spirituality",20,"religion-spirituality",{"id":46,"doc_module":4,"doc_module_name":9,"category_name":49,"show_sort_weight":46,"slug":50},"World Cup","world-cup",{"id":52,"doc_module":4,"doc_module_name":9,"category_name":53,"show_sort_weight":52,"slug":54},10,"Lifestyle","lifestyle",{"id":56,"doc_module":4,"doc_module_name":9,"category_name":57,"show_sort_weight":24,"slug":58},19,"General","general",{"code":4,"msg":60,"data":61},"ok",{"site_id":62,"language":63,"slug":64,"title":65,"keywords":66,"description":67,"schema_data":68,"social_meta":124,"head_meta":126,"extra_data":128,"updated_unix":130},105,"en","surface-areas-lecture-4","Surface Areas - Lecture 4","","Lecture 4 focuses on solving surface-area problems involving composite solids. It includes questions where two cubes are joined end to end to form a cuboid, and tasks requiring total surface area calculations for blocks made from a cube and a hemisphere using pi=22/7. Further problems cover a solid cylinder with a conical cavity, a hemispherical depression cut from a cubical block, and a wooden article formed by scooping hemispheres from both ends of a cylinder, culminating in surface area and drilled-hole configurations in metallic blocks. Methods emphasize geometric formulas and unit handling.",{"@graph":69,"@context":123},[70,84,106],{"@type":71,"itemListElement":72},"BreadcrumbList",[73,77,79,82],{"item":74,"name":75,"@type":76,"position":8},"https://docshare.wps.com","Home","ListItem",{"item":78,"name":9,"@type":76,"position":14},"https://docshare.wps.com/document/",{"item":80,"name":20,"@type":76,"position":81},"https://docshare.wps.com/document/exam/",3,{"item":83,"name":65,"@type":76,"position":19},"https://docshare.wps.com/document/surface-areas-lecture-4/297677/",{"url":83,"name":65,"@type":85,"image":86,"author":91,"headline":65,"publisher":94,"fileFormat":97,"inLanguage":63,"description":67,"dateModified":98,"datePublished":99,"encodingFormat":97,"isAccessibleForFree":100,"interactionStatistic":101},"DigitalDocument",{"url":87,"@type":88,"width":89,"height":90},"https://docshare.wps.com/thumbnails/surface-areas-lecture-4/297677.png","ImageObject",300,407,{"name":92,"@type":93},"Maya Linwood","Person",{"url":74,"name":95,"@type":96},"DocShare","Organization","application/pdf","2026-10-20","2026-09-18",true,{"@type":102,"interactionType":103,"userInteractionCount":105},"InteractionCounter",{"@type":104},"ViewAction",11,{"@type":107,"mainEntity":108},"FAQPage",[109,115,119],{"name":110,"@type":111,"acceptedAnswer":112},"How do you find the surface area when two cubes are joined end to end?","Question",{"text":113,"@type":114},"Form the resulting cuboid by combining the lengths of the joined faces, then apply the cuboid surface area formula using the new dimensions.","Answer",{"name":116,"@type":111,"acceptedAnswer":117},"What information is needed to compute the total surface area of a cube-plus-hemisphere decorative block?",{"text":118,"@type":114},"Use the cube edge length and the hemisphere diameter, then add the exposed cube area and the hemisphere curved surface area, taking pi as 22/7 as instructed.",{"name":120,"@type":111,"acceptedAnswer":121},"How is the surface area of the remaining solid handled when a conical cavity is hollowed out?",{"text":122,"@type":114},"Calculate the original solid’s total surface area, subtract the areas removed by the conical cavity (including the cavity’s curved surface), and report the result to the nearest cm².","https://schema.org",{"og:url":83,"og:type":125,"og:title":65,"og:site_name":95,"og:description":67},"article",{"robots":127,"canonical":83},"index,follow",{"doc_id":129,"site_id":62},297677,1789746877,{"code":4,"msg":5,"data":132},{"doc_id":129,"user_id":133,"nickname":92,"user_avatar":134,"doc_module":4,"category_id":19,"category_name":20,"doc_title":65,"doc_description":67,"doc_content":135,"file_id":136,"file_url":137,"file_type":138,"file_size":139,"view_count":105,"is_deleted":4,"is_public":8,"is_downloadable":8,"audit_status":8,"page_count":105,"language":140,"language_code":63,"site_id":62,"html_lang":63,"table_of_contents":141,"faqs":142,"seo_title":143,"seo_description":67,"update_tm":130,"read_time":144},962084928432,"https://ap-avatar.wpscdn.com/davatar_155a257f0dc6eb9ab79c44ca47cae57d","# SURFACE AREASURFACE AREASS&VOLUMES&VOLUMESLecture\\#4\n\n\\#LP:Two cubes each of 10 cm edge are joined end to end.Find the surface areg of theresulting cuboid.  \na三10m  \na.←  Susate.area→2(9b+bh+h2)又(Qa×a+axa+a&u)(2a²+a²+2a²)入2×5a²10(10²(|0x100SAx 10TDc²  \n\\#LP:Two cubes each of volume 64 cm³are joined end to end.Find the surface area of theresulting cuboid.  \n ooid sA→10  \n10(y  \n 10×16SA李160cm²Y  \n(64cm^2  \ngiven,vo|=6Ycm³q³=64  \n0:36Y  \n\\#LP:The decorative block is made of two solids -a cube and a hemisphere.The base ofthe block is a cube with edge 5cm,and the hemisphere fixed on the top has a diameter of4.2cm Find the total surface area of the block.(Take pi=22/7)a=6cm:4 JmG=2|cmT3A (ombinationa TSA cube -Q5.d boxe+(SA5em可hn6a2一^+xml6a^+x5cm[ 6(5)²+0=>16376-√  \n\\#LP:From dsolidcylinder whose height is 2.4 cm and diameter 1.4 cm,a conical cavity ofthe same heignt and same diameter is hollowed out Find the total surface area of theremaining solid to the nearest cm²TS d -e-ony sil↓ha镇Gecertbush:2cm十(SA(on πxh+πx²+工)今π |2h+8+Q=0·1m嗡ey)+店)子  \n产~…  \nW9·七l\u003CS)  \n Q1   \nW)(st+七0-8k)e  \n→Cavi\\#LP:A hemisphericakdepression is cut out form one face of the cubical wooden block suchthat the diameter of the hemisphere is equal to the edge of the cube.Determine thesurface area of the remaining solid.d=a7SA  dshckm*0)+cst(Ga²一πx)+2π²6²+nx²6o^2π(y6a²+πa²=  \nS1.unit  \n\\#LP:A wooden article was made by scooping out a hemisphere from each end of a solidcylinder.If the height of the cylinder is 10 cm,and its base is of radius 3.5 cm.find the totalsurface area of the article.TSAd roung,sdSAeln+Q《sthuwlr一 nxh十xTCn+22100QX13c23  \n\\#LP:A cuboidal solid metallic block is of dimension 15 cm×10cmx5cm,acylindrical holeof diameter 7cm is drilled out.Find the surface area of the remaining block.(Use pi=22/7)TSA千remaining solid-stcooil-tide+Ctola(2or1hc-a2)+8oh1(o0580一鸿汽能之583cm^2  \n\\#LP:A pen stand made of wood is in the shape of a cuboid with four conical depressions tohold pens.The dimensions of the cuboid are 15cm by 10 cm by 3.5cm.The radius of eachof the depressions is 0:5cm and the depth is(1.4 cm Find the volume of wood in the entirestand.  \nWolumet stand→Je(vbnQ-9≥(xbxh)一(4×,(151D5-16101m","cbCaiiK8cAiuMBj5","https://ap.wps.com/l/cbCaiiK8cAiuMBj5","pdf",5924740,"English","# SURFACE AREA\n## Problems on cubes joined to form cuboids\n## Cube and hemisphere block surface area\n## Cylinder with conical cavity\n## Hemispheric depression in a cube\n## Hemispheres scooped from cylinder ends","[{\"question\":\"How do you find the surface area when two cubes are joined end to end?\",\"answer\":\"Form the resulting cuboid by combining the lengths of the joined faces, then apply the cuboid surface area formula using the new dimensions.\"},{\"question\":\"What information is needed to compute the total surface area of a cube-plus-hemisphere decorative block?\",\"answer\":\"Use the cube edge length and the hemisphere diameter, then add the exposed cube area and the hemisphere curved surface area, taking pi as 22/7 as instructed.\"},{\"question\":\"How is the surface area of the remaining solid handled when a conical cavity is hollowed out?\",\"answer\":\"Calculate the original solid’s total surface area, subtract the areas removed by the conical cavity (including the cavity’s curved surface), and report the result to the nearest cm².\"}]","Surface Areas - Lecture 4 | PDF",28]