[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"doc-seo-522556-105":3,"detail-sidebar-cat-0-en-105":81,"doc-detail-522556-en":130},{"code":4,"msg":5,"data":6},0,"ok",{"site_id":7,"language":8,"slug":9,"title":10,"keywords":11,"description":12,"schema_data":13,"social_meta":74,"head_meta":76,"extra_data":78,"updated_unix":80},105,"en","solving-systems-of-equations-by-substitution","Solving Systems of Equations by Substitution","","Worksheet focused on solving systems of linear equations using the substitution method. Each problem provides two linear equations with variables x and y and asks for the solution pair. The set includes multiple distinct systems ranging from simple one-to-one substitutions to more complex expressions. 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\nSolve each system by substitution.  \n1) y = 6x − 11 2) 2x − 3 y = −1  \n−2x − 3 y = −7 y = x − 1  \n3) y = −3x + 5 4) −3x − 3 y = 3  \n5x − 4 y = −3 y = −5x − 17  \n5) y = −2 6) y = 5x − 7  \n4x − 3 y = 18 −3x − 2 y = −12  \n7) −4x + y = 6 8) −7x − 2 y = −13  \n−5x − y = 21 x − 2 y = 11  \n9) −5x + y = −2 10) −5x + y = −3  \n−3x + 6y = −12 3x − 8 y = 24  \n11) x + 3y = 1 12) −3x − 8 y = 20  \n−3x − 3 y = −15 −5x + y = 19  \n13) −3x + 3y = 4 14) −3x + 3y = 3  \n− x + y = 3 −5x + y = 13  \n15) 6x + 6y = −6 16) 2x + y = 20  \n5x + y = −13 6x − 5 y = 12  \n17) −3x − 4 y = 2 18) −2x + 6y = 6  \n3x + 3y = −3 −7x + 8y = −5  \n19) −5x − 8 y = 17 20) −2x − y = −9  \n2x − 7 y = −17 5x − 2 y = 18  \nKuta Software-Infinite Algebra 1 Name   \nSolving Systems of Equations by Substitution Date  Period   \nSolve each system by substitution.  \n1) y = 6x − 11 2) 2x − 3 y = −1  \n−2x − 3 y = −7 y = x − 1  \n(2, 1) (4, 3)  \n3) y = −3x + 5 4) −3x − 3 y = 3  \n5x − 4 y = −3 y = −5x − 17  \n( 1, 2) (−4, 3)  \n5) y = −2 6) y = 5x − 7  \n4x − 3 y = 18 −3x − 2 y = −12  \n(3, −2) (2, 3)  \n7) −4x + y = 6 8) −7x − 2 y = −13  \n−5x − y = 21 x − 2 y = 11  \n(−3, −6) (3, −4)  \n9) −5x + y = −2 10) −5x + y = −3  \n−3x + 6y = −12 3x − 8 y = 24  \n(0, −2) (0, −3)  \n11) x + 3y = 1 12) −3x − 8 y = 20  \n−3x − 3 y = −15 −5x + y = 19  \n(7, −2) (−4, −1)  \n13) −3x + 3y = 4 14) −3x + 3y = 3  \n− x + y = 3 −5x + y = 13  \nNo solution (−3, −2)  \n15) 6x + 6y = −6 16) 2x + y = 20  \n5x + y = −13 6x − 5 y = 12  \n(−3, 2) (7, 6)  \n17) −3x − 4 y = 2 18) −2x + 6y = 6  \n3x + 3y = −3 −7x + 8y = −5  \n(−2, 1) (3, 2)  \n19) −5x − 8 y = 17 20) −2x − y = −9  \n2x − 7 y = −17 5x − 2 y = 18  \n(−5, 1) (4, 1)  \nCreate your own worksheets like this one with Infinite Algebra 1. Free trial available [at KutaSoftware.com](at KutaSoftware.com)","cbCaioelpxStx8cz","https://ap.wps.com/l/cbCaioelpxStx8cz","pdf",30570,"English","# Solve each system by substitution","[{\"question\":\"What method is used to solve the systems in this worksheet?\",\"answer\":\"The worksheet instructs solving each system by substitution.\"},{\"question\":\"What information is given for each problem?\",\"answer\":\"Each problem provides two linear equations involving x and y.\"},{\"question\":\"How do you determine the answer for a system in substitution?\",\"answer\":\"Substitute one expression into the other equation, then solve for the remaining variable and derive the coordinate pair.\"}]","Solving Systems of Equations by Substitution | PDF",1791425912]