[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"doc-seo-144207-105":3,"detail-sidebar-cat-0-en-105":85,"doc-detail-144207-en":135},{"code":4,"msg":5,"data":6},0,"ok",{"site_id":7,"language":8,"slug":9,"title":10,"keywords":11,"description":12,"schema_data":13,"social_meta":78,"head_meta":80,"extra_data":82,"updated_unix":84},105,"en","physics-scholarship-answers-2022-iut-admission-testsocie-physics-questions","Physics Scholarship Answers - 2022 IUT Admission Test(SOCIE) Physics Questions","","2022 IUT Admission Test (SOCIE) physics answers covering multiple-choice solution steps across key mechanics and electromagnetism topics. Includes problems on equivalent resistance for series-parallel circuits, wavelength–frequency relation for light, kinetic friction using normal force and net force conditions, conservation of mechanical energy for projectile motion or height-to-speed conversion, vector addition of electric forces between charges, and charge sharing when connecting two capacitors of different capacitance. Each item provides a computed final numerical result.",{"@graph":14,"@context":77},[15,34,56],{"@type":16,"itemListElement":17},"BreadcrumbList",[18,23,27,31],{"item":19,"name":20,"@type":21,"position":22},"https://docshare.wps.com","Home","ListItem",1,{"item":24,"name":25,"@type":21,"position":26},"https://docshare.wps.com/document/","Document",2,{"item":28,"name":29,"@type":21,"position":30},"https://docshare.wps.com/document/exam/","Exam",3,{"item":32,"name":10,"@type":21,"position":33},"https://docshare.wps.com/document/physics-scholarship-answers-2022-iut-admission-testsocie-physics-questions/144207/",4,{"url":32,"name":10,"@type":35,"image":36,"author":41,"headline":10,"publisher":44,"fileFormat":47,"inLanguage":8,"description":12,"dateModified":48,"datePublished":49,"encodingFormat":47,"isAccessibleForFree":50,"interactionStatistic":51},"DigitalDocument",{"url":37,"@type":38,"width":39,"height":40},"https://docshare.wps.com/thumbnails/physics-scholarship-answers-2022-iut-admission-testsocie-physics-questions/144207.png","ImageObject",300,407,{"name":42,"@type":43},"Theodora","Person",{"url":19,"name":45,"@type":46},"DocShare","Organization","application/pdf","2026-10-25","2026-08-25",true,{"@type":52,"interactionType":53,"userInteractionCount":55},"InteractionCounter",{"@type":54},"ViewAction",12,{"@type":57,"mainEntity":58},"FAQPage",[59,65,69,73],{"name":60,"@type":61,"acceptedAnswer":62},"How are equivalent resistances for a series-parallel connection obtained in the solutions?","Question",{"text":63,"@type":64},"The solutions treat the parallel part first to find its equivalent resistance, then add it in series with the remaining resistor(s). The final equivalent resistance is computed using the numeric values given in the problem.","Answer",{"name":66,"@type":61,"acceptedAnswer":67},"What relation links wavelength and frequency of light in the answers?",{"text":68,"@type":64},"The answers use the wave relation involving the speed of electromagnetic waves c, expressing how wavelength and frequency correspond. The wavelength is then calculated from the given frequency using that formula.",{"name":70,"@type":61,"acceptedAnswer":71},"How is the coefficient of kinetic friction found from forces?",{"text":72,"@type":64},"The solutions set the vertical net force to zero to get the normal force N, then use the horizontal net force condition with kinetic friction proportional to μkN. Substituting the provided values yields the numeric μk.",{"name":74,"@type":61,"acceptedAnswer":75},"How are charges and equivalent results determined when two capacitors are connected?",{"text":76,"@type":64},"The solutions compute the initial charge on the first capacitor, then use capacitor connection conditions so the final electric potentials become equal. Charge conservation across both capacitors is applied to find the final charges and the required numeric result.","https://schema.org",{"og:url":32,"og:type":79,"og:title":10,"og:site_name":45,"og:description":12},"article",{"robots":81,"canonical":32},"index,follow",{"doc_id":83,"site_id":7},144207,1787698708,{"code":4,"msg":86,"data":87},"success",[88,92,96,99,104,109,114,119,124,127,131],{"id":22,"doc_module":4,"doc_module_name":25,"category_name":89,"show_sort_weight":90,"slug":91},"Story & Novel",90,"story-novel",{"id":26,"doc_module":4,"doc_module_name":25,"category_name":93,"show_sort_weight":94,"slug":95},"Literature",80,"literature",{"id":33,"doc_module":4,"doc_module_name":25,"category_name":29,"show_sort_weight":97,"slug":98},70,"exam",{"id":100,"doc_module":4,"doc_module_name":25,"category_name":101,"show_sort_weight":102,"slug":103},5,"Comic",60,"comic",{"id":105,"doc_module":4,"doc_module_name":25,"category_name":106,"show_sort_weight":107,"slug":108},6,"Technology",50,"technology",{"id":110,"doc_module":4,"doc_module_name":25,"category_name":111,"show_sort_weight":112,"slug":113},7,"Healthcare",40,"healthcare",{"id":115,"doc_module":4,"doc_module_name":25,"category_name":116,"show_sort_weight":117,"slug":118},8,"Research & Report",30,"research-report",{"id":120,"doc_module":4,"doc_module_name":25,"category_name":121,"show_sort_weight":122,"slug":123},9,"Religion & Spirituality",20,"religion-spirituality",{"id":122,"doc_module":4,"doc_module_name":25,"category_name":125,"show_sort_weight":122,"slug":126},"World Cup","world-cup",{"id":128,"doc_module":4,"doc_module_name":25,"category_name":129,"show_sort_weight":128,"slug":130},10,"Lifestyle","lifestyle",{"id":132,"doc_module":4,"doc_module_name":25,"category_name":133,"show_sort_weight":100,"slug":134},19,"General","general",{"code":4,"msg":86,"data":136},{"doc_id":83,"user_id":137,"nickname":42,"user_avatar":138,"doc_module":4,"category_id":33,"category_name":29,"doc_title":10,"doc_description":12,"doc_content":139,"file_id":140,"file_url":141,"file_type":142,"file_size":143,"view_count":55,"is_deleted":4,"is_public":22,"is_downloadable":22,"audit_status":22,"page_count":26,"language":144,"language_code":8,"site_id":7,"html_lang":8,"table_of_contents":145,"faqs":146,"seo_title":147,"seo_description":12,"update_tm":84,"read_time":100},687197207919,"https://ap-avatar.wpscdn.com/avatar/a000253d6f5f7c60be?x-image-process=image/resize,m_fixed,w_180,h_180&k=1779446848396160552","2022 IUT Admission Test(SOCIE)  \n\u003CMultiple choice Types> There is only one correct answer per each question. Mark your answer choice on the OMR answer sheet.  \nFor each correct answer, you will get the points indicated next to each question number.  \nNo penalty point is applied to an incorrect answer.  \n, 4. , 5.  \n1. [1 point]  \nSince 􀈖􀈺 and 􀈖􀈻 are connected in parallel, the equivalent resistance of this parallel connection can be  \n􀈹 􀈹 􀈹 􀈹 􀈹 􀈺 found: 􀉮 􀉋 􀉮􀉌 􀉮 􀉋 􀉮 􀉌 􀉮 􀉋 􀉮  \n􀈖􀋮 􀈖􀈺 􀈖􀈻 􀈹 Ω 􀈹 Ω 􀈹 Ω . therefore 􀈖􀋮 􀉋 􀉁 􀉕 􀈼 Ω .  \nNow 􀈖􀈹 and 􀈖􀋮 are connected in series, the equivalent resistance of this series connection is 􀈖􀋤􀋯 􀉋 􀈖􀈹 􀉌 􀈖􀋮 􀉋 􀈺 Ω 􀉌 􀉁 􀉕 􀈼 Ω 􀉋 􀈺 􀉕 􀈼 Ω  \nAnswer) 2.5 Ω  \n2. [1 point]  \nThe wavelength (l) and the frequency (f) of light is related as 􀆠 􀇣 􀅀 􀇠 , where c is the speed of electromagnetic waves. Therefore, the wavelength is  \n􀇠 􀄽􀄯 􀄶 × 􀄭􀄶􀄴 m 􀅍 s 􀄾  \n􀆠 􀅀  􀅀 􀅌 􀅌 􀄶 × 􀄭􀄶􀄵 H z 􀄾 􀅀 􀄶 􀅌 􀄭􀄱 m  \nAnswer) 0.15 m  \n3. [2 points]  \nThe net force in the horizontal direction is  \n􀃾 ≠ 􀇱 􀅀 􀃾 􀄿 􀆡􀇨 􀄆 􀅀 􀇪􀇞 􀅀 􀄮 kg × 􀄯 m 􀅍 s􀄮 􀅀 􀄲 N , where 􀆡􀇨 is the coefficient of kinetic friction and Nis the normal force. Since the net force in the vertical direction is zero, N = mg = 20 N.  \nTherefore, the coefficient of kinetic friction is  \n􀄭􀄶 N 􀄿 􀄲 N  \n􀆡􀇨 􀅀  􀅀 􀄶 􀅌 􀄮  \nAnswer) 0.2  \n4. [2 point]  \nAccording to the conservation of mechanical energy, the potential energy at the top ( 􀋫􀋦􀌑) should be same  \n􀈹  \nas the kinetic energy at the bottom ( 􀉮 􀋫􀋴􀈺 ). That is,  \n􀈺  \n􀋫􀋦􀌑 =  􀋫􀋴􀈺 .  \nTherefore 􀋴 􀉋 􀉞 􀉋 􀉞􀈺 × 􀈼 m 􀉋 􀈹􀉁 m􀉖s Answer) 10 m/s  \nSOCIE- 1 / 3  \n5. [3 point]  \nThe electric force between two charges with charges  \n􀄭 􀇮􀄮  \n+q is 􀄶 􀄮 . The angle between two forces arising from other two charges is 􀈽􀉁 􀋈 . Therefore the vector sum of the two forces with the same magnitude of  \n􀄭 􀇮􀄮 􀅕 􀇮􀄮􀅦 􀅦 is 􀅦 􀅦􀄰􀆥􀆚 􀄶 􀇩 􀄮 􀄰􀆥􀆚 􀄶 􀇩􀄮 .  \n􀅕 􀇮􀄮 Answer) 􀅦 􀅦  \n􀄰􀆥􀆚 􀄶 􀇩 􀄮  \n6. [3 point]  \nThe original amount of charge accumulated in the first capacitor is 􀄉􀄶 􀅀 􀃻􀄎 􀅀 􀄯 × 􀄭􀄶􀄿 􀄲 F × 􀄭􀄮 V 􀅀 􀄯􀄲 􀆡C. When the first capacitor (􀈇􀈹 􀉋 3 􀆡F ) is connected to the second capacitor (􀈇􀈺 􀉋 6 􀆡F ), the charge flows out of the first capacitor untill the electric potential of the two capacitors become equivalent.  \n􀈕 􀈕  \nSince 􀄎 􀅀 􀄉􀅍􀃻 , 􀈹􀈹 􀉋 􀈺􀈺 . Therefore 􀈕􀈺 􀉋 􀈺􀈕􀈹 . And due to the charge conservation law, sum of the charges in two capacitors should be same as the original charge: 􀈕 􀈹 􀉌 􀈕􀈺 􀉋 􀈕􀉁 . Therefore,  \n􀈕􀈹 􀉌 􀈕􀈺 􀉋 􀈕􀈹 􀉌 􀈺􀈕􀈹 􀉋 􀈻􀈕􀈹 􀉋 􀈕􀉁 􀉋 􀈻􀈽 􀊨F . Thus we find 􀈕􀈹 􀉋 􀈹􀈺 􀊨F.  \nAnswer) 12 􀆡C","cbCaiaiXpQjGEyx9","https://ap.wps.com/l/cbCaiaiXpQjGEyx9","pdf",95013,"English","# Multiple choice answers\n## Electric circuits and resistance\n## Optics and wave relation\n## Mechanics: friction and energy\n## Electrostatics: charges and capacitors","[{\"question\":\"How are equivalent resistances for a series-parallel connection obtained in the solutions?\",\"answer\":\"The solutions treat the parallel part first to find its equivalent resistance, then add it in series with the remaining resistor(s). The final equivalent resistance is computed using the numeric values given in the problem.\"},{\"question\":\"What relation links wavelength and frequency of light in the answers?\",\"answer\":\"The answers use the wave relation involving the speed of electromagnetic waves c, expressing how wavelength and frequency correspond. The wavelength is then calculated from the given frequency using that formula.\"},{\"question\":\"How is the coefficient of kinetic friction found from forces?\",\"answer\":\"The solutions set the vertical net force to zero to get the normal force N, then use the horizontal net force condition with kinetic friction proportional to μkN. Substituting the provided values yields the numeric μk.\"},{\"question\":\"How are charges and equivalent results determined when two capacitors are connected?\",\"answer\":\"The solutions compute the initial charge on the first capacitor, then use capacitor connection conditions so the final electric potentials become equal. Charge conservation across both capacitors is applied to find the final charges and the required numeric result.\"}]","Physics Scholarship Answers - 2022 IUT Admission Test(SOCIE) Physics Questions | PDF"]