[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"doc-detail-208000-en":3,"doc-seo-208000-105":30,"detail-sidebar-cat-0-en-105":89},{"code":4,"msg":5,"data":6},0,"success",{"doc_id":7,"user_id":8,"nickname":9,"user_avatar":10,"doc_module":4,"category_id":11,"category_name":12,"doc_title":13,"doc_description":14,"doc_content":15,"file_id":16,"file_url":17,"file_type":18,"file_size":19,"view_count":4,"is_deleted":4,"is_public":20,"is_downloadable":20,"audit_status":20,"page_count":21,"language":22,"language_code":23,"site_id":24,"html_lang":23,"table_of_contents":25,"faqs":26,"seo_title":27,"seo_description":14,"update_tm":28,"read_time":29},208000,2336475401981,"Chumphorn","https://ap-avatar.wpscdn.com/avatar/22000c94efd8d5204d?x-image-process=image/resize,m_fixed,w_180,h_180&k=1786935347598174694",4,"Exam","Periodic Table Mark Scheme - Question 1-2","Answer mark scheme for a periodic table assessment covering Q1 and Q2. Includes electron structure and bonding interpretations for argon, oxidation and group-based reasoning for PH3 and tellurium, and application of metal/non-metal trends. Provides guided marking points for reactions (effervescence, barium with HCl, rubidium behavior with water) and equation-based credit rules. Also includes justification for electron loss energy and calculations for relative atomic mass, with rounding expectations.","Mark schemes  \nQ1 .  \n(a) (atoms of) argon have a stable arrangement of electrons allow (atoms of) argon have a full outer shell (of electrons)  \n1  \n(so) argon (atoms) do not share / transfer electrons  \n1  \n(b) PH3  \nallow H3P  \n1  \n(c) yes, because tellurium is towards the right of the periodic table  \nallow yes, because tellurium is in Group 6  \n1  \n(so) tellurium is a non-metal  \nallow (so) tellurium will gain electrons (from a  \nmetal)  \n1  \nMP2 is dependent upon MP1 being awarded  \nOR  \nyes, because tellurium is in the same group as oxygen / sulfur (1)  \n(and) oxygen / sulfur will react with metals (1)  \nallow (so) tellurium is a non-metal  \nallow (so) tellurium will gain electrons (from a  \nmetal)  \nOR  \nno, because tellurium is towards the bottom of the periodic table (1)  \n(so) tellurium is a metal (1)  \nallow (so) difficult for tellurium to gain electrons  \n(from a metal) (1)  \nOR  \ncannot predict as tellurium is towards the bottom and to the right of  \nthe periodic table (1)  \n(so) don't know whether tellurium is a metal or non-metal (1) allow (so) don't know whether tellurium will gain electrons  \n(d) any two from:  \n• effervescence / fizzing / bubbles  \nignore produces a gas  \n• barium disappears  \nallow barium gets smaller  \n• forms a colourless solution  \n• temperature increases  \nallow barium moves around  \n2  \nignore references to floating / flames  \n(e) Ba + 2 HCl ĺ BaCl2 + H2  \nallow multiples  \n3  \nallow 1 mark for BaCl2  \nallow 1 mark for H2  \nignore state symbols  \n[10]  \nQ2 .  \n(a) any one from:  \n• more vigorous bubbling (for rubidium)  \n• bigger / brighter flame (for rubidium)  \nallow converse statements for potassium  \nallow (rubidium) catches fire more quickly  \nallow (rubidium) moves around more quickly  \nallow (rubidium) explodes  \nallow (rubidium) disappears more quickly  \nallow (rubidium) melts more quickly  \n1  \n(b) (rubidium’s) outer shell / electron is further from the nucleus  \nallow the (rubidium) atom is larger  \nallow (rubidium) has more shells  \n1  \n(so) there is less (electrostatic) attraction between the nucleus and the  \nouter electron (in rubidium)  \nallow (so) there is more shielding between the outer electron  \nand the nucleus (in rubidium)  \n1  \n(so) the outer electron (in rubidium) is more easily lost  \nallow (so) less energy is needed to remove the (outer)  \nelectron (in rubidium)  \n1  \nallow energy level for shell throughout  \nallow converse argument in terms of potassium  \n(c) 2 Rb + 2 H2O ĺ 2 RbOH + H2  \nignore state symbols  \nallow multiples  \nallow 1 mark for H2  \nallow 1 mark for RbOH  \n3  \n(d) the noble gases have boiling points that increase going down the group  \n1  \n(e) (relative atomic mass =)   \nallow (relative atomic mass =)   \nallow (relative atomic mass =) 18.096 + 0.0567 + 2.035  \n1  \n= 20.1877  \n1  \n= 20.2  \nallow an answer correctly rounded to 3 significant figures  \nfrom an incorrect calculation which uses all of the values in  \nthe table  \nignore units  \n1  \n[11]","cbCaihvA9Ol68BNC","https://ap.wps.com/l/cbCaihvA9Ol68BNC","pdf",951128,1,3,"English","en",105,"# Q1\n## (a)\n## (b)\n## (c)\n## (d)\n## (e)\n# Q2\n## (a)\n## (b)\n## (c)\n## (d)\n## (e)","[{\"question\":\"How is the marking for Q1(a) about argon’s electrons typically awarded?\",\"answer\":\"Marks are for stating argon has a stable arrangement and a full outer shell, so it does not share or transfer electrons.\"},{\"question\":\"What reasoning supports whether tellurium is a metal or non-metal in Q1(c)?\",\"answer\":\"Marks allow answers based on tellurium’s position, such as being right/left or group relationships with elements like oxygen/sulfur, leading to conclusions about metal versus non-metal behavior.\"},{\"question\":\"How is Q2(e) relative atomic mass calculated and rounded?\",\"answer\":\"Marks allow use of permitted values and the final result, with credit for correctly rounding to 3 significant figures and ignoring incorrect-unit or minor calculation presentation issues.\"}]","Periodic Table Mark Scheme - 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