[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"doc-seo-637505-105":3,"detail-sidebar-cat-0-en-105":81,"doc-detail-637505-en":130},{"code":4,"msg":5,"data":6},0,"ok",{"site_id":7,"language":8,"slug":9,"title":10,"keywords":11,"description":12,"schema_data":13,"social_meta":74,"head_meta":76,"extra_data":78,"updated_unix":80},105,"en","perimeter-of-a-semi-circle-problems-2a","Perimeter of a Semi-Circle Problems - 2A","","This educational document provides a comprehensive set of practice problems focused on calculating the perimeter of semi-circular shapes and complex geometric figures incorporating semi-circles. It includes detailed exercises, such as finding the perimeter of a semicircular window, an archway composed of straight sections and a semi-circle, and a running track design. Each problem is accompanied by step-by-step solutions, explaining the methodology for calculating arc lengths and adding relevant straight dimensions to reach the final perimeter. This resource is designed to help students master geometric measurement techniques.",{"@graph":14,"@context":73},[15,34,56],{"@type":16,"itemListElement":17},"BreadcrumbList",[18,23,27,31],{"item":19,"name":20,"@type":21,"position":22},"https://docshare.wps.com","Home","ListItem",1,{"item":24,"name":25,"@type":21,"position":26},"https://docshare.wps.com/document/","Document",2,{"item":28,"name":29,"@type":21,"position":30},"https://docshare.wps.com/document/exam/","Exam",3,{"item":32,"name":10,"@type":21,"position":33},"https://docshare.wps.com/document/perimeter-of-a-semi-circle-problems-2a/637505/",4,{"url":32,"name":10,"@type":35,"image":36,"author":41,"headline":10,"publisher":44,"fileFormat":47,"inLanguage":8,"description":12,"dateModified":48,"datePublished":49,"encodingFormat":47,"isAccessibleForFree":50,"interactionStatistic":51},"DigitalDocument",{"url":37,"@type":38,"width":39,"height":40},"https://docshare.wps.com/thumbnails/perimeter-of-a-semi-circle-problems-2a/637505.png","ImageObject",300,407,{"name":42,"@type":43},"awa","Person",{"url":19,"name":45,"@type":46},"DocShare","Organization","application/pdf","2026-10-30","2026-10-22",true,{"@type":52,"interactionType":53,"userInteractionCount":55},"InteractionCounter",{"@type":54},"ViewAction",5,{"@type":57,"mainEntity":58},"FAQPage",[59,65,69],{"name":60,"@type":61,"acceptedAnswer":62},"How do you calculate the perimeter of a semicircular window with a radius of 14 inches?","Question",{"text":63,"@type":64},"To find the perimeter, you calculate the length of the curved section using half the circumference formula (π × radius) and add the length of the diameter (2 × radius). For a 14-inch radius, this results in π × 14 + 28, which rounds to 72 inches.","Answer",{"name":66,"@type":61,"acceptedAnswer":67},"What is the approach for determining the perimeter of an arch made of two straight sections and a semi-circle?",{"text":68,"@type":64},"The total perimeter is found by summing the lengths of the two straight sections and the arc length of the semi-circle. In this case, you calculate the arc using the radius (half the width of the arch) and add the lengths of the two vertical sides.",{"name":70,"@type":61,"acceptedAnswer":71},"How is the total perimeter of a running track with two semi-circular ends and a rectangular center calculated?",{"text":72,"@type":64},"The two semi-circular ends are combined to form one complete circle, and their perimeter is added to the lengths of the two straight rectangular sides. The total perimeter is the sum of the circle's circumference and the two parallel straight sections.","https://schema.org",{"og:url":32,"og:type":75,"og:title":10,"og:site_name":45,"og:description":12},"article",{"robots":77,"canonical":32},"index,follow",{"doc_id":79,"site_id":7},637505,1792994712,{"code":4,"msg":82,"data":83},"success",[84,88,92,95,99,104,109,114,119,122,126],{"id":22,"doc_module":4,"doc_module_name":25,"category_name":85,"show_sort_weight":86,"slug":87},"Story & Novel",90,"story-novel",{"id":26,"doc_module":4,"doc_module_name":25,"category_name":89,"show_sort_weight":90,"slug":91},"Literature",80,"literature",{"id":33,"doc_module":4,"doc_module_name":25,"category_name":29,"show_sort_weight":93,"slug":94},70,"exam",{"id":55,"doc_module":4,"doc_module_name":25,"category_name":96,"show_sort_weight":97,"slug":98},"Comic",60,"comic",{"id":100,"doc_module":4,"doc_module_name":25,"category_name":101,"show_sort_weight":102,"slug":103},6,"Technology",50,"technology",{"id":105,"doc_module":4,"doc_module_name":25,"category_name":106,"show_sort_weight":107,"slug":108},7,"Healthcare",40,"healthcare",{"id":110,"doc_module":4,"doc_module_name":25,"category_name":111,"show_sort_weight":112,"slug":113},8,"Research & Report",30,"research-report",{"id":115,"doc_module":4,"doc_module_name":25,"category_name":116,"show_sort_weight":117,"slug":118},9,"Religion & Spirituality",20,"religion-spirituality",{"id":117,"doc_module":4,"doc_module_name":25,"category_name":120,"show_sort_weight":117,"slug":121},"World Cup","world-cup",{"id":123,"doc_module":4,"doc_module_name":25,"category_name":124,"show_sort_weight":123,"slug":125},10,"Lifestyle","lifestyle",{"id":127,"doc_module":4,"doc_module_name":25,"category_name":128,"show_sort_weight":55,"slug":129},19,"General","general",{"code":4,"msg":82,"data":131},{"doc_id":79,"user_id":132,"nickname":42,"user_avatar":133,"doc_module":4,"category_id":33,"category_name":29,"doc_title":10,"doc_description":12,"doc_content":134,"file_id":135,"file_url":136,"file_type":137,"file_size":138,"view_count":55,"is_deleted":4,"is_public":22,"is_downloadable":22,"audit_status":22,"page_count":26,"language":139,"language_code":8,"site_id":7,"html_lang":8,"table_of_contents":140,"faqs":141,"seo_title":142,"seo_description":12,"update_tm":143,"read_time":55},3985747858093,"https://ap-avatar.wpscdn.com/davatar_3d24733baf745e90a7e4bdd5f77d97b2","Name Date  \nPERIMETER OF A SEMI-CIRCLE PROBLEMS 2A  \nWorking out  \n1) A semicircular window has a radius of 14 inches.  \nWhat is the perimeter of the window?  \nGive your answer to the nearest inch.  \n14 in. Perimeter of the window is    \n2)  \nThe arch below is made of two straight sections and a semi-circle. Work out the perimeter of the arch.  \nGive your answer to 1 decimal place.  \n12 ft  \n15 ft  \nPerimeter of the arch is    \n3) A running track is made up of 2 semi-circles at either end and a rectangle in the middle (see diagram below) . What is the perimeter of the track to the nearest yard?  \nPerimeter of the track is    \nName Date  \nPERIMETER OF A SEMI-CIRCLE PROBLEMS 2A ANSWERS  \nWorking out  \n1) A semicircular window has a radius of 14 inches.  \nWhat is the perimeter of the window?  \nGive your answer to the nearest inch.  \n14 in. Perimeter of the mirror is 72 inches.  \nDiameter = 14 x 2 = 28 Perimeter = curved section + diameter.= π x 14 + 28 in  \n= 72 in  \n2)  \nThe arch below is made of two straight sections and a semi-circle. Work out the perimeter of the arch.  \nGive your answer to 1 decimal place.  \n12 ft  \n15 ft  \nRadius of arch = 15 ÷ 2 = 7.5 ft.  \nPerimeter = perimeter of semi-circle + two straight sections  \n= π x 7.5 + 2 x 12  \nThe perimeter of the arch is    \n3) A running track is made up of 2 semi-circles at either end Perimeter = perimeter of and a rectangle in the middle (see diagram below) . two semi-circles + What is the perimeter of the track to the nearest yard? perimeter of the sides.  \nThe two semi-circles add  \n~~ 150 yd ~~ up to make one whole  \ncircle.  \nPerimeter of circle = π x  \n40 yd 40 = 125.7 yd  \nPerimeter of straight parts = 2 x 150 = 300 yd.  \nTotal perimeter = 125.7 +  \n300 = 425.7 yd  \nPerimeter of the track is 425.7 yd","cbCaipoNGecmLfbW","https://ap.wps.com/l/cbCaipoNGecmLfbW","pdf",157063,"English","# Perimeter of a Semi-Circle Problems 2A\n## Problem Descriptions\n## Answer Key and Step-by-Step Solutions","[{\"question\":\"How do you calculate the perimeter of a semicircular window with a radius of 14 inches?\",\"answer\":\"To find the perimeter, you calculate the length of the curved section using half the circumference formula (π × radius) and add the length of the diameter (2 × radius). For a 14-inch radius, this results in π × 14 + 28, which rounds to 72 inches.\"},{\"question\":\"What is the approach for determining the perimeter of an arch made of two straight sections and a semi-circle?\",\"answer\":\"The total perimeter is found by summing the lengths of the two straight sections and the arc length of the semi-circle. In this case, you calculate the arc using the radius (half the width of the arch) and add the lengths of the two vertical sides.\"},{\"question\":\"How is the total perimeter of a running track with two semi-circular ends and a rectangular center calculated?\",\"answer\":\"The two semi-circular ends are combined to form one complete circle, and their perimeter is added to the lengths of the two straight rectangular sides. The total perimeter is the sum of the circle's circumference and the two parallel straight sections.\"}]","Perimeter of a Semi-Circle Problems - 2A | PDF",1792680694]