[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"doc-seo-522503-105":3,"doc-detail-522503-en":81,"detail-sidebar-cat-0-en-105":97},{"code":4,"msg":5,"data":6},0,"ok",{"site_id":7,"language":8,"slug":9,"title":10,"keywords":11,"description":12,"schema_data":13,"social_meta":74,"head_meta":76,"extra_data":78,"updated_unix":80},105,"en","mixture-word-problems","Mixture Word Problems","","A set of algebra practice problems on mixture word problems, focusing on percent composition and concentration after combining different quantities. The worksheet includes scenarios with soil sand content, alcohol solution strengths, fruit juice percentages from two brands, peanut mixtures, spice/cinnamon cost per pound, alloy nickel percentages, acid and sugar solution concentrations, and combining metals to reach a target gold content. It also covers product formulation for mixed nuts by calculating required amounts from brands with different peanut percentages.",{"@graph":14,"@context":73},[15,34,56],{"@type":16,"itemListElement":17},"BreadcrumbList",[18,23,27,31],{"item":19,"name":20,"@type":21,"position":22},"https://docshare.wps.com","Home","ListItem",1,{"item":24,"name":25,"@type":21,"position":26},"https://docshare.wps.com/document/","Document",2,{"item":28,"name":29,"@type":21,"position":30},"https://docshare.wps.com/document/exam/","Exam",3,{"item":32,"name":10,"@type":21,"position":33},"https://docshare.wps.com/document/mixture-word-problems/522503/",4,{"url":32,"name":10,"@type":35,"image":36,"author":41,"headline":10,"publisher":44,"fileFormat":47,"inLanguage":8,"description":12,"dateModified":48,"datePublished":49,"encodingFormat":47,"isAccessibleForFree":50,"interactionStatistic":51},"DigitalDocument",{"url":37,"@type":38,"width":39,"height":40},"https://docshare.wps.com/thumbnails/mixture-word-problems/522503.png","ImageObject",300,407,{"name":42,"@type":43},"Hazel","Person",{"url":19,"name":45,"@type":46},"DocShare","Organization","application/pdf","2026-10-25","2026-10-08",true,{"@type":52,"interactionType":53,"userInteractionCount":55},"InteractionCounter",{"@type":54},"ViewAction",8,{"@type":57,"mainEntity":58},"FAQPage",[59,65,69],{"name":60,"@type":61,"acceptedAnswer":62},"How do you find the percent sand content after mixing soils with different sand percentages?","Question",{"text":63,"@type":64},"Use the total amounts and compute the combined sand contribution from each soil portion, then divide by the total mixture volume.","Answer",{"name":66,"@type":61,"acceptedAnswer":67},"How do you determine the concentration of a new alcohol mixture after combining two solutions?",{"text":68,"@type":64},"Convert each solution to its alcohol amount (volume times percent), add them, then divide by the new total volume to get the new percent concentration.",{"name":70,"@type":61,"acceptedAnswer":71},"How do you solve alloy and metal-mixture problems with target gold or nickel percentages?",{"text":72,"@type":64},"Compute the required total percent composition by converting each metal’s percent to its amount, then set up equations (or proportional totals) to match the target percentage.","https://schema.org",{"og:url":32,"og:type":75,"og:title":10,"og:site_name":45,"og:description":12},"article",{"robots":77,"canonical":32},"index,follow",{"doc_id":79,"site_id":7},522503,1791504620,{"code":4,"msg":82,"data":83},"success",{"doc_id":79,"user_id":84,"nickname":42,"user_avatar":85,"doc_module":4,"category_id":33,"category_name":29,"doc_title":10,"doc_description":12,"doc_content":86,"file_id":87,"file_url":88,"file_type":89,"file_size":90,"view_count":55,"is_deleted":4,"is_public":22,"is_downloadable":22,"audit_status":22,"page_count":33,"language":91,"language_code":8,"site_id":7,"html_lang":8,"table_of_contents":92,"faqs":93,"seo_title":94,"seo_description":12,"update_tm":95,"read_time":96,"preview_page_count":4},137441390410,"https://ap-avatar.wpscdn.com/avatar/2000252f4ab5702993?_k=1776741390130283984","Kuta Software-Infinite Algebra 1  \nMixture Word Problems  \n1) 2 m³ of soil containing 35% sand was mixed into 6 m³ of soil containing 15% sand. What is the sand content of the mixture?  \n3) 5 fl. oz. of a 2% alcohol solution was mixed with 11 fl. oz. of a 66% alcohol solution. Find the concentration of the new mixture.  \n5) Emily mixed together 9 gal. of Brand A fruit drink and 8 gal. of Brand B fruit drink which contains 48% fruit juice. Find the percent of fruit juice in Brand A if the mixture contained 30% fruit juice.  \nName  Date  Period   \n2) 9 lbs. of mixed nuts containing 55% peanuts were mixed with 6 lbs. of another kind of mixed nuts that contain 40% peanuts. What percent of the new mixture is peanuts?  \n4) 16 lb of Brand M Cinnamon was made by combining 12 lb of Indonesian cinnamon which costs $19/lb with 4 lb of Thai cinnamon which costs $11/lb. Find the cost per lb of the mixture.  \n6) How many mg of a metal containing 45% nickel must be combined with 6 mg of pure nickel to form an alloy containing 78% nickel?  \n7) 7 L of an acid solution was mixed with 3 L of a 15% acid solution to make a 29% acid solution. Find the percent concentration of the first solution.  \n9) A metallurgist needs to make 12.4 lb. of an alloy containing 50% gold. He is going to melt and combine one metal that is 60% gold with another metal that is 40% gold. How much of each should he use?  \n8) 9 gal. of a sugar solution was mixed with 6 gal. of a 90% sugar solution to make a 84% sugar solution. Find the percent concentration of the first solution.  \n10) Brand X sells 21 oz. bags of mixed nuts that contain 29% peanuts. To make their product they combine Brand A mixed nuts which contain 35% peanuts and Brand B mixed nuts which contain 25% peanuts. How much of each do they need to use?  \nKuta Software-Infinite Algebra 1  \nMixture Word Problems  \n1) 2 m³ of soil containing 35% sand was mixed into 6 m³ of soil containing 15% sand. What is the sand content of the mixture?  \n20%  \n3) 5 fl. oz. of a 2% alcohol solution was mixed with 11 fl. oz. of a 66% alcohol solution. Find the concentration of the new mixture.  \n46%  \n5) Emily mixed together 9 gal. of Brand A fruit drink and 8 gal. of Brand B fruit drink which contains 48% fruit juice. Find the percent of fruit juice in Brand A if the mixture contained 30% fruit juice.  \n14%  \nName  Date  Period   \n2) 9 lbs. of mixed nuts containing 55% peanuts were mixed with 6 lbs. of another kind of mixed nuts that contain 40% peanuts. What percent of the new mixture is peanuts?  \n49%  \n4) 16 lb of Brand M Cinnamon was made by combining 12 lb of Indonesian cinnamon which costs $19/lb with 4 lb of Thai cinnamon which costs $11/lb. Find the cost per lb of the mixture.  \n$17/lb  \n6) How many mg of a metal containing 45% nickel must be combined with 6 mg of pure nickel to form an alloy containing 78% nickel?  \n4 mg  \n7) 7 L of an acid solution was mixed with 3 L of a 15% acid solution to make a 29% acid solution. Find the percent concentration of the first solution.  \n35%  \n9) A metallurgist needs to make 12.4 lb. of an alloy containing 50% gold. He is going to melt and combine one metal that is 60% gold with another metal that is 40% gold. How much of each should he use?  \n6.2 lb. of 60% gold, 6.2 lb. of 40% gold  \n8) 9 gal. of a sugar solution was mixed with 6 gal. of a 90% sugar solution to make a 84% sugar solution. Find the percent concentration of the first solution.  \n80%  \n10) Brand X sells 21 oz. bags of mixed nuts that contain 29% peanuts. To make their product they combine Brand A mixed nuts which contain 35% peanuts and Brand B mixed nuts which contain 25% peanuts. How much of each do they need to use?  \n8.4 oz. of Brand A, 12.6 oz. of Brand B  \nCreate your own worksheets like this one with Infinite Algebra 1. Free trial available [at KutaSoftware.com](at KutaSoftware.com)","cbCaivgOQX7KYhfr","https://ap.wps.com/l/cbCaivgOQX7KYhfr","pdf",27427,"English","# Mixture Word Problems\n## Soil, alcohol, and drink mixtures\n## Nuts, cinnamon, and metal alloys","[{\"question\":\"How do you find the percent sand content after mixing soils with different sand percentages?\",\"answer\":\"Use the total amounts and compute the combined sand contribution from each soil portion, then divide by the total mixture volume.\"},{\"question\":\"How do you determine the concentration of a new alcohol mixture after combining two solutions?\",\"answer\":\"Convert each solution to its alcohol amount (volume times percent), add them, then divide by the new total volume to get the new percent concentration.\"},{\"question\":\"How do you solve alloy and metal-mixture problems with target gold or nickel percentages?\",\"answer\":\"Compute the required total percent composition by converting each metal’s percent to its amount, then set up equations (or proportional totals) to match the target percentage.\"}]","Mixture Word Problems | PDF",1791425854,10,{"code":4,"msg":82,"data":98},[99,103,107,110,115,120,125,129,134,137,140],{"id":22,"doc_module":4,"doc_module_name":25,"category_name":100,"show_sort_weight":101,"slug":102},"Story & Novel",90,"story-novel",{"id":26,"doc_module":4,"doc_module_name":25,"category_name":104,"show_sort_weight":105,"slug":106},"Literature",80,"literature",{"id":33,"doc_module":4,"doc_module_name":25,"category_name":29,"show_sort_weight":108,"slug":109},70,"exam",{"id":111,"doc_module":4,"doc_module_name":25,"category_name":112,"show_sort_weight":113,"slug":114},5,"Comic",60,"comic",{"id":116,"doc_module":4,"doc_module_name":25,"category_name":117,"show_sort_weight":118,"slug":119},6,"Technology",50,"technology",{"id":121,"doc_module":4,"doc_module_name":25,"category_name":122,"show_sort_weight":123,"slug":124},7,"Healthcare",40,"healthcare",{"id":55,"doc_module":4,"doc_module_name":25,"category_name":126,"show_sort_weight":127,"slug":128},"Research & Report",30,"research-report",{"id":130,"doc_module":4,"doc_module_name":25,"category_name":131,"show_sort_weight":132,"slug":133},9,"Religion & Spirituality",20,"religion-spirituality",{"id":132,"doc_module":4,"doc_module_name":25,"category_name":135,"show_sort_weight":132,"slug":136},"World Cup","world-cup",{"id":96,"doc_module":4,"doc_module_name":25,"category_name":138,"show_sort_weight":96,"slug":139},"Lifestyle","lifestyle",{"id":141,"doc_module":4,"doc_module_name":25,"category_name":142,"show_sort_weight":111,"slug":143},19,"General","general"]