[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"doc-seo-553297-105":3,"detail-sidebar-cat-0-en-105":81,"doc-detail-553297-en":130},{"code":4,"msg":5,"data":6},0,"ok",{"site_id":7,"language":8,"slug":9,"title":10,"keywords":11,"description":12,"schema_data":13,"social_meta":74,"head_meta":76,"extra_data":78,"updated_unix":80},105,"en","mixed-operations-word-problems-grade-5-solve-the-word-problems","Mixed Operations Word Problems - Grade 5 - Solve the Word Problems","","Mixed operations word problems for Grade 5 focus on airport scenarios during normal days versus Christmas holidays. Students calculate planes taking off per hour, passengers leaving per hour, and increases in daily passenger counts. Additional problems address late passengers, delays caused by late arrivals, and require forming and solving an equation. A cargo loading question connects morning and afternoon totals to a daily combined weight.",{"@graph":14,"@context":73},[15,34,56],{"@type":16,"itemListElement":17},"BreadcrumbList",[18,23,27,31],{"item":19,"name":20,"@type":21,"position":22},"https://docshare.wps.com","Home","ListItem",1,{"item":24,"name":25,"@type":21,"position":26},"https://docshare.wps.com/document/","Document",2,{"item":28,"name":29,"@type":21,"position":30},"https://docshare.wps.com/document/exam/","Exam",3,{"item":32,"name":10,"@type":21,"position":33},"https://docshare.wps.com/document/mixed-operations-word-problems-grade-5-solve-the-word-problems/553297/",4,{"url":32,"name":10,"@type":35,"image":36,"author":41,"headline":10,"publisher":44,"fileFormat":47,"inLanguage":8,"description":12,"dateModified":48,"datePublished":49,"encodingFormat":47,"isAccessibleForFree":50,"interactionStatistic":51},"DigitalDocument",{"url":37,"@type":38,"width":39,"height":40},"https://docshare.wps.com/thumbnails/mixed-operations-word-problems-grade-5-solve-the-word-problems/553297.png","ImageObject",300,407,{"name":42,"@type":43},"Aran","Person",{"url":19,"name":45,"@type":46},"DocShare","Organization","application/pdf","2026-11-09","2026-10-12",true,{"@type":52,"interactionType":53,"userInteractionCount":55},"InteractionCounter",{"@type":54},"ViewAction",5,{"@type":57,"mainEntity":58},"FAQPage",[59,65,69],{"name":60,"@type":61,"acceptedAnswer":62},"How do you calculate the number of planes taking off per hour during the Christmas holidays?","Question",{"text":63,"@type":64},"Find the total planes per day (336) and divide by the number of hours the airport is open (12). The result is 28 planes per hour.","Answer",{"name":66,"@type":61,"acceptedAnswer":67},"What is the delay in overall airport operation if there are 832 passengers late?",{"text":68,"@type":64},"Use the rule 5 minutes of delay for every 32 late passengers. Compute 832 ÷ 32 × 5 to get 130 minutes.",{"name":70,"@type":61,"acceptedAnswer":71},"How is the equation for the afternoon cargo weight solved?",{"text":72,"@type":64},"Set up the equation using the morning cargo and total cargo: 7,580 + x = 12,997. 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During the Christmas holidays, about 336 planes take off every day from the airport.  \n1. During the Christmas holidays, the airport opens 12 hours during each day, how many planes take off from this airport in each hour?  \n2. In average, each plane takes 240 passengers and 12 tons of cargo. How many passengers depart from the airport every hour during the Christmas holidays?  \n3. Compared with a normal day, how many more passengers depart from the airport in a day during the Christmas holidays?  \n4. During a normal day, there are 782 passengers in average that are late for their plane each day. However, during the Christmas holidays, there are 1,835 passengers that are late for their planes each day which caused delays of 14 planes. How many more passengers are late for their planes in each day during the Christmas holidays?  \n5. The airport administration did a study and found that an additional 5 minutes of delay in the overall operation of the airport is caused for every 32 passengers that are late for their flights. What is the delay in the overall operation if there are 832 passengers late for their flights?  \n6. Write an equation using “􀝔” and then solve the equation.  \nOn the New Year Eve, there were 7,580 tons of cargo loaded in the morning. In the afternoon, there were 􀝔 tons of cargos. The total weight of cargos loaded on the day weighed 12,997 tons.  \nReading and Math for K-5 © [www.k5learning.com](www.k5learning.com)  \nAnswers  \n1. 336 ÷ 12 = 28  \n28 planes take off from this airport each hour during the Christmas holidays.  \n2. 28 x 240 = 6,720  \n6,720 passengers depart from the airport every hour.  \n3. (336 – 280) x 240 = 13,440  \n13,440 more passengers depart from the airport in a day during the Christmas holidays.  \n4. 1,835 – 782 = 1,053 passengers  \n1,053 more passengers are late for their planes in each day during the Christmas holidays.  \n5. 832 ÷ 32 x 5=130  \nThere will be a delay of 130 minutes in the overall operation of the airport.  \n6. 7,580 + 􀝔 = 12,997  \n􀝔 = 5,417  \n.  \nReading and Math for K-5 © [www.k5learning.com](www.k5learning.com)","cbCaisBp9Ryrolf0","https://ap.wps.com/l/cbCaisBp9Ryrolf0","pdf",68263,"English","# Mixed operations word problems - Grade 5\n## Planes and passengers during Christmas holidays\n## Late passengers and operational delays\n## Equation and cargo totals","[{\"question\":\"How do you calculate the number of planes taking off per hour during the Christmas holidays?\",\"answer\":\"Find the total planes per day (336) and divide by the number of hours the airport is open (12). The result is 28 planes per hour.\"},{\"question\":\"What is the delay in overall airport operation if there are 832 passengers late?\",\"answer\":\"Use the rule 5 minutes of delay for every 32 late passengers. Compute 832 ÷ 32 × 5 to get 130 minutes.\"},{\"question\":\"How is the equation for the afternoon cargo weight solved?\",\"answer\":\"Set up the equation using the morning cargo and total cargo: 7,580 + x = 12,997. Solve to get x = 5,417 tons.\"}]","Mixed Operations Word Problems - Grade 5 - Solve the Word Problems | PDF",1791790882]