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Students complete break-apart multiplication expressions to find missing addends and compute the products. Additional sections require finding missing subtracted parts near ten and missing factors in “So, a × ___” statements. A challenge asks students to use distributive reasoning to determine total cookies for treat bags and explain the thinking in one sentence. 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Then find the product. Show neat work.  \nPart A—Missing Addend in a Break-Apart (1–6)  \n1. 26 × 4  \n(20 × 4) + (  × 4) =   +   =   2. 47 × 3  \n(40 × 3) + (  × 3) =   +   =    \n3. 35 × 6  \n(30 × 6) + (  × 6) =   +   =    \n4. 58 × 2  \n(50 × 2) + (  × 2) =   +   =    \n5. 19 × 5  \n(10 × 5) + (  × 5) =   +   =    \n6. 64 × 7  \n(60 × 7) + (  × 7) =   +   =    \nPart B—Missing Subtracted Part (Near Ten) (7–10)  \n7. 29 × 6  \n(30 × 6) − (  × 6) =   −   =   8. 48 × 5  \n(50 × 5) − (  × 5) =   −   =    \n1  \nMashup Math LLC | Al[l Rights Reserved | Get More K-12 Math Worksheets at ](l Rights Reserved | Get More K-12 Math Worksheets at www.mashupmath.com)[www.mashupmath.com](l Rights Reserved | Get More K-12 Math Worksheets at www.mashupmath.com)  \n9. 19 × 8  \n(20 × 8) − (  × 8) =   −   =   10.97 × 4  \n(100 × 4) − (  × 4) =   −   =    \nPart C—Missing Factor (11–14)  \n11. (20 × 7) + (6 × 7) = 140 + 42 =   So, 26 ×   =    \n12. (40 × 3) + (5 × 3) = 120 + 15 =   So, 45 ×   =    \n13. (50 × 6) − (2 × 6) = 300 − 12 =   So, 48 ×   =    \n14. (30 × 8) − (1 × 8) = 240 − 8 =   So, 29 ×   =    \nChallenge Problem (Show your thinking)  \n15.A club is making 28 treat bags. Each bag has 7 cookies.  \nUse the distributive property to find the total. Work:  \n(20 × 7) + (  × 7) =   +   =   cookies  \nOne sentence: Explain how the distributive property helped you:  \n2  \nMashup Math LLC | Al[l Rights Reserved | Get More K-12 Math Worksheets at ](l Rights Reserved | Get More K-12 Math Worksheets at www.mashupmath.com)[www.mashupmath.com](l Rights Reserved | Get More K-12 Math Worksheets at www.mashupmath.com)  \nAnswer Key  \n1. (20×4) + (6 ×4) = 80 + 24 = 104  \n2. (40×3) + (7 ×3) = 120 + 21 = 141  \n3. (30×6) + (5 ×6) = 180 + 30 = 210  \n4. (50×2) + (8 ×2) = 100 + 16 = 116  \n5. (10×5) + (9 ×5) = 50 + 45 = 95  \n6. (60×7) + (4 ×7) = 420 + 28 = 448  \n7. (30×6) − ( 1 ×6) = 180 − 6 = 174  \n8. (50×5) − (2 ×5) = 250 − 10 = 240  \n9. (20×8) − ( 1 ×8) = 160 − 8 = 152  \n10. (100×4) − (3 ×4) = 400 − 12 = 388  \n11. 140 + 42 = 182 ; so 26 × 7 = 182  \n12. 120 + 15 = 135 ; so 45 × 3 = 135  \n13.300 − 12 = 288 ; so 48 × 6 = 288  \n14.240 − 8 = 232 ; so 29 × 8 = 232  \n15. (20×7) + (8 ×7) = 140 + 56 = 196 cookies  \nOne sentence (sample): Breaking 28 into 20 and 8 makes the multiplication easier, then  \nyou add the partial products.  \nMashup Math LLC | Al[l Rights Reserved | Get More K-12 Math Worksheets at ](l Rights Reserved | Get More K-12 Math Worksheets at www.mashupmath.com)[www.mashupmath.com](l Rights Reserved | Get More K-12 Math Worksheets at www.mashupmath.com)  \n3","cbCaiq7fEmoJ9wHF","https://ap.wps.com/l/cbCaiq7fEmoJ9wHF","pdf",1306994,"English","# Directions\n# Part A—Missing Addend in a Break-Apart (1–6)\n# Part B—Missing Subtracted Part (7–10)\n# Part C—Missing Factor (11–14)\n# Challenge Problem (15)\n# Answer Key","[{\"question\":\"How do you solve Part A problems using the distributive property?\",\"answer\":\"Break one factor into tens and ones (or another compatible sum), multiply each part by the other factor, then add the partial products to get the final product.\"},{\"question\":\"What strategy helps with Part B “missing subtracted part (near ten)” problems?\",\"answer\":\"Rewrite the expression using numbers close to ten so the subtraction creates manageable partial products; then subtract the missing part and compute the product.\"},{\"question\":\"How do you approach the challenge problem about treat bags and cookies?\",\"answer\":\"Find total cookies by splitting 28 into two addends, multiply each addend by 7 using distributive property, add the partial results, and then write one sentence explaining how the break-apart made multiplication easier.\"}]","Missing Numbers Using The Distributive Property - Fill in the Missing Numbers and Find the Products | PDF",1790131942]