[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"detail-sidebar-cat-0-en-105":3,"doc-seo-522700-105":59,"doc-detail-522700-en":131},{"code":4,"msg":5,"data":6},0,"success",[7,13,18,23,28,33,38,43,48,51,55],{"id":8,"doc_module":4,"doc_module_name":9,"category_name":10,"show_sort_weight":11,"slug":12},1,"Document","Story & Novel",90,"story-novel",{"id":14,"doc_module":4,"doc_module_name":9,"category_name":15,"show_sort_weight":16,"slug":17},2,"Literature",80,"literature",{"id":19,"doc_module":4,"doc_module_name":9,"category_name":20,"show_sort_weight":21,"slug":22},4,"Exam",70,"exam",{"id":24,"doc_module":4,"doc_module_name":9,"category_name":25,"show_sort_weight":26,"slug":27},5,"Comic",60,"comic",{"id":29,"doc_module":4,"doc_module_name":9,"category_name":30,"show_sort_weight":31,"slug":32},6,"Technology",50,"technology",{"id":34,"doc_module":4,"doc_module_name":9,"category_name":35,"show_sort_weight":36,"slug":37},7,"Healthcare",40,"healthcare",{"id":39,"doc_module":4,"doc_module_name":9,"category_name":40,"show_sort_weight":41,"slug":42},8,"Research & Report",30,"research-report",{"id":44,"doc_module":4,"doc_module_name":9,"category_name":45,"show_sort_weight":46,"slug":47},9,"Religion & Spirituality",20,"religion-spirituality",{"id":46,"doc_module":4,"doc_module_name":9,"category_name":49,"show_sort_weight":46,"slug":50},"World Cup","world-cup",{"id":52,"doc_module":4,"doc_module_name":9,"category_name":53,"show_sort_weight":52,"slug":54},10,"Lifestyle","lifestyle",{"id":56,"doc_module":4,"doc_module_name":9,"category_name":57,"show_sort_weight":24,"slug":58},19,"General","general",{"code":4,"msg":60,"data":61},"ok",{"site_id":62,"language":63,"slug":64,"title":65,"keywords":66,"description":67,"schema_data":68,"social_meta":124,"head_meta":126,"extra_data":128,"updated_unix":130},105,"en","inverses-of-logarithms","Inverses of Logarithms","","Worksheets for solving inverse logarithmic functions. Students are asked to find the inverse of multiple logarithm expressions, including cases with negative coefficients inside the log, shifts and scalings in the argument, and different base values. The problems require transforming each function into its inverse relation, then rewriting the inverse in proper logarithmic form. Suitable for practice in algebra 2 topics on inverses and logarithms.",{"@graph":69,"@context":123},[70,84,106],{"@type":71,"itemListElement":72},"BreadcrumbList",[73,77,79,82],{"item":74,"name":75,"@type":76,"position":8},"https://docshare.wps.com","Home","ListItem",{"item":78,"name":9,"@type":76,"position":14},"https://docshare.wps.com/document/",{"item":80,"name":20,"@type":76,"position":81},"https://docshare.wps.com/document/exam/",3,{"item":83,"name":65,"@type":76,"position":19},"https://docshare.wps.com/document/inverses-of-logarithms/522700/",{"url":83,"name":65,"@type":85,"image":86,"author":91,"headline":65,"publisher":94,"fileFormat":97,"inLanguage":63,"description":67,"dateModified":98,"datePublished":99,"encodingFormat":97,"isAccessibleForFree":100,"interactionStatistic":101},"DigitalDocument",{"url":87,"@type":88,"width":89,"height":90},"https://docshare.wps.com/thumbnails/inverses-of-logarithms/522700.png","ImageObject",300,407,{"name":92,"@type":93},"\tJames","Person",{"url":74,"name":95,"@type":96},"DocShare","Organization","application/pdf","2026-11-10","2026-10-08",true,{"@type":102,"interactionType":103,"userInteractionCount":105},"InteractionCounter",{"@type":104},"ViewAction",12,{"@type":107,"mainEntity":108},"FAQPage",[109,115,119],{"name":110,"@type":111,"acceptedAnswer":112},"What is the goal of the worksheet?","Question",{"text":113,"@type":114},"The worksheet asks students to find the inverse of each given logarithmic function.","Answer",{"name":116,"@type":111,"acceptedAnswer":117},"What types of logarithmic functions are included?",{"text":118,"@type":114},"The problems include logarithms with different bases and with argument changes such as shifts, scaling, and expressions involving negative terms.",{"name":120,"@type":111,"acceptedAnswer":121},"How should students approach each problem?",{"text":122,"@type":114},"For each function, rewrite the equation, swap the role of x and y to form the inverse relation, and then solve for the new dependent variable in logarithmic form.","https://schema.org",{"og:url":83,"og:type":125,"og:title":65,"og:site_name":95,"og:description":67},"article",{"robots":127,"canonical":83},"index,follow",{"doc_id":129,"site_id":62},522700,1791504211,{"code":4,"msg":5,"data":132},{"doc_id":129,"user_id":133,"nickname":92,"user_avatar":134,"doc_module":4,"category_id":19,"category_name":20,"doc_title":65,"doc_description":67,"doc_content":135,"file_id":136,"file_url":137,"file_type":138,"file_size":139,"view_count":105,"is_deleted":4,"is_public":8,"is_downloadable":8,"audit_status":8,"page_count":19,"language":140,"language_code":63,"site_id":62,"html_lang":63,"table_of_contents":141,"faqs":142,"seo_title":143,"seo_description":67,"update_tm":144,"read_time":52,"preview_page_count":4},2336474466412,"https://ap-avatar.wpscdn.com/davatar_155a257f0dc6eb9ab79c44ca47cae57d","Kuta Software-Infinite Algebra 2 Name   \nInverses of Logarithms Date  Period   \nFind the inverse of each function.  \n1) y = log (−2x) 2) y = log  1 x 5  \n4  \n3) y = log  1 x − 4 4) y = log 3 (4 x − 4) 5  \n5) y = log 2 (3x 3 ) 6) y = −7 log 6 (−3x)  \n7) y = log 2 (x + 5) − 9 8) y = log 6 (4x + 4)  \n9) y = log 5 (3x 3 − 6) 10) y = 6log 2 (2 x − 7)  \n11) y = 6 log 5 (−4x) − 7 x  \n4  \n12) y = 6  \n51 + x + 1 14) y = 5 x − 8  \n13) y =  5 x   \nx  1  \n2 16) y = − ~~ ~~  \n15) y = 5 41 + x  \n 1   1   \n17) y = (~~ ~~x2) 3 18) y = (4 x − 1) 5  \n 1   1   \n19) y = (5 x − 7) 4 20) y = ((15) x − 2) 2  \n1  3 x + 9  \n21) y = (~~ ~~3~~ ~~−3~~ ~~8~~ ~~ ) 4 22) y = log 5  2   \n 1   1   \n23) y = (~~ ~~3~~ ~~−2~~ ~~4~~ ~~ ) 2 24) y = (~~ ~~3~~ ~~x~~ ~~~~ ~~9~~ ~~ ) 5  \nKuta Software-Infinite Algebra 2 Name   \nInverses of Logarithms Date  Period   \nFind the inverse of each function.  \n1) y = log (−2x)  \ny = − ~~ ~~102x  \n3) y = log  1 x − 4  \n5  \ny =  1   \n5 x + 4  \n5) y = log 2 (3x 3 )  1   \ny = (~~ ~~23x~~ ~~ ) 3  \n7) y = log 2 (x + 5) − 9  \ny = 2x + 9 − 5  \n9) y = log 5 (3x 3 − 6)  1   \ny = (~~ ~~5~~ ~~x~~ ~~~~ ~~6~~ ~~ ) 3  \n11) y = 6 log 5 (−4x) − 7  \ny =  \nx + 7   \n65  \n−4  \n2) y = log  1 4  \nx 5  \ny = ~~ ~~514~~ ~~x  \n4) y = log 3 (4 x − 4)  \ny = log 4 (3 x + 4)  \n6) y = −7 log 6 (−3x)  \ny =  \nx −  \n76  \n−3  \n8) y = log 6 (4x + 4)  \ny =  \n6 x − 4 4  \n10) y = 6 log 2 (2 x − 7)  \ny = log 2 (2~~ ~~x6 + 7)  \nx  \n4  \n12) y = 6  \ny = log 6 x4  \n51 + x + 1 14) y = 5 x − 8  \n13) y = ~~ ~~  \n5 x y = log 5 (x + 8) y = log  1 (x − 5)  \n5  \nx  1  \n15) y = 5 2 16) y = −  41 + x  \ny = log 5 x2 y = log  1 −4x  \n4  \n 1   1   \n17) y = (~~ ~~x2~~ ~~ ) 3 18) yy(4lo−4 1(x) 55 + 1)  \ny = log 4 −2x 3  \n 1   1   \n19) yy(5lo−5 7(x) 44 + 7) 20) y = ((15) x − 2) 2  \ny = log  1 (x 2 + 2) 5  \n1  3 x + 9  \n21) y = (~~ ~~3~~ ~~−3~~ ~~8~~ ~~ ) 4 22) y = log 5  2   \ny = log 3 (2 ⋅ 5x − 9)  \ny = log 3 (−3x 4 + 8)  \n 1   1   \n23) y = (~~ ~~3~~ ~~−2~~ ~~4~~ ~~ ) 2 24) y = (~~ ~~3~~ ~~x~~ ~~~~ ~~9~~ ~~ ) 5  \ny = log 3 (−2x 2 + 4) y = log 3 (3x 5 + 9)  \nCreate your own worksheets like this one with Infinite Algebra 2. Free trial available [at KutaSoftware.com](at KutaSoftware.com)","cbCaikvMOJcebVNG","https://ap.wps.com/l/cbCaikvMOJcebVNG","pdf",34240,"English","# Find the inverse of each function","[{\"question\":\"What is the goal of the worksheet?\",\"answer\":\"The worksheet asks students to find the inverse of each given logarithmic function.\"},{\"question\":\"What types of logarithmic functions are included?\",\"answer\":\"The problems include logarithms with different bases and with argument changes such as shifts, scaling, and expressions involving negative terms.\"},{\"question\":\"How should students approach each problem?\",\"answer\":\"For each function, rewrite the equation, swap the role of x and y to form the inverse relation, and then solve for the new dependent variable in logarithmic form.\"}]","Inverses of Logarithms | PDF",1791426073]