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The data are summarized in the table above. Based on the data from the study, an estimate of the percent of US teens who are heavy texters is 30% and the associated margin of error is 3% . Which of the following is a correct statement based on the given margin of error?  \nA. Approximately 3% of the teens in the study who are classified as heavy texters are not really heavy texters.  \nB. It is not possible that the percent of all US teens who are heavy texters is less than 27% .  \nC. The percent of all US teens who are heavy texters is 33% .  \nD. It is doubtful that the percent of all US teens who are heavy texters is 35% .  \nID: 85939da5 Answer  \nCorrect Answer: D  \nRationale  \nChoice D is correct. The given margin of error of 3% indicates that the actual percent of all US teens who are heavy texters is likely within 3% of the estimate of 30%, or between 27% and 33% . Therefore, it is unlikely, or doubtful, that the percent of all US teens who are heavy texters would be 35% .  \nChoice A is incorrect. The margin of error doesn’t provide any information about the accuracy of reporting in the study. Choice B is incorrect. Based on the estimate and given margin of error, it is unlikely that the percent of all US teens who are heavy texters would be less than 27%, but it is possible. Choice C is incorrect. While the percent of all US teens who are heavy texters is likely between 27% and 33%, any value within this interval is equally likely. We can’t be certain that the value is exactly 33% .  \nQuestion Difficulty: Hard  \nQuestion ID c7e73ece  \n\n| Assessment\u003Cbr>SAT | Test\u003Cbr>Math | Domain\u003Cbr>Problem-Solving and Data Analysis | Skill\u003Cbr>Inference from sample statistics and margin of error | Difficulty\u003Cbr>|\n| --- | --- | --- | --- | --- |\n\nID: c7e73ece  \nViews on Nuclear Energy Use  \n\n| Response | Frequency |\n| --- | --- |\n| Strongly favor | 56 |\n| Somewhat\u003Cbr>favor | 214 |\n| Somewhat\u003Cbr>oppose | 104 |\n| Strongly\u003Cbr>oppose | 37 |\n\nA researcher interviewed 411 randomly selected US residents and asked about their views on the use of nuclear energy. The table above summarizes the responses of the interviewees. If the population of the United States was 300 million when the survey was given, based on the sample data for the 411 US residents, what is the best estimate, in millions, of the difference between the number of US residents who somewhat favor or strongly favor the use of nuclear energy and the number of those who somewhat oppose or strongly oppose it? (Round your answer to the nearest whole number.)  \nID: c7e73ece Answer  \nRationale  \nThe correct answer is 94. Of those interviewed,  “strongly favor” or “somewhat favor” the use of nuclear energy, and  interviewees “somewhat oppose” or “strongly oppose” the use of nuclear energy. The difference between the sizes of the two surveyed groups is  . The proportion of this difference among the entire group  \nof interviewees is . Because the sample of interviewees was selected at random from US residents, it is reasonable to assume that the proportion of this difference is the same among all US residents as in the sample. Therefore, the best estimate, in millions, of the difference between the number of US residents who somewhat favor or strongly favor the use of  \nnuclear energy and the number of those who somewhat oppose or strongly oppose it is , which to the nearest million is 94.  \nQuesti","cbCait0S3koh9a6P","https://ap.wps.com/l/cbCait0S3koh9a6P","pdf",1872472,51,"English","# SAT Math Statistics Questions\n## Margin of Error and Estimation\n## Nuclear Energy Use Survey\n## Box Plot Median Comparison","[{\"question\":\"How does a margin of error determine what is likely or unlikely about the true percentage?\",\"answer\":\"The margin of error defines an interval around the estimate. Values outside that interval are unlikely, while values within the interval are plausible based on the provided error bounds.\"},{\"question\":\"How is the population difference estimated from favor/oppose survey results?\",\"answer\":\"Compute the difference in counts (favor minus oppose) using the sample, then scale that difference to the entire population using the proportionality implied by random sampling.\"},{\"question\":\"What box-plot information is sufficient to answer which statement must be true?\",\"answer\":\"The median line inside each box provides the central tendency needed for must-be-true comparisons. Mean values generally cannot be determined from box plots.\"}]","HARD stats and scatterplots KEY - SAT Math Problem-Solving and Data Analysis | PDF",1789407727,129]