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It provides clear, step-by-step instructions on selecting two points (x1, y1) and (x2, y2) from a given line and applying the slope formula m = (y2 - y1) / (x2 - x1). The worksheet includes structured problem-solving sections followed by an answer key that demonstrates the full working-out process for three distinct coordinate-based problems, ensuring learners understand how to simplify results into whole numbers or fractions. By focusing on practical application, the resource effectively builds foundational algebra skills, helping students visualize and quantify the steepness of lines through coordinate geometry. This resource is highly suitable for classroom exercises, home practice, or as a supplement for mathematics curriculum reinforcement, offering both the problem sets and the necessary guidance for self-assessment and conceptual clarity in analytical linear algebra.",{"@graph":69,"@context":122},[70,84,105],{"@type":71,"itemListElement":72},"BreadcrumbList",[73,77,79,82],{"item":74,"name":75,"@type":76,"position":8},"https://docshare.wps.com","Home","ListItem",{"item":78,"name":9,"@type":76,"position":14},"https://docshare.wps.com/document/",{"item":80,"name":20,"@type":76,"position":81},"https://docshare.wps.com/document/exam/",3,{"item":83,"name":65,"@type":76,"position":19},"https://docshare.wps.com/document/gradient-of-a-linear-equation-worksheet-3/637977/",{"url":83,"name":65,"@type":85,"image":86,"author":91,"headline":65,"publisher":94,"fileFormat":97,"inLanguage":63,"description":67,"dateModified":98,"datePublished":99,"encodingFormat":97,"isAccessibleForFree":100,"interactionStatistic":101},"DigitalDocument",{"url":87,"@type":88,"width":89,"height":90},"https://docshare.wps.com/thumbnails/gradient-of-a-linear-equation-worksheet-3/637977.png","ImageObject",300,407,{"name":92,"@type":93},"mieayamfan","Person",{"url":74,"name":95,"@type":96},"DocShare","Organization","application/pdf","2026-11-02","2026-10-22",true,{"@type":102,"interactionType":103,"userInteractionCount":29},"InteractionCounter",{"@type":104},"ViewAction",{"@type":106,"mainEntity":107},"FAQPage",[108,114,118],{"name":109,"@type":110,"acceptedAnswer":111},"What formula is used to find the gradient of a linear equation?","Question",{"text":112,"@type":113},"The gradient (m) is calculated using the formula m = (y2 – y1) / (x2 – x1), where (x1, y1) and (x2, y2) are two points on the line.","Answer",{"name":115,"@type":110,"acceptedAnswer":116},"How should the final gradient answer be expressed?",{"text":117,"@type":113},"The answer should be given either as a whole number or as a fraction in its simplest form.",{"name":119,"@type":110,"acceptedAnswer":120},"What points were used to calculate the gradient for the second problem in the answer key?",{"text":121,"@type":113},"The points used for the second problem are (-4, 2) and (2, 5), resulting in a gradient of 1/2 or 0.5.","https://schema.org",{"og:url":83,"og:type":124,"og:title":65,"og:site_name":95,"og:description":67},"article",{"robots":126,"canonical":83},"index,follow",{"doc_id":128,"site_id":62},637977,1792856092,{"code":4,"msg":5,"data":131},{"doc_id":128,"user_id":132,"nickname":92,"user_avatar":133,"doc_module":4,"category_id":19,"category_name":20,"doc_title":65,"doc_description":67,"doc_content":134,"file_id":135,"file_url":136,"file_type":137,"file_size":138,"view_count":29,"is_deleted":4,"is_public":8,"is_downloadable":8,"audit_status":8,"page_count":14,"language":139,"language_code":63,"site_id":62,"html_lang":63,"table_of_contents":140,"faqs":141,"seo_title":142,"seo_description":67,"update_tm":143,"read_time":24},962090893677,"https://ap-avatar.wpscdn.com/davatar_3d24733baf745e90a7e4bdd5f77d97b2","Name Date  \nGRADIENT OF A LINEAR EQUATION SHEET 3  \n• Take the two points (x1, y 1) and (x2, y2) which lie on the line shown.  \n• Find the gradient using the equation m = (y2 – y1 )/(x2 –x1) .  \n• Give your answer as a whole number or as a fraction in simplest form.  \n1)  \n2)  \n3)  \nWORKING OUT  \nName Date  \nGRADIENT OF A LINEAR EQUATION SHEET 3 ANSWERS  \n1)  \n2)  \n3)  \nWORKING OUT  \nTake points (0,0) and (2,3) m = (3 – 0)/(2 – 0) = 3/2 or 1.5 The gradient is 3/2 or 1.5  \nTake points (-4, 2) and (2, 5) m = (5 – 2)/(2 –(-4)) = 3/6 = ½ The gradient is ½ or 0.5  \nTake points (-3, 5) and (3, 3) m = (3 – 5)/(3 –(-3)) = -2/6 = - ⅓ The gradient is- ⅓.","cbCailvgatkw96oB","https://ap.wps.com/l/cbCailvgatkw96oB","pdf",214963,"English","# Calculation Instructions\n## Worksheet Problems\n## Answer Key and Working Out","[{\"question\":\"What formula is used to find the gradient of a linear equation?\",\"answer\":\"The gradient (m) is calculated using the formula m = (y2 – y1) / (x2 – x1), where (x1, y1) and (x2, y2) are two points on the line.\"},{\"question\":\"How should the final gradient answer be expressed?\",\"answer\":\"The answer should be given either as a whole number or as a fraction in its simplest form.\"},{\"question\":\"What points were used to calculate the gradient for the second problem in the answer key?\",\"answer\":\"The points used for the second problem are (-4, 2) and (2, 5), resulting in a gradient of 1/2 or 0.5.\"}]","Gradient of a Linear Equation - Worksheet 3 | PDF",1792681849]