[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"detail-sidebar-cat-0-en-105":3,"doc-seo-207388-105":59,"doc-detail-207388-en":124},{"code":4,"msg":5,"data":6},0,"success",[7,13,18,23,28,33,38,43,48,51,55],{"id":8,"doc_module":4,"doc_module_name":9,"category_name":10,"show_sort_weight":11,"slug":12},1,"Document","Story & Novel",90,"story-novel",{"id":14,"doc_module":4,"doc_module_name":9,"category_name":15,"show_sort_weight":16,"slug":17},2,"Literature",80,"literature",{"id":19,"doc_module":4,"doc_module_name":9,"category_name":20,"show_sort_weight":21,"slug":22},4,"Exam",70,"exam",{"id":24,"doc_module":4,"doc_module_name":9,"category_name":25,"show_sort_weight":26,"slug":27},5,"Comic",60,"comic",{"id":29,"doc_module":4,"doc_module_name":9,"category_name":30,"show_sort_weight":31,"slug":32},6,"Technology",50,"technology",{"id":34,"doc_module":4,"doc_module_name":9,"category_name":35,"show_sort_weight":36,"slug":37},7,"Healthcare",40,"healthcare",{"id":39,"doc_module":4,"doc_module_name":9,"category_name":40,"show_sort_weight":41,"slug":42},8,"Research & Report",30,"research-report",{"id":44,"doc_module":4,"doc_module_name":9,"category_name":45,"show_sort_weight":46,"slug":47},9,"Religion & Spirituality",20,"religion-spirituality",{"id":46,"doc_module":4,"doc_module_name":9,"category_name":49,"show_sort_weight":46,"slug":50},"World Cup","world-cup",{"id":52,"doc_module":4,"doc_module_name":9,"category_name":53,"show_sort_weight":52,"slug":54},10,"Lifestyle","lifestyle",{"id":56,"doc_module":4,"doc_module_name":9,"category_name":57,"show_sort_weight":24,"slug":58},19,"General","general",{"code":4,"msg":60,"data":61},"ok",{"site_id":62,"language":63,"slug":64,"title":65,"keywords":66,"description":67,"schema_data":68,"social_meta":117,"head_meta":119,"extra_data":121,"updated_unix":123},105,"en","gcse-science-chemistry-higher-tier-end-of-year-10-test-2018","GCSE Science Chemistry Higher Tier - End of Year 10 test 2018","","GCSE Science (Chemistry, Higher Tier) End of Year 10 test 2018 assesses understanding of key chemical reactions and metals. The paper includes questions on magnesium reacting with air to form magnesium oxide, percent by mass calculations, and evaluating sources of mass change and experimental accuracy. It also examines metal occurrence in ores and Earth’s crust, comparative extraction history, production ratios, and reactions in a blast furnace. Further sections cover electrolysis of potassium chloride solution and hydrogen gas measurement.",{"@graph":69,"@context":116},[70,84,99],{"@type":71,"itemListElement":72},"BreadcrumbList",[73,77,79,82],{"item":74,"name":75,"@type":76,"position":8},"https://docshare.wps.com","Home","ListItem",{"item":78,"name":9,"@type":76,"position":14},"https://docshare.wps.com/document/",{"item":80,"name":20,"@type":76,"position":81},"https://docshare.wps.com/document/exam/",3,{"item":83,"name":65,"@type":76,"position":19},"https://docshare.wps.com/document/gcse-science-chemistry-higher-tier-end-of-year-10-test-2018/207388/",{"url":83,"name":65,"@type":85,"author":86,"headline":65,"publisher":89,"fileFormat":92,"inLanguage":63,"description":67,"dateModified":93,"datePublished":93,"encodingFormat":92,"isAccessibleForFree":94,"interactionStatistic":95},"DigitalDocument",{"name":87,"@type":88},"Patrick","Person",{"url":74,"name":90,"@type":91},"DocShare","Organization","application/pdf","2026-09-05",true,{"@type":96,"interactionType":97,"userInteractionCount":4},"InteractionCounter",{"@type":98},"ViewAction",{"@type":100,"mainEntity":101},"FAQPage",[102,108,112],{"name":103,"@type":104,"acceptedAnswer":105},"How is the percentage by mass of magnesium in magnesium oxide calculated?","Question",{"text":106,"@type":107},"Determine the mass of magnesium and the mass of the product after heating, then use the percentage by mass formula based on those two values.","Answer",{"name":109,"@type":104,"acceptedAnswer":110},"What improvement helps the student obtain a more accurate result for the magnesium investigation?",{"text":111,"@type":107},"Heating until the mass is constant and using a balance that measures to one decimal place would improve accuracy.",{"name":113,"@type":104,"acceptedAnswer":114},"What is the purpose of electrolysis in the experiment with potassium chloride solution?",{"text":115,"@type":107},"Electrolysis is used to produce hydrogen gas, and the volume of hydrogen formed in a fixed time is recorded for different masses of potassium chloride.","https://schema.org",{"og:url":83,"og:type":118,"og:title":65,"og:site_name":90,"og:description":67},"article",{"robots":120,"canonical":83},"index,follow",{"doc_id":122,"site_id":62},207388,1788599369,{"code":4,"msg":5,"data":125},{"doc_id":122,"user_id":126,"nickname":87,"user_avatar":127,"doc_module":4,"category_id":19,"category_name":20,"doc_title":65,"doc_description":67,"doc_content":128,"file_id":129,"file_url":130,"file_type":131,"file_size":132,"view_count":4,"is_deleted":4,"is_public":8,"is_downloadable":8,"audit_status":8,"page_count":133,"language":134,"language_code":63,"site_id":62,"html_lang":63,"table_of_contents":135,"faqs":136,"seo_title":137,"seo_description":67,"update_tm":123,"read_time":26},549758146520,"https://ap-avatar.wpscdn.com/avatar/80002397d8c0411e94?_k=1775819394049821470","| Please write clearly in block capitals. |  |  |  |\n| --- | --- | --- | --- |\n| Centre number |  | Candidate number |  |\n| Surname  \u003Cbr>Forename(s)  \u003Cbr>Candidate signature   |  |  |  |\n\nGCSE SCIENCE  \nCHEMISTRY  \nHigher Tier  \nH  \nEnd of Year 10 test 2018 Time allowed: 1 hour  \nMaterials  \nFor this paper you must have:  \n• a ruler  \n• a scientific calculator  \n• the periodic table.  \nInstructions  \n• Use black ink or black ball-point pen.  \n• Fill in the boxes at the top of this page.  \n• Answer all questions in the spaces provided.  \n• Do all rough work in this book. Cross through any work you do not want to be marked.  \n• In all calculations, show clearly how you work out your answer.  \nInformation  \n• The maximum mark for this paper is 60.  \n• The marks for questions are shown in brackets.  \n• You are expected to use a calculator where appropriate.  \n• You are reminded of the need for good English and clear presentation in your answers.  \n\n| For Examiner’s Use |  |\n| --- | --- |\n| Question | Mark |\n| 1 |  |\n| 2 |  |\n| 3 |  |\n| 4 |  |\n| 5 |  |\n| 6 |  |\n| 7 |  |\n| TOTAL |  |\n\n2  \nDo not write outside the box  \n 0  1  A student investigated the reaction of magnesium with air.  \nThe equation for the reaction is:  \n2Mg(s) + O2(g) → 2MgO(s)  \nFigure 1 shows the apparatus the student used.  \nFigure 1  \nThis is the method used.  \n1. Measure the mass of a crucible and lid.  \n2. Add magnesium ribbon to the crucible.  \n3. Measure the mass of the crucible, lid and magnesium ribbon.  \n4. Heat the crucible and magnesium ribbon for 10 minutes.  \n5. Lift the lid of the crucible every few minutes.  \n6. Weigh the crucible, lid and product (magnesium oxide) after heating.  \nTable 1 shows the student’s results.  \nTable 1  \n\n| Mass of crucible and lid | 52.34 g |\n| --- | --- |\n| Mass of crucible, lid and magnesium ribbon | 52.52 g |\n| Mass of crucible, lid and product after heating for 10 minutes | 52.63 g |\n\n3  \nDo not write outside the box  \n 0  1  .  1  Calculate the percentage by mass of magnesium in the product.  \nYou should first determine:  \n• the mass of magnesium  \n• the mass of the product.  \n[3 marks]  \nMass of magnesium =   g  \nMass of product =   g  \nPercentage of magnesium =   %  \n 0  1  . 2 Explain why the reaction appears to involve a change in mass.  \n[2 marks]  \n|  |\n| --- |\n|  |\n|  |\n\nQuestion 1 continues on the next page  \n4  \nDo not write outside the box  \n\n| 0 | 1 | . | 3 | What improvement could the student make to obtain a more accurate result?\u003Cbr>Tick one box.\u003Cbr>Add more magnesium to the crucible.\u003Cbr>Heat the crucible, lid and product until the mass is constant. Use a balance measuring to one decimal place.\u003Cbr>Use a clock instead of a stopwatch.\u003Cbr>[1 mark]\u003Cbr>\u003Cbr>The student repeated the investigation.\u003Cbr>The student used:\u003Cbr>• the same crucible and lid\u003Cbr>• the same mass of magnesium.\u003Cbr>The student did not lift the lid of the crucible during heating.\u003Cbr>The student obtained a much lower value for the mass of crucible, lid and product in the second investigation.\u003Cbr>Suggest one reason why.\u003Cbr>[1 mark] |  |\n| --- | --- | --- | --- | --- | --- |\n|  |  |  |  |  |  |\n| 0 | 1 | . | 4 |  |  |\n|  |  |  |  |  |  |\n|  |  |  |  |  |  |\n|  |  |  |  |  | 7 |\n|  |  |  |  |  |  |\n\n5  \nDo not write outside the box  \nTurn over for the next question  \nDO NOT WRITE ON THIS PAGE ANSWER IN THE SPACES PROVIDED  \n6  \nDo not write outside the box  \n 0  2  Table 2 shows information about some metals.  \nTable 2  \n\n| Metal | Date of discovery and extraction | Percentage (%) of metal in ore | Percentage (%) of Earth’s crust containing metal | Annual production in kg |\n| --- | --- | --- | --- | --- |\n| Aluminium | 1825 | 28.0 | 8.0 | 5.76 × 1010 |\n| Gold | approximately 3000 BC | Occurs as\u003Cbr>metal | 0.004 | 3.1 × 106 |\n| Iron | approximately 3000 BC | 29.0 | 5.0 | 1.15 × 1012 |\n\n 0  2  . 1 Why is gold found in the Earth as the pure metal?  \n[ 1 mark]  \n0  2  . 2 Aluminium is the most common metal in the Earth’s crust.  \nSuggest why iron was ","cbCaihrtuM8gTk2x","https://ap.wps.com/l/cbCaihrtuM8gTk2x","pdf",519961,24,"English","# End of Year 10 test 2018\n## Reaction of magnesium with air\n## Metals: discovery, extraction, and production\n## Electrolysis of potassium chloride solution","[{\"question\":\"How is the percentage by mass of magnesium in magnesium oxide calculated?\",\"answer\":\"Determine the mass of magnesium and the mass of the product after heating, then use the percentage by mass formula based on those two values.\"},{\"question\":\"What improvement helps the student obtain a more accurate result for the magnesium investigation?\",\"answer\":\"Heating until the mass is constant and using a balance that measures to one decimal place would improve accuracy.\"},{\"question\":\"What is the purpose of electrolysis in the experiment with potassium chloride solution?\",\"answer\":\"Electrolysis is used to produce hydrogen gas, and the volume of hydrogen formed in a fixed time is recorded for different masses of potassium chloride.\"}]","GCSE Science Chemistry Higher Tier - End of Year 10 test 2018 | PDF"]