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The paper also tests radioactive emission properties, ionisation effects, detection limits for spark detectors, and renewable energy applications using a wind turbine 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equation links current, potential difference and resistance in the circuit question?","Question",{"text":56,"@type":57},"The paper expects the relationship V = I R between potential difference (V), current (I) and resistance (R).","Answer",{"name":59,"@type":54,"acceptedAnswer":60},"How is the energy transferred by the battery determined in Question 1.4?",{"text":61,"@type":57},"Use the given average power output and discharge time to calculate energy transferred, applying E = P t.",{"name":63,"@type":54,"acceptedAnswer":64},"Why can a spark detector detect alpha radiation but not beta radiation?",{"text":65,"@type":57},"Because the spark detector relies on alpha particles ionising atoms near the wire mesh, while beta particles do not cause ionisation in the same way in the air gap under the detector 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|\n| Surname  \u003Cbr>Forename(s)  \u003Cbr>Candidate signature  \u003Cbr>I declare this is my own work. |  |  |  |\n\nGCSE  \nCOMBINED SCIENCE: TRILOGY  \nHigher Tier  \nPhysics Paper 1H  \nH  \nTime allowed: 1 hour 15 minutes  \nMaterials  \nFor this paper you must have:  \n• a ruler  \n• a scientific calculator  \n• the Physics Equations Sheet (enclosed) .  \nInstructions  \n• Use black ink or black ball-point pen.  \n• Pencil should be used for drawing.  \n• Fill in the boxes at the top of this page.  \n• Answer all questions in the spaces provided.  \n• If you need extra space for your answer(s), use the lined pages at the end of this book. Write the question number against your answer(s) .  \n• Do all rough work in this book. Cross through any work you do not want to be marked.  \n• In all calculations, show clearly how you work out your answer.  \n\n| For Examiner’s Use |  |\n| --- | --- |\n| Question | Mark |\n| 1 |  |\n| 2 |  |\n| 3 |  |\n| 4 |  |\n| 5 |  |\n| 6 |  |\n| TOTAL |  |\n\nInformation  \n• The maximum mark for this paper is 70.  \n• The marks for questions are shown in brackets.  \n• You are expected to use a calculator where appropriate.  \n• You are reminded of the need for good English and clear presentation in your answers.  \n*jun218464p1h01*  \nIB/M/Jun21/E6  \n8464/P/1H  \nThere are no questions printed on this page  \nDO NOT WRITE ON THIS PAGE ANSWER IN THE SPACES PROVIDED  \nDo not write outside the box  \n\n| \u003Cbr> 0  1  Figure 1 shows a mobile phone with its battery removed.\u003Cbr>Figure 1\u003Cbr>A student measured the potential difference across the battery and then put the battery into the phone.\u003Cbr> 0  1  .  1 What is the equation linking current (I), potential difference ( V) and resistance (R)?\u003Cbr>[1 mark]\u003Cbr>Tick ( 􀀹 ) one box.\u003Cbr>|  |\n| --- | --- |\n| I = V R\u003Cbr>R = I V\u003Cbr>V = I R\u003Cbr>V = I2 R | |\n| Question 1 continues on the next page |  |\n\noutside the box  \n 0  1  .  2 The current in the electronic circuit in the mobile phone was 0.12 A.  \nThe potential difference across the battery was 3.9 V.  \nCalculate the resistance of the electronic circuit in the mobile phone.  \n[3 marks]  \n\n|  |\n| --- |\n|  |\n|  |\n|  |\n|  |\n\nResistance =   Ω  \noutside the box  \n 0  1  .  3 Write down the equation which links energy (E), power (P) and time (t) .  \n[1 mark]  \n0  1  .  4 The battery was fully charged when it was put into the mobile phone.  \nThe battery discharged when the mobile phone was switched on.  \nThe average power output of the battery as it discharged was 0.46 watts.  \nThe time taken to fully discharge the battery was 2500 minutes.  \nCalculate the energy transferred by the battery.  \n[3 marks]  \nEnergy transferred =   J  \nQuestion 1 continues on the next page  \noutside the box  \n\n|  |  |  |  |  | The mobile phone includes a sensor to monitor the temperature of the battery.\u003Cbr>Figure 2 shows the circuit symbol for a component used in the sensor.\u003Cbr>Figure 2\u003Cbr>\u003Cbr>What component does the circuit symbol shown in Figure 2 represent?\u003Cbr>[1 mark]\u003Cbr>The temperature of the component in Figure 2 increases.\u003Cbr>The potential difference across the component remains constant.\u003Cbr>Explain what happens to the current in the component.\u003Cbr>[2 marks]\u003Cbr> | outside box |\n| --- | --- | --- | --- | --- | --- | --- |\n|  | 0 | 1 | . | 5 |  |  |\n|  |  |  |  |  |  |  |\n|  | 0 | 1 | . | 6 |  |  |\n|  |  |  |  |  |  |  |\n|  |  |  |  |  |  |  |\n|  |  |  |  |  |  | 11 |\n|  |  |  |  |  |  |  |\n\nthe  \n\n| 0  2 A radioactive source emits alpha, beta and gamma radiation.\u003Cbr>0  2 . 1 An alpha particle is the same as a helium nucleus.\u003Cbr>How many times bigger is the radius of a helium atom than the radius of an alpha particle?\u003Cbr>[1 mark]\u003Cbr>Tick ( 􀀹 ) one box.\u003Cbr>Less than 100 times bigger \u003Cbr>Exactly 5000 times bigger \u003Cbr>More than 10 000 times bigger \u003Cbr>0  2 . 2 Alpha particles can ionise atoms in the air.\u003Cbr>What happens to an atom when it is ionised by an alpha particle?\u003Cb","cbCail2LgytXJrQK","https://ap.wps.com/l/cbCail2LgytXJrQK","pdf",3267087,32,"English","# Question 1\n## Electricity and circuit calculations\n## Battery energy transfer\n## Temperature sensor circuit component\n# Question 2\n## Alpha, beta and gamma radiation concepts\n## Ionisation by alpha particles\n## Spark detector limitations and experimental method\n# Question 3\n## Wind turbine and renewable energy resources\n## Generator and battery charging benefits","[{\"question\":\"What equation links current, potential difference and resistance in the circuit question?\",\"answer\":\"The paper expects the relationship V = I R between potential difference (V), current (I) and resistance (R).\"},{\"question\":\"How is the energy transferred by the battery determined in Question 1.4?\",\"answer\":\"Use the given average power output and discharge time to calculate energy transferred, applying E = P t.\"},{\"question\":\"Why can a spark detector detect alpha radiation but not beta radiation?\",\"answer\":\"Because the spark detector relies on alpha particles ionising atoms near the wire mesh, while beta particles do not cause ionisation in the same way in the air gap under the detector conditions.\"}]","GCSE Combined Science: Trilogy - Higher Tier - Physics Paper 1H | PDF",81]