[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"detail-sidebar-cat-0-en-105":3,"doc-seo-657819-105":59,"doc-detail-657819-en":130},{"code":4,"msg":5,"data":6},0,"success",[7,13,18,23,28,33,38,43,48,51,55],{"id":8,"doc_module":4,"doc_module_name":9,"category_name":10,"show_sort_weight":11,"slug":12},1,"Document","Story & Novel",90,"story-novel",{"id":14,"doc_module":4,"doc_module_name":9,"category_name":15,"show_sort_weight":16,"slug":17},2,"Literature",80,"literature",{"id":19,"doc_module":4,"doc_module_name":9,"category_name":20,"show_sort_weight":21,"slug":22},4,"Exam",70,"exam",{"id":24,"doc_module":4,"doc_module_name":9,"category_name":25,"show_sort_weight":26,"slug":27},5,"Comic",60,"comic",{"id":29,"doc_module":4,"doc_module_name":9,"category_name":30,"show_sort_weight":31,"slug":32},6,"Technology",50,"technology",{"id":34,"doc_module":4,"doc_module_name":9,"category_name":35,"show_sort_weight":36,"slug":37},7,"Healthcare",40,"healthcare",{"id":39,"doc_module":4,"doc_module_name":9,"category_name":40,"show_sort_weight":41,"slug":42},8,"Research & Report",30,"research-report",{"id":44,"doc_module":4,"doc_module_name":9,"category_name":45,"show_sort_weight":46,"slug":47},9,"Religion & Spirituality",20,"religion-spirituality",{"id":46,"doc_module":4,"doc_module_name":9,"category_name":49,"show_sort_weight":46,"slug":50},"World Cup","world-cup",{"id":52,"doc_module":4,"doc_module_name":9,"category_name":53,"show_sort_weight":52,"slug":54},10,"Lifestyle","lifestyle",{"id":56,"doc_module":4,"doc_module_name":9,"category_name":57,"show_sort_weight":24,"slug":58},19,"General","general",{"code":4,"msg":60,"data":61},"ok",{"site_id":62,"language":63,"slug":64,"title":65,"keywords":66,"description":67,"schema_data":68,"social_meta":123,"head_meta":125,"extra_data":127,"updated_unix":129},105,"en","free-body-exercises-linear-motion","Free-Body Exercises - Linear Motion","","Instructional physics worksheet guiding students to draw accurate free-body diagrams for a rock in linear motion cases. It specifies that friction is negligible except where stated, and that forces should be labeled with w (weight), T (tension), n (normal reaction force), and f (friction). The material includes an equilibrium example using the parallelogram method, then provides multiple numbered linear-motion scenarios and emphasizes correct construction practices and interpretation of resultant and acceleration directions.",{"@graph":69,"@context":122},[70,84,105],{"@type":71,"itemListElement":72},"BreadcrumbList",[73,77,79,82],{"item":74,"name":75,"@type":76,"position":8},"https://docshare.wps.com","Home","ListItem",{"item":78,"name":9,"@type":76,"position":14},"https://docshare.wps.com/document/",{"item":80,"name":20,"@type":76,"position":81},"https://docshare.wps.com/document/exam/",3,{"item":83,"name":65,"@type":76,"position":19},"https://docshare.wps.com/document/free-body-exercises-linear-motion/657819/",{"url":83,"name":65,"@type":85,"image":86,"author":91,"headline":65,"publisher":94,"fileFormat":97,"inLanguage":63,"description":67,"dateModified":98,"datePublished":99,"encodingFormat":97,"isAccessibleForFree":100,"interactionStatistic":101},"DigitalDocument",{"url":87,"@type":88,"width":89,"height":90},"https://docshare.wps.com/thumbnails/free-body-exercises-linear-motion/657819.png","ImageObject",300,407,{"name":92,"@type":93},"fresh2021","Person",{"url":74,"name":95,"@type":96},"DocShare","Organization","application/pdf","2026-10-30","2026-10-26",true,{"@type":102,"interactionType":103,"userInteractionCount":29},"InteractionCounter",{"@type":104},"ViewAction",{"@type":106,"mainEntity":107},"FAQPage",[108,114,118],{"name":109,"@type":110,"acceptedAnswer":111},"What should be included in each free-body diagram for the rock?","Question",{"text":112,"@type":113},"Each diagram must show all forces acting on the rock, labeled with w (weight), T (tension), n (normal reaction force), and f (friction), including forces identified only by context such as gravity.","Answer",{"name":115,"@type":110,"acceptedAnswer":116},"Is friction always ignored in the linear-motion exercises?",{"text":117,"@type":113},"Friction is negligible except where the problem explicitly notes otherwise, such as cases involving kinetic friction or where sliding occurs on an incline.",{"name":119,"@type":110,"acceptedAnswer":120},"How does the worksheet handle the equilibrium example LM-1?",{"text":121,"@type":113},"LM-1 is worked using the parallelogram method, drawing vectors for the forces and using construction steps (including balance considerations) so the diagram reflects equilibrium conditions.","https://schema.org",{"og:url":83,"og:type":124,"og:title":65,"og:site_name":95,"og:description":67},"article",{"robots":126,"canonical":83},"index,follow",{"doc_id":128,"site_id":62},657819,1793086518,{"code":4,"msg":5,"data":131},{"doc_id":128,"user_id":132,"nickname":92,"user_avatar":133,"doc_module":4,"category_id":19,"category_name":20,"doc_title":65,"doc_description":67,"doc_content":134,"file_id":135,"file_url":136,"file_type":137,"file_size":138,"view_count":29,"is_deleted":4,"is_public":8,"is_downloadable":8,"audit_status":8,"page_count":139,"language":140,"language_code":63,"site_id":62,"html_lang":63,"table_of_contents":141,"faqs":142,"seo_title":143,"seo_description":67,"update_tm":144,"read_time":145},962093912154,"https://ap-avatar.wpscdn.com/davatar_9964176cb1d06d4a9deccf72a44ae3dc","# Free-Body Exercises:Linear Motion\n\nIn each case the rock is acted on by one or more forces.All drawings are in a vertical plane,and friction is negligible exceptwhere noted.Draw accurate free-body diagrams showing all forces acting on the rock.LM-1 is done as an example,usingthe “parallelogram”method.For convenience,you may draw all forces acting at the center of mass,even though friction andnormal reaction force act at the point of contact with the surface.Please use a ruler,and do it in pencil so you can correctmistakes.Label forces using the following symbols:w=weight of rock,T=tension,n=normal reaction force,f=friction.  \n\n| LM-1.Equilibrium(Example)  \u003Cbr>Step 3.Draw liner  \u003Cbr>parallel to the two  \u003Cbr>strings,completing  \u003Cbr>the parallelogram.  \u003Cbr>Step 4.Draw  \u003Cbr>arTows along  \u003Cbr>the two strings.  \u003Cbr>The sides of the  \u003Cbr>parallelogram  \u003Cbr>are T,and T  \u003Cbr>Step 2.Draw a line  \u003Cbr>the same length as  \u003Cbr>the w arrow to  \u003Cbr>T₂  \u003Cbr>\"balance\"w.  \u003Cbr>Remember,only  \u003Cbr>Step 1.Draw an  \u003Cbr>the three black  \u003Cbr>arrow representing  \u003Cbr>arrows are the free-  \u003Cbr>the weight.  \u003Cbr>body diagram.   | LM-2.Equilibrium   | LM-3.Friction prevents sliding.   |\n| --- | --- | --- |\n| LM-4.Equilibrium   | LM-5.Equilibrium   | LM-6.Equilibrium   |\n| LM-7.Equilibrium   | LM-8.Equilibrium   | LM-9.Rock is sliding on a frictionless  \u003Cbr>incline.   |\n\n| LM-10.Rock is falling.No friction   | LM-11.Rock is sliding at constant speed  \u003Cbr>on a frictionless surface   | LM-12.Rock is falling at constant  \u003Cbr>(terminal)velocity   |\n| --- | --- | --- |\n| LM-13.Rock is decelerating because of  \u003Cbr>kinetic friction  \u003Cbr>(((   | LM-14.Rock is rising in a parabolic  \u003Cbr>trajectory.   | LM-15.Rock is at the top of a parabolic  \u003Cbr>trajectory   |\n| LM-16.Rock is tied to a rope and pulled  \u003Cbr>straight upward,accelerating at 9.8 m/s²  \u003Cbr>No friction   | LM-17.Rock is tied to a rope and pulled  \u003Cbr>so that it moves horizontally at constant  \u003Cbr>velocity.(There must be friction.   | LM-18.Rock is tied to a rope and pullec  \u003Cbr>so that it accelerates horizontally at 2g.  \u003Cbr>No friction.   |\n\n# Free-Body Solutions:Linear Motion\n\nThe dashed arrows and construction lines in these solutions are for explanation only,and not part of the finished diagram.The free-body diagram in each case consists of only the dark,solid arrows.Forces of the same magnitude or lines of thesame length are indicated by the same number of “tick”marks drawn through the two lines or arrows.Symbols:w=weight,T=tension,n=normal reaction force,f=friction.  \n\n| LM-1  \u003Cbr>parallel to the two  \u003Cbr>T,  \u003Cbr>Step 4.Draw  \u003Cbr>arrows along  \u003Cbr>the two strings.  \u003Cbr>The sides of the  \u003Cbr>parallelogram  \u003Cbr>are T₁and T₂  \u003Cbr>Step 2.Draw a line  \u003Cbr>the same length a  \u003Cbr>the w arrow to  \u003Cbr>T₂  \u003Cbr>\"balance\"w.  \u003Cbr>Step 1.Draw an  \u003Cbr>Remember,only  \u003Cbr>arTow representing  \u003Cbr>the three black  \u003Cbr>arrows are the free-  \u003Cbr>body diagram.   | LM-2   | LM-3  \u003Cbr>m  \u003Cbr>f and n are  \u003Cbr>actually  \u003Cbr>applied at  \u003Cbr>w  \u003Cbr>the surface.   |\n| --- | --- | --- |\n| LM-4  \u003Cbr>T₁  \u003Cbr>T₂  \u003Cbr>w   | LM-5  \u003Cbr>T₁  \u003Cbr>T₂  \u003Cbr>Note that the  \u003Cbr>tension is not  \u003Cbr>proportional to  \u003Cbr>string length.  \u003Cbr>w   | LM-6   |\n| LM-7   | LM-8   | LM-9  \u003Cbr>n  \u003Cbr>Resultant is in  \u003Cbr>the direction of  \u003Cbr>acceleration.   |\n\n| LM-10   | LM-12  \u003Cbr>LM-11   |\n| --- | --- |\n| LM-13  \u003Cbr>n  \u003Cbr>f is actually  \u003Cbr>applied at the  \u003Cbr>w  \u003Cbr>surface.   | LM-14  \u003Cbr>LM-15   |\n| LM-16  \u003Cbr>T(=2w)  \u003Cbr>W_   | LM-17  \u003Cbr>LM-18  \u003Cbr>T  \u003Cbr>T  \u003Cbr>2w  \u003Cbr>Resultant of  \u003Cbr>Resultant of  \u003Cbr>T and w is in  \u003Cbr>T and w is  \u003Cbr>direction off  \u003Cbr>equal to f.  \u003Cbr>acceleration.  \u003Cbr>w   |\n\n# Free-Body Exercises:Circular Motion\n\nDraw free-body diagrams showing forces acting on the rock,and in each case,indicate the centripetal force.Please notethat the rock is not in equilibrium if it is moving in a circle.The centripetal force depends on angular velocity and theremay not be any indication of exactly how big that force should be draw","cbCaitIeKn8Ock3Y","https://ap.wps.com/l/cbCaitIeKn8Ock3Y","pdf",1120659,14,"English","# Free-Body Exercises - Linear Motion\n## Free-Body Solutions - Linear Motion\n# Free-Body Exercises - Circular Motion\n# Free-Body Solutions - Circular Motion","[{\"question\":\"What should be included in each free-body diagram for the rock?\",\"answer\":\"Each diagram must show all forces acting on the rock, labeled with w (weight), T (tension), n (normal reaction force), and f (friction), including forces identified only by context such as gravity.\"},{\"question\":\"Is friction always ignored in the linear-motion exercises?\",\"answer\":\"Friction is negligible except where the problem explicitly notes otherwise, such as cases involving kinetic friction or where sliding occurs on an incline.\"},{\"question\":\"How does the worksheet handle the equilibrium example LM-1?\",\"answer\":\"LM-1 is worked using the parallelogram method, drawing vectors for the forces and using construction steps (including balance considerations) so the diagram reflects equilibrium conditions.\"}]","Free-Body Exercises - Linear Motion | PDF",1792991002,35]