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Each item instructs students to find the missing factor that makes an equation true, decomposing one or both numbers into place-value components (e.g., tens and ones) and summing the resulting partial products. An accompanying answer key provides the missing numbers for questions 1 through 15. 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on the board. 14 × 18 = (10 × 10)+ (10 × 8) + (4 × 10) +  \u003Cbr>2) 838 × 6 = (800 × 6) + (30 × 6) + (   × 6)\u003Cbr>3) Katie is using partial products to multiply. 61 × 12 = (60 × 10) + (60 × 2) + (1 ×\u003Cbr>10) +  \u003Cbr>4) Victor breaks a multiplication problem into partial products. 862 × 5 = (800 × 5)+ (60 × 5) +  \u003Cbr>5) A student breaks a multiplication problem into partial products. 312 × 9 = (300 × 9) + (10 × 9) + (___ × 9)\u003Cbr>6) A teacher shows this partial products strategy on the board. 58 × 37 = (50 × 30)+ (50 × 7) + (8 × 30) + (8 × ___)\u003Cbr>7) A student uses place value to break apart a multiplication problem. 481 × 8 =(400 × 8) + (80 × 8) +  \u003Cbr>8) 14 × 71 = (10 × 70) + (10 × 1) + (4 × 70) + (4 ×   )\u003Cbr>9) Frank is using partial products to multiply. 83 × 91 = (80 × 90) + (80 × 1) + (3 ×\u003Cbr>90) + (3 × ___)\u003Cbr>10) Faye uses place value to break apart a multiplication problem. 574 × 6 = (500 ×\u003Cbr>6) + (70 × 6) + (___ × 6)\u003Cbr>11) 428 × 3 = (400 × 3) + (20 × 3) +  \u003Cbr>12) 86 × 73 = (80 × 70) + (80 × 3) + (6 × 70) +  \u003Cbr>13) 77 × 55 = (70 × 50) + (70 × 5) + (7 × 50) +  \u003Cbr>14) A teacher shows this partial products strategy on the board. 81 × 66 = (80 × 60)+ (80 × 6) + (1 × 60) +  \u003Cbr>15) A student uses place value to break apart a multiplication problem. 383 × 2 =(300 × 2) + (80 × 2) +   |  |  |  | Answers\u003Cbr>1.  \u003Cbr>2.  \u003Cbr>3.  \u003Cbr>4.  \u003Cbr>5.  \u003Cbr>6.  \u003Cbr>7.  \u003Cbr>8.  \u003Cbr>9.  \u003Cbr>10.  \u003Cbr>11.  \u003Cbr>12.  \u003Cbr>13.  \u003Cbr>14.  \u003Cbr>15.   |  |  |  |  |  |  |  |\n| --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- |\n| \u003Cbr>\u003Cbr>Math\u003Cbr>[www.CommonCoreSheets.com](www.CommonCoreSheets.com)\u003Cbr>9\u003Cbr>1-10\u003Cbr>11-15 | 93 | 87 | 80 |  | 73 | 67 | 60 | 53 | 47 | 40 | 33 |\n|  | 27 | 20 | 13 |  | 7 | 0 |  |  |  |  |  |\n\nFinding Partial Products (Missing Number)  \nName: Answer Key  \n\n| Find the number that makes each equation true.\u003Cbr>1) A teacher shows this partial products strategy on the board. 14 × 18 = (10 × 10)+ (10 × 8) + (4 × 10) +   |  |  |  |  | Answers\u003Cbr>1.  32  |  |  |  |  |  |  |  |\n| --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- |\n| 2) | 838 × 6 = (800 × 6) + (30 × 6) + (___ × 6) |  |  |  | 2.  8  |  |  |  |  |  |  |  |\n| 3) | Katie is using partial products to multiply. 61 × 12 = (60 × 10) + (60 × 2) + (1 × 10) +   |  |  |  | 3.  2  4. 10 |  |  |  |  |  |  |  |\n| 4) | Victor breaks a multiplication problem into partial products. 862 × 5 = (800 × 5)+ (60 × 5) +   |  |  |  | 5.  2  |  |  |  |  |  |  |  |\n| 5) | A student breaks a multiplication problem into partial products. 312 × 9 = (300 × 9) + (10 × 9) + (___ × 9) |  |  |  | 6.  7  |  |  |  |  |  |  |  |\n| 6) | A teacher shows this partial products strategy on the board. 58 × 37 = (50 × 30)+ (50 × 7) + (8 × 30) + (8 × ___) |  |  |  | 7.  8  8. 1 |  |  |  |  |  |  |  |\n| 7) | A student uses place value to break apart a multiplication problem. 481 × 8 =(400 × 8) + (80 × 8) +   |  |  |  | 9.  1  |  |  |  |  |  |  |  |\n| 8) | 14 × 71 = (10 × 70) + (10 × 1) + (4 × 70) + (4 ×   ) |  |  |  | 10.  4  |  |  |  |  |  |  |  |\n| 9) | Frank is using partial products to multiply. 83 × 91 = (80 × 90) + (80 × 1) + (3 × |  |  |  | 11.  24  |  |  |  |  |  |  |  |\n| 10) | 90) + (3 × ___)\u003Cbr>Faye uses place value to break apart a multiplication problem. 574 × 6 = (500 × 6) + (70 × 6) + (___ × 6) |  |  |  | 12.  18  13. 35 |  |  |  |  |  |  |  |\n| 11) | 428 × 3 = (400 × 3) + (20 × 3) +   |  |  |  | 14.  6  |  |  |  |  |  |  |  |\n| 12) | 86 × 73 = (80 × 70) + (80 × 3) + (6 × 70) +   |  |  |  | 15.  6  |  |  |  |  |  |  |  |\n| 13) | 77 × 55 = (70 × 50) + (70 × 5) + (7 × 50) +   |  |  |  |  |  |  |  |  |  |  |  |\n| 14) | A teacher shows this partial products strategy on the board. 81 × 66 = (80 × 60)+ (80 × 6) + (1 × 60) +   |  |  |  |  |  |  |  |  |  |  |  |\n| 15) | A student uses place value to break apart a m","cbCaitYRt8DYO7el","https://ap.wps.com/l/cbCaitYRt8DYO7el","pdf",43652,"English","# Find the number that makes each equation true\n## Partial products and place value multiplication questions (1-15)\n## Answers","[{\"question\":\"What do students need to do on this worksheet?\",\"answer\":\"Find the missing number that makes each multiplication equation true using partial products and/or place value decomposition.\"},{\"question\":\"How is the multiplication modeled in these problems?\",\"answer\":\"By breaking numbers into place-value parts and multiplying each part by the other factor, then adding the partial products.\"},{\"question\":\"Where can the correct missing-number answers be found?\",\"answer\":\"In the included Answer Key section, listing the solutions for questions 1 through 15.\"}]","Finding Partial Products (Missing Number) - Answer Key | PDF",1790804182]