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The document includes an answer key listing the correct missing numbers for problems 1 through 15.",{"name":70,"@type":61,"acceptedAnswer":71},"What kinds of equations appear in the worksheet?",{"text":72,"@type":64},"The worksheet contains multiplication equations where one of the partial products uses a blank (___), and the task is to fill in that missing number.","https://schema.org",{"og:url":32,"og:type":75,"og:title":10,"og:site_name":45,"og:description":12},"article",{"robots":77,"canonical":32},"index,follow",{"doc_id":79,"site_id":7},485426,1792811534,{"code":4,"msg":82,"data":83},"success",[84,88,92,95,100,105,110,115,119,122,126],{"id":22,"doc_module":4,"doc_module_name":25,"category_name":85,"show_sort_weight":86,"slug":87},"Story & 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true.\u003Cbr>1) Debby uses place value to break apart a multiplication problem. 875 × 4 = (800 ×\u003Cbr>4) + (70 × 4) + (___ × 4)\u003Cbr>2) A teacher shows this partial products strategy on the board. 98 × 44 = (90 × 40)+ (90 × 4) + (8 × 40) + (8 × ___)\u003Cbr>3) 14 × 72 = (10 × 70) + (10 × 2) + (4 × 70) +  \u003Cbr>4) George breaks a multiplication problem into partial products. 168 × 9 = (100 × 9)+ (60 × 9) +  \u003Cbr>5) Janet is using partial products to multiply. 72 × 57 = (70 × 50) + (70 × 7) + (2 × 50) +  \u003Cbr>6) A student breaks a multiplication problem into partial products. 184 × 3 = (100 × 3) + (80 × 3) + (___ × 3)\u003Cbr>7) A student uses place value to break apart a multiplication problem. 667 × 4 =(600 × 4) + (60 × 4) +  \u003Cbr>8) 98 × 77 = (90 × 70) + (90 × 7) + (8 × 70) + (8 ×   )\u003Cbr>9) 576 × 7 = (500 × 7) + (70 × 7) + (   × 7)\u003Cbr>10) 681 × 6 = (600 × 6) + (80 × 6) +  \u003Cbr>11) A teacher shows this partial products strategy on the board. 57 × 75 = (50 × 70)+ (50 × 5) + (7 × 70) +  \u003Cbr>12) Paul is using partial products to multiply. 34 × 42 = (30 × 40) + (30 × 2) + (4 × 40)+ (4 × ___)\u003Cbr>13) 23 × 86 = (20 × 80) + (20 × 6) + (3 × 80) +  \u003Cbr>14) Roger is using partial products to multiply. 33 × 97 = (30 × 90) + (30 × 7) + (3 ×\u003Cbr>90) + (3 × ___)\u003Cbr>15) 454 × 8 = (400 × 8) + (50 × 8) +   |  |  |  | Answers\u003Cbr>1.  \u003Cbr>2.  \u003Cbr>3.  \u003Cbr>4.  \u003Cbr>5.  \u003Cbr>6.  \u003Cbr>7.  \u003Cbr>8.  \u003Cbr>9.  \u003Cbr>10.  \u003Cbr>11.  \u003Cbr>12.  \u003Cbr>13.  \u003Cbr>14.  \u003Cbr>15.   |  |  |  |  |  |  |  |\n| --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- |\n| \u003Cbr>\u003Cbr>Math\u003Cbr>[www.CommonCoreSheets.com](www.CommonCoreSheets.com)\u003Cbr>6\u003Cbr>1-10\u003Cbr>11-15 | 93 | 87 | 80 |  | 73 | 67 | 60 | 53 | 47 | 40 | 33 |\n|  | 27 | 20 | 13 |  | 7 | 0 |  |  |  |  |  |\n\nFinding Partial Products (Missing Number)  \nName: Answer Key  \n\n| Find the number that makes each equation true.\u003Cbr>1) Debby uses place value to break apart a multiplication problem. 875 × 4 = (800 ×\u003Cbr>4) + (70 × 4) + (___ × 4) |  |  |  |  | Answers\u003Cbr>1.  5  |  |  |  |  |  |  |  |\n| --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- |\n| 2) | A teacher shows this partial products strategy on the board. 98 × 44 = (90 × 40)+ (90 × 4) + (8 × 40) + (8 × ___) |  |  |  | 2.  4  |  |  |  |  |  |  |  |\n| 3) | 14 × 72 = (10 × 70) + (10 × 2) + (4 × 70) +   |  |  |  | 3.  8  |  |  |  |  |  |  |  |\n| 4) | George breaks a multiplication problem into partial products. 168 × 9 = (100 × 9)+ (60 × 9) +   |  |  |  | 4.  72  5.  14  |  |  |  |  |  |  |  |\n| 5) | Janet is using partial products to multiply. 72 × 57 = (70 × 50) + (70 × 7) + (2 × 50) +   |  |  |  | 6.  4  |  |  |  |  |  |  |  |\n| 6) | A student breaks a multiplication problem into partial products. 184 × 3 = (100 × 3) + (80 × 3) + (___ × 3) |  |  |  | 7.  28  8. 7 |  |  |  |  |  |  |  |\n| 7) | A student uses place value to break apart a multiplication problem. 667 × 4 =(600 × 4) + (60 × 4) +   |  |  |  | 9.  6  |  |  |  |  |  |  |  |\n| 8) | 98 × 77 = (90 × 70) + (90 × 7) + (8 × 70) + (8 × ___) |  |  |  | 10.  6  |  |  |  |  |  |  |  |\n| 9) | 576 × 7 = (500 × 7) + (70 × 7) + (___ × 7) |  |  |  | 11.  35  |  |  |  |  |  |  |  |\n| 10) | 681 × 6 = (600 × 6) + (80 × 6) +   |  |  |  | 12.  2  13. 18 |  |  |  |  |  |  |  |\n| 11) | A teacher shows this partial products strategy on the board. 57 × 75 = (50 × 70)+ (50 × 5) + (7 × 70) +   |  |  |  | 14.  7  |  |  |  |  |  |  |  |\n| 12) | Paul is using partial products to multiply. 34 × 42 = (30 × 40) + (30 × 2) + (4 × 40)+ (4 × ___) |  |  |  | 15.  32  |  |  |  |  |  |  |  |\n| 13) | 23 × 86 = (20 × 80) + (20 × 6) + (3 × 80) +   |  |  |  |  |  |  |  |  |  |  |  |\n| 14) | Roger is using partial products to multiply. 33 × 97 = (30 × 90) + (30 × 7) + (3 × 90) + (3 × ___) |  |  |  |  |  |  |  |  |  |  |  |\n| 15) | 454 × 8 = (400 × 8) + (50 × 8) +   |  |  |  |  |  |  |  |  |  |  |  |\n|  | Math\u003Cbr>[www.CommonCoreSheets.com](www.CommonCoreShe","cbCaik6iO5BJhA9k","https://ap.wps.com/l/cbCaik6iO5BJhA9k","pdf",43693,"English","# Find the Missing Number\n## Partial products with place value\n## Multiplication equations 1-15\n## Answer key","[{\"question\":\"What strategy do students use to solve these problems?\",\"answer\":\"Students use partial products and place value to break each multiplication into expanded parts, then determine the missing factor that makes the equation true.\"},{\"question\":\"Are answers provided for all problems?\",\"answer\":\"Yes. The document includes an answer key listing the correct missing numbers for problems 1 through 15.\"},{\"question\":\"What kinds of equations appear in the worksheet?\",\"answer\":\"The worksheet contains multiplication equations where one of the partial products uses a blank (___), and the task is to fill in that missing number.\"}]","Finding Partial Products (Missing Number) - Answer Key | PDF",1790804204]