[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"detail-sidebar-cat-0-en-105":3,"doc-detail-485421-en":59,"doc-seo-485421-105":80},{"code":4,"msg":5,"data":6},0,"success",[7,13,18,23,28,33,38,43,48,51,55],{"id":8,"doc_module":4,"doc_module_name":9,"category_name":10,"show_sort_weight":11,"slug":12},1,"Document","Story & Novel",90,"story-novel",{"id":14,"doc_module":4,"doc_module_name":9,"category_name":15,"show_sort_weight":16,"slug":17},2,"Literature",80,"literature",{"id":19,"doc_module":4,"doc_module_name":9,"category_name":20,"show_sort_weight":21,"slug":22},4,"Exam",70,"exam",{"id":24,"doc_module":4,"doc_module_name":9,"category_name":25,"show_sort_weight":26,"slug":27},5,"Comic",60,"comic",{"id":29,"doc_module":4,"doc_module_name":9,"category_name":30,"show_sort_weight":31,"slug":32},6,"Technology",50,"technology",{"id":34,"doc_module":4,"doc_module_name":9,"category_name":35,"show_sort_weight":36,"slug":37},7,"Healthcare",40,"healthcare",{"id":39,"doc_module":4,"doc_module_name":9,"category_name":40,"show_sort_weight":41,"slug":42},8,"Research & Report",30,"research-report",{"id":44,"doc_module":4,"doc_module_name":9,"category_name":45,"show_sort_weight":46,"slug":47},9,"Religion & Spirituality",20,"religion-spirituality",{"id":46,"doc_module":4,"doc_module_name":9,"category_name":49,"show_sort_weight":46,"slug":50},"World Cup","world-cup",{"id":52,"doc_module":4,"doc_module_name":9,"category_name":53,"show_sort_weight":52,"slug":54},10,"Lifestyle","lifestyle",{"id":56,"doc_module":4,"doc_module_name":9,"category_name":57,"show_sort_weight":24,"slug":58},19,"General","general",{"code":4,"msg":5,"data":60},{"doc_id":61,"user_id":62,"nickname":63,"user_avatar":64,"doc_module":4,"category_id":19,"category_name":20,"doc_title":65,"doc_description":66,"doc_content":67,"file_id":68,"file_url":69,"file_type":70,"file_size":71,"view_count":24,"is_deleted":4,"is_public":8,"is_downloadable":8,"audit_status":8,"page_count":72,"language":73,"language_code":74,"site_id":75,"html_lang":74,"table_of_contents":76,"faqs":77,"seo_title":78,"seo_description":66,"update_tm":79,"read_time":39,"preview_page_count":4},485421,5909893218464,"dhado","https://ap-avatar.wpscdn.com/davatar_085a072bc5b1113ac321206ff7593b45","Finding Partial Products (Missing Number) - Answer Key","Worksheets and an answer key for finding missing factors using the partial products (expanded multiplication) strategy. Each problem rewrites a multiplication as a sum of place-value partial products, leaving one addend factor blank. The answer key provides the missing numbers for all listed equations, including teacher/student scenarios, helping students check and understand how to decompose multi-digit multiplication into tens, ones, and corresponding products.","Finding Partial Products (Missing Number)  \nName:  \n\n| Find the number that makes each equation true.\u003Cbr>1) 21 × 93 = (20 × 90) + (20 × 3) + (1 × 90) +  \u003Cbr>2) Jerry is using partial products to multiply. 47 × 36 = (40 × 30) + (40 × 6) + (7 × 30) + (7 × ___)\u003Cbr>3) 73 × 14 = (70 × 10) + (70 × 4) + (3 × 10) + (3 ×   )\u003Cbr>4) A teacher shows this partial products strategy on the board. 83 × 78 = (80 × 70)+ (80 × 8) + (3 × 70) +  \u003Cbr>5) A student uses place value to break apart a multiplication problem. 159 × 6 =(100 × 6) + (50 × 6) +  \u003Cbr>6) 355 × 5 = (300 × 5) + (50 × 5) + (   × 5)\u003Cbr>7) Olivia uses place value to break apart a multiplication problem. 157 × 3 = (100 ×\u003Cbr>3) + (50 × 3) + (___ × 3)\u003Cbr>8) 193 × 4 = (100 × 4) + (90 × 4) +  \u003Cbr>9) A teacher shows this partial products strategy on the board. 24 × 75 = (20 × 70)+ (20 × 5) + (4 × 70) + (4 × ___)\u003Cbr>10) A student breaks a multiplication problem into partial products. 183 × 8 = (100 × 8) + (80 × 8) + (___ × 8)\u003Cbr>11) Katie is using partial products to multiply. 14 × 14 = (10 × 10) + (10 × 4) + (4 ×\u003Cbr>10) +  \u003Cbr>12) Oliver breaks a multiplication problem into partial products. 689 × 2 = (600 × 2) +(80 × 2) +  \u003Cbr>13) 819 × 6 = (800 × 6) + (10 × 6) +  \u003Cbr>14) 15 × 62 = (10 × 60) + (10 × 2) + (5 × 60) + (5 ×   )\u003Cbr>15) 134 × 2 = (100 × 2) + (30 × 2) + (   × 2) |  |  |  | Answers\u003Cbr>1.  \u003Cbr>2.  \u003Cbr>3.  \u003Cbr>4.  \u003Cbr>5.  \u003Cbr>6.  \u003Cbr>7.  \u003Cbr>8.  \u003Cbr>9.  \u003Cbr>10.  \u003Cbr>11.  \u003Cbr>12.  \u003Cbr>13.  \u003Cbr>14.  \u003Cbr>15.   |  |  |  |  |  |  |  |\n| --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- |\n| \u003Cbr>\u003Cbr>Math\u003Cbr>[www.CommonCoreSheets.com](www.CommonCoreSheets.com)\u003Cbr>2\u003Cbr>1-10\u003Cbr>11-15 | 93 | 87 | 80 |  | 73 | 67 | 60 | 53 | 47 | 40 | 33 |\n|  | 27 | 20 | 13 |  | 7 | 0 |  |  |  |  |  |\n\nFinding Partial Products (Missing Number)  \nName: Answer Key  \n\n| Find the number that makes each equation true.\u003Cbr>1) 21 × 93 = (20 × 90) + (20 × 3) + (1 × 90) +   |  |  |  |  | Answers\u003Cbr>1.  3  |  |  |  |  |  |  |  |\n| --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- |\n| 2) | Jerry is using partial products to multiply. 47 × 36 = (40 × 30) + (40 × 6) + (7 × 30) + (7 × ___) |  |  |  | 2.  6  |  |  |  |  |  |  |  |\n| 3) | 73 × 14 = (70 × 10) + (70 × 4) + (3 × 10) + (3 × ___) |  |  |  | 3.  4  |  |  |  |  |  |  |  |\n| 4) | A teacher shows this partial products strategy on the board. 83 × 78 = (80 × 70)+ (80 × 8) + (3 × 70) +   |  |  |  | 4.  24  5.  54  |  |  |  |  |  |  |  |\n| 5) | A student uses place value to break apart a multiplication problem. 159 × 6 =(100 × 6) + (50 × 6) +   |  |  |  | 6.  5  |  |  |  |  |  |  |  |\n| 6) | 355 × 5 = (300 × 5) + (50 × 5) + (___ × 5) |  |  |  | 7.  7  |  |  |  |  |  |  |  |\n| 7) | Olivia uses place value to break apart a multiplication problem. 157 × 3 = (100 × 3) + (50 × 3) + (___ × 3) |  |  |  | 8.  12  9.  5  |  |  |  |  |  |  |  |\n| 8) | 193 × 4 = (100 × 4) + (90 × 4) +   |  |  |  | 10.  3  |  |  |  |  |  |  |  |\n| 9) | A teacher shows this partial products strategy on the board. 24 × 75 = (20 × 70) |  |  |  | 11.  16  |  |  |  |  |  |  |  |\n| 10) | + (20 × 5) + (4 × 70) + (4 × ___)\u003Cbr>A student breaks a multiplication problem into partial products. 183 × 8 = (100 × 8) + (80 × 8) + (___ × 8) |  |  |  | 12.  18  13. 54 |  |  |  |  |  |  |  |\n| 11) | Katie is using partial products to multiply. 14 × 14 = (10 × 10) + (10 × 4) + (4 × 10) +   |  |  |  | 14.  2  |  |  |  |  |  |  |  |\n| 12) | Oliver breaks a multiplication problem into partial products. 689 × 2 = (600 × 2) +(80 × 2) +   |  |  |  | 15.  4  |  |  |  |  |  |  |  |\n| 13) | 819 × 6 = (800 × 6) + (10 × 6) +   |  |  |  |  |  |  |  |  |  |  |  |\n| 14) | 15 × 62 = (10 × 60) + (10 × 2) + (5 × 60) + (5 × ___) |  |  |  |  |  |  |  |  |  |  |  |\n| 15) | 134 × 2 = (100 × 2) + (30 × 2) + (___ × 2) |  |  |  |  |  |  |  |  |  |  |  |\n|  | Math\u003Cbr>[www.CommonCoreSheets.com](www.CommonCoreSheets.com)\u003Cbr>2\u003Cbr>1-10\u003Cbr>11-15 | 93 | 87 | 80 |  | 73 | 67 | 60 | 53 | 47 | 40 | 33 |\n|  ","cbCaivklEF4jrm92","https://ap.wps.com/l/cbCaivklEF4jrm92","pdf",43593,3,"English","en",105,"# Find the number that makes each equation true\n## Partial products blanks (1-15)","[{\"question\":\"What strategy is used in these problems?\",\"answer\":\"Students use partial products to break a multiplication into sums of place-value products, then find the missing number that makes the equation true.\"},{\"question\":\"How do you determine the missing 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