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",{"@graph":14,"@context":73},[15,34,56],{"@type":16,"itemListElement":17},"BreadcrumbList",[18,23,27,31],{"item":19,"name":20,"@type":21,"position":22},"https://docshare.wps.com","Home","ListItem",1,{"item":24,"name":25,"@type":21,"position":26},"https://docshare.wps.com/document/","Document",2,{"item":28,"name":29,"@type":21,"position":30},"https://docshare.wps.com/document/exam/","Exam",3,{"item":32,"name":10,"@type":21,"position":33},"https://docshare.wps.com/document/finding-partial-products-missing-number-485428/485428/",4,{"url":32,"name":10,"@type":35,"image":36,"author":41,"headline":10,"publisher":44,"fileFormat":47,"inLanguage":8,"description":12,"dateModified":48,"datePublished":49,"encodingFormat":47,"isAccessibleForFree":50,"interactionStatistic":51},"DigitalDocument",{"url":37,"@type":38,"width":39,"height":40},"https://docshare.wps.com/thumbnails/finding-partial-products-missing-number-485428/485428.png","ImageObject",300,407,{"name":42,"@type":43},"dhado","Person",{"url":19,"name":45,"@type":46},"DocShare","Organization","application/pdf","2026-11-02","2026-09-30",true,{"@type":52,"interactionType":53,"userInteractionCount":55},"InteractionCounter",{"@type":54},"ViewAction",7,{"@type":57,"mainEntity":58},"FAQPage",[59,65,69],{"name":60,"@type":61,"acceptedAnswer":62},"What skill do students practice in this worksheet?","Question",{"text":63,"@type":64},"Students practice finding the missing number in expanded multiplication using partial products and place value.","Answer",{"name":66,"@type":61,"acceptedAnswer":67},"How do the problems work?",{"text":68,"@type":64},"Each equation rewrites a multiplication as a sum of partial products, and the student fills in the blank term(s) so the equation becomes true.",{"name":70,"@type":61,"acceptedAnswer":71},"What strategies are represented in the questions?",{"text":72,"@type":64},"The worksheet shows different approaches, including breaking factors apart by place value and combining the partial products to get the full product.","https://schema.org",{"og:url":32,"og:type":75,"og:title":10,"og:site_name":45,"og:description":12},"article",{"robots":77,"canonical":32},"index,follow",{"doc_id":79,"site_id":7},485428,1792860322,{"code":4,"msg":82,"data":83},"success",{"doc_id":79,"user_id":84,"nickname":42,"user_avatar":85,"doc_module":4,"category_id":33,"category_name":29,"doc_title":10,"doc_description":12,"doc_content":86,"file_id":87,"file_url":88,"file_type":89,"file_size":90,"view_count":55,"is_deleted":4,"is_public":22,"is_downloadable":22,"audit_status":22,"page_count":30,"language":91,"language_code":8,"site_id":7,"html_lang":8,"table_of_contents":92,"faqs":93,"seo_title":94,"seo_description":12,"update_tm":95,"read_time":96,"preview_page_count":4},5909893218464,"https://ap-avatar.wpscdn.com/davatar_085a072bc5b1113ac321206ff7593b45","Finding Partial Products (Missing Number)  \nName:  \n\n| Find the number that makes each equation true.\u003Cbr>1) Janet uses place value to break apart a multiplication problem. 762 × 8 = (700 × 8) + (60 × 8) + (___ × 8)\u003Cbr>2) Rachel is using partial products to multiply. 35 × 73 = (30 × 70) + (30 × 3) + (5 ×\u003Cbr>70) +  \u003Cbr>3) A teacher shows this partial products strategy on the board. 67 × 22 = (60 × 20)+ (60 × 2) + (7 × 20) +  \u003Cbr>4) 649 × 9 = (600 × 9) + (40 × 9) +  \u003Cbr>5) 33 × 48 = (30 × 40) + (30 × 8) + (3 × 40) +  \u003Cbr>6) A student uses place value to break apart a multiplication problem. 887 × 3 =(800 × 3) + (80 × 3) +  \u003Cbr>7) A teacher shows this partial products strategy on the board. 98 × 71 = (90 × 70)+ (90 × 1) + (8 × 70) + (8 × ___)\u003Cbr>8) Billy breaks a multiplication problem into partial products. 791 × 7 = (700 × 7) +(90 × 7) +  \u003Cbr>9) 823 × 6 = (800 × 6) + (20 × 6) + (   × 6)\u003Cbr>10) A student breaks a multiplication problem into partial products. 371 × 6 = (300 × 6) + (70 × 6) + (___ × 6)\u003Cbr>11) Frank is using partial products to multiply. 82 × 74 = (80 × 70) + (80 × 4) + (2 ×\u003Cbr>70) + (2 × ___)\u003Cbr>12) 18 × 69 = (10 × 60) + (10 × 9) + (8 × 60) + (8 ×   )\u003Cbr>13) 88 × 32 = (80 × 30) + (80 × 2) + (8 × 30) + (8 ×   )\u003Cbr>14) A teacher shows this partial products strategy on the board. 86 × 41 = (80 × 40)+ (80 × 1) + (6 × 40) + (6 × ___)\u003Cbr>15) Tom is using partial products to multiply. 25 × 55 = (20 × 50) + (20 × 5) + (5 × 50)+ (5 × ___) |  |  |  | Answers\u003Cbr>1.  \u003Cbr>2.  \u003Cbr>3.  \u003Cbr>4.  \u003Cbr>5.  \u003Cbr>6.  \u003Cbr>7.  \u003Cbr>8.  \u003Cbr>9.  \u003Cbr>10.  \u003Cbr>11.  \u003Cbr>12.  \u003Cbr>13.  \u003Cbr>14.  \u003Cbr>15.   |  |  |  |  |  |  |  |\n| --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- |\n| \u003Cbr>\u003Cbr>Math\u003Cbr>[www.CommonCoreSheets.com](www.CommonCoreSheets.com)\u003Cbr>8\u003Cbr>1-10\u003Cbr>11-15 | 93 | 87 | 80 |  | 73 | 67 | 60 | 53 | 47 | 40 | 33 |\n|  | 27 | 20 | 13 |  | 7 | 0 |  |  |  |  |  |\n\nFinding Partial Products (Missing Number)  \nName: Answer Key  \n\n| Find the number that makes each equation true.\u003Cbr>1) Janet uses place value to break apart a multiplication problem. 762 × 8 = (700 × 8) + (60 × 8) + (___ × 8) |  |  |  |  | Answers\u003Cbr>1.  2  |  |  |  |  |  |  |  |\n| --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- |\n| 2) | Rachel is using partial products to multiply. 35 × 73 = (30 × 70) + (30 × 3) + (5 × 70) +   |  |  |  | 2.  15  |  |  |  |  |  |  |  |\n| 3) | A teacher shows this partial products strategy on the board. 67 × 22 = (60 × 20)+ (60 × 2) + (7 × 20) +   |  |  |  | 3.  14  4. 81 |  |  |  |  |  |  |  |\n| 4) | 649 × 9 = (600 × 9) + (40 × 9) +   |  |  |  | 5.  24  |  |  |  |  |  |  |  |\n| 5) | 33 × 48 = (30 × 40) + (30 × 8) + (3 × 40) +   |  |  |  | 6.  21  |  |  |  |  |  |  |  |\n| 6) | A student uses place value to break apart a multiplication problem. 887 × 3 =(800 × 3) + (80 × 3) +   |  |  |  | 7.  1  8. 7 |  |  |  |  |  |  |  |\n| 7) | A teacher shows this partial products strategy on the board. 98 × 71 = (90 × 70)+ (90 × 1) + (8 × 70) + (8 × ___) |  |  |  | 9.  3  |  |  |  |  |  |  |  |\n| 8) | Billy breaks a multiplication problem into partial products. 791 × 7 = (700 × 7) +(90 × 7) +   |  |  |  | 10.  1  |  |  |  |  |  |  |  |\n| 9) | 823 × 6 = (800 × 6) + (20 × 6) + (___ × 6) |  |  |  | 11.  4  |  |  |  |  |  |  |  |\n| 10) | A student breaks a multiplication problem into partial products. 371 × 6 = (300 × 6) + (70 × 6) + (___ × 6) |  |  |  | 12.  9  13. 2 |  |  |  |  |  |  |  |\n| 11) | Frank is using partial products to multiply. 82 × 74 = (80 × 70) + (80 × 4) + (2 × 70) + (2 × ___) |  |  |  | 14.  1  |  |  |  |  |  |  |  |\n| 12) | 18 × 69 = (10 × 60) + (10 × 9) + (8 × 60) + (8 × ___) |  |  |  | 15.  5  |  |  |  |  |  |  |  |\n| 13) | 88 × 32 = (80 × 30) + (80 × 2) + (8 × 30) + (8 × ___) |  |  |  |  |  |  |  |  |  |  |  |\n| 14) | A teacher shows this partial products strategy on the board. 86 × 41 = (80 × 40)+ (80 × 1) + (6 × 40) + (6 × ___) |  |  |  |  |  |  |  |  |  |  |  |\n| 15) | Tom is using partial pr","cbCaior8b2X6dqix","https://ap.wps.com/l/cbCaior8b2X6dqix","pdf",43730,"English","# Finding Partial Products (Missing Number)\n## Missing addends in expanded multiplication equations","[{\"question\":\"What skill do students practice in this worksheet?\",\"answer\":\"Students practice finding the missing number in expanded multiplication using partial products and place value.\"},{\"question\":\"How do the problems work?\",\"answer\":\"Each equation rewrites a multiplication as a sum of partial products, and the student fills in the blank term(s) so the equation becomes true.\"},{\"question\":\"What strategies are represented in the questions?\",\"answer\":\"The worksheet shows different approaches, including breaking factors apart by place value and combining the partial products to get the full product.\"}]","Finding Partial Products (Missing Number) | 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