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true.\u003Cbr>1) A teacher shows this partial products strategy on the board. 35 × 31 = (30 × 30)+ (30 × 1) + (5 × 30) + (5 × ___)\u003Cbr>2) Lana uses place value to break apart a multiplication problem. 783 × 3 = (700 ×\u003Cbr>3) + (80 × 3) + (___ × 3)\u003Cbr>3) A student breaks a multiplication problem into partial products. 159 × 5 = (100 × 5) + (50 × 5) + (___ × 5)\u003Cbr>4) A student uses place value to break apart a multiplication problem. 674 × 6 =(600 × 6) + (70 × 6) +  \u003Cbr>5) Adam is using partial products to multiply. 12 × 38 = (10 × 30) + (10 × 8) + (2 × 30) + (2 × ___)\u003Cbr>6) 94 × 34 = (90 × 30) + (90 × 4) + (4 × 30) + (4 ×   )\u003Cbr>7) 769 × 7 = (700 × 7) + (60 × 7) +  \u003Cbr>8) 821 × 4 = (800 × 4) + (20 × 4) + (   × 4)\u003Cbr>9) Paul breaks a multiplication problem into partial products. 853 × 5 = (800 × 5) +(50 × 5) +  \u003Cbr>10) 88 × 97 = (80 × 90) + (80 × 7) + (8 × 90) +  \u003Cbr>11) A teacher shows this partial products strategy on the board. 26 × 31 = (20 × 30)+ (20 × 1) + (6 × 30) +  \u003Cbr>12) Nancy is using partial products to multiply. 63 × 89 = (60 × 80) + (60 × 9) + (3 ×\u003Cbr>80) +  \u003Cbr>13) 66 × 32 = (60 × 30) + (60 × 2) + (6 × 30) +  \u003Cbr>14) A student breaks a multiplication problem into partial products. 197 × 6 = (100 × 6) + (90 × 6) + (___ × 6)\u003Cbr>15) A teacher shows this partial products strategy on the board. 52 × 23 = (50 × 20)+ (50 × 3) + (2 × 20) +   |  |  |  | Answers\u003Cbr>1.  \u003Cbr>2.  \u003Cbr>3.  \u003Cbr>4.  \u003Cbr>5.  \u003Cbr>6.  \u003Cbr>7.  \u003Cbr>8.  \u003Cbr>9.  \u003Cbr>10.  \u003Cbr>11.  \u003Cbr>12.  \u003Cbr>13.  \u003Cbr>14.  \u003Cbr>15.   |  |  |  |  |  |  |  |\n| --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- |\n| \u003Cbr>\u003Cbr>Math\u003Cbr>[www.CommonCoreSheets.com](www.CommonCoreSheets.com)\u003Cbr>7\u003Cbr>1-10\u003Cbr>11-15 | 93 | 87 | 80 |  | 73 | 67 | 60 | 53 | 47 | 40 | 33 |\n|  | 27 | 20 | 13 |  | 7 | 0 |  |  |  |  |  |\n\nFinding Partial Products (Missing Number)  \nName: Answer Key  \n\n| Find the number that makes each equation true.\u003Cbr>1) A teacher shows this partial products strategy on the board. 35 × 31 = (30 × 30)+ (30 × 1) + (5 × 30) + (5 × ___) |  |  |  |  | Answers\u003Cbr>1.  1  |  |  |  |  |  |  |  |\n| --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- |\n| 2) | Lana uses place value to break apart a multiplication problem. 783 × 3 = (700 × 3) + (80 × 3) + (___ × 3) |  |  |  | 2.  3  |  |  |  |  |  |  |  |\n| 3) | A student breaks a multiplication problem into partial products. 159 × 5 = (100 × 5) + (50 × 5) + (___ × 5) |  |  |  | 3.  9  4. 24 |  |  |  |  |  |  |  |\n| 4) | A student uses place value to break apart a multiplication problem. 674 × 6 =(600 × 6) + (70 × 6) +   |  |  |  | 5.  8  |  |  |  |  |  |  |  |\n| 5) | Adam is using partial products to multiply. 12 × 38 = (10 × 30) + (10 × 8) + (2 × 30) + (2 × ___) |  |  |  | 6.  4  |  |  |  |  |  |  |  |\n| 6) | 94 × 34 = (90 × 30) + (90 × 4) + (4 × 30) + (4 × ___) |  |  |  | 7.  63  |  |  |  |  |  |  |  |\n| 7) | 769 × 7 = (700 × 7) + (60 × 7) +   |  |  |  | 8.  1  9.  15  |  |  |  |  |  |  |  |\n| 8) | 821 × 4 = (800 × 4) + (20 × 4) + (   × 4) |  |  |  | 10.  56  |  |  |  |  |  |  |  |\n| 9) | Paul breaks a multiplication problem into partial products. 853 × 5 = (800 × 5) +(50 × 5) +   |  |  |  | 11.  6  12. 27 |  |  |  |  |  |  |  |\n| 10) | 88 × 97 = (80 × 90) + (80 × 7) + (8 × 90) +   |  |  |  | 13. 12 |  |  |  |  |  |  |  |\n| 11) | A teacher shows this partial products strategy on the board. 26 × 31 = (20 × 30)+ (20 × 1) + (6 × 30) +   |  |  |  | 14.  7  |  |  |  |  |  |  |  |\n| 12) | Nancy is using partial products to multiply. 63 × 89 = (60 × 80) + (60 × 9) + (3 × 80) +   |  |  |  | 15.  6  |  |  |  |  |  |  |  |\n| 13) | 66 × 32 = (60 × 30) + (60 × 2) + (6 × 30) +   |  |  |  |  |  |  |  |  |  |  |  |\n| 14) | A student breaks a multiplication problem into partial products. 197 × 6 = (100 × 6) + (90 × 6) + (___ × 6) |  |  |  |  |  |  |  |  |  |  |  |\n| 15) | A teacher shows this partial products strategy o","cbCaiodLUWnZOCMv","https://ap.wps.com/l/cbCaiodLUWnZOCMv","pdf",43666,"English","# Finding Partial Products (Missing Number)\n## Student Problems (1-15)\n## Answer Key","[{\"question\":\"What does “partial products” mean in these problems?\",\"answer\":\"It means breaking a multiplication into smaller place-value multiplications (like tens and ones), then adding the partial results.\"},{\"question\":\"How do you find the missing number in each equation?\",\"answer\":\"Compute each required partial product using the given numbers, then choose the value that makes the full multiplication equation true.\"},{\"question\":\"Why do some problems mention place value?\",\"answer\":\"Place value cues how to split the factors (e.g., hundreds, tens, ones) so the partial products align with the structure of the equation.\"}]","Finding Partial Products - Missing Number | PDF",1790804204]