[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"detail-sidebar-cat-0-en-105":3,"doc-seo-485423-105":59,"doc-detail-485423-en":130},{"code":4,"msg":5,"data":6},0,"success",[7,13,18,23,28,33,38,43,48,51,55],{"id":8,"doc_module":4,"doc_module_name":9,"category_name":10,"show_sort_weight":11,"slug":12},1,"Document","Story & Novel",90,"story-novel",{"id":14,"doc_module":4,"doc_module_name":9,"category_name":15,"show_sort_weight":16,"slug":17},2,"Literature",80,"literature",{"id":19,"doc_module":4,"doc_module_name":9,"category_name":20,"show_sort_weight":21,"slug":22},4,"Exam",70,"exam",{"id":24,"doc_module":4,"doc_module_name":9,"category_name":25,"show_sort_weight":26,"slug":27},5,"Comic",60,"comic",{"id":29,"doc_module":4,"doc_module_name":9,"category_name":30,"show_sort_weight":31,"slug":32},6,"Technology",50,"technology",{"id":34,"doc_module":4,"doc_module_name":9,"category_name":35,"show_sort_weight":36,"slug":37},7,"Healthcare",40,"healthcare",{"id":39,"doc_module":4,"doc_module_name":9,"category_name":40,"show_sort_weight":41,"slug":42},8,"Research & Report",30,"research-report",{"id":44,"doc_module":4,"doc_module_name":9,"category_name":45,"show_sort_weight":46,"slug":47},9,"Religion & Spirituality",20,"religion-spirituality",{"id":46,"doc_module":4,"doc_module_name":9,"category_name":49,"show_sort_weight":46,"slug":50},"World Cup","world-cup",{"id":52,"doc_module":4,"doc_module_name":9,"category_name":53,"show_sort_weight":52,"slug":54},10,"Lifestyle","lifestyle",{"id":56,"doc_module":4,"doc_module_name":9,"category_name":57,"show_sort_weight":24,"slug":58},19,"General","general",{"code":4,"msg":60,"data":61},"ok",{"site_id":62,"language":63,"slug":64,"title":65,"keywords":66,"description":67,"schema_data":68,"social_meta":123,"head_meta":125,"extra_data":127,"updated_unix":129},105,"en","finding-partial-products-missing-number-485423","Finding Partial Products (Missing Number)","","Worksheet on finding missing numbers in multiplication equations using the partial products method and place value decomposition. Each item presents a multiplication problem rewritten as a sum of partial products with one or more terms replaced by blanks, and requires determining the value that makes the equation true. Includes a separate answer key listing the correct missing numbers for problems 1–15, supporting stepwise breakdown of factors into tens and 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does each problem ask you to do?","Question",{"text":112,"@type":113},"Find the number that makes each multiplication equation true by filling in the missing value in the partial products expression.","Answer",{"name":115,"@type":110,"acceptedAnswer":116},"Which strategies are used in the worksheet?",{"text":117,"@type":113},"It uses partial products and place value to break multiplication into sums of tens and ones products.",{"name":119,"@type":110,"acceptedAnswer":120},"Where can the correct answers be found?",{"text":121,"@type":113},"The document includes an answer key that lists the missing numbers for problems 1 through 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×   )\u003Cbr>2) A student breaks a multiplication problem into partial products. 531 × 4 = (500 × 4) + (30 × 4) + (___ × 4)\u003Cbr>3) Henry breaks a multiplication problem into partial products. 761 × 5 = (700 × 5)+ (60 × 5) +  \u003Cbr>4) Debby is using partial products to multiply. 19 × 73 = (10 × 70) + (10 × 3) + (9 ×\u003Cbr>70) +  \u003Cbr>5) A student uses place value to break apart a multiplication problem. 566 × 7 =(500 × 7) + (60 × 7) +  \u003Cbr>6) 42 × 75 = (40 × 70) + (40 × 5) + (2 × 70) +  \u003Cbr>7) Cody is using partial products to multiply. 15 × 42 = (10 × 40) + (10 × 2) + (5 ×\u003Cbr>40) + (5 × ___)\u003Cbr>8) 596 × 5 = (500 × 5) + (90 × 5) +  \u003Cbr>9) Paige uses place value to break apart a multiplication problem. 386 × 5 = (300 ×\u003Cbr>5) + (80 × 5) + (___ × 5)\u003Cbr>10) A teacher shows this partial products strategy on the board. 39 × 85 = (30 × 80)+ (30 × 5) + (9 × 80) +  \u003Cbr>11) 327 × 5 = (300 × 5) + (20 × 5) + (   × 5)\u003Cbr>12) A teacher shows this partial products strategy on the board. 76 × 41 = (70 × 40)+ (70 × 1) + (6 × 40) + (6 × ___)\u003Cbr>13) A teacher shows this partial products strategy on the board. 94 × 96 = (90 × 90)+ (90 × 6) + (4 × 90) +  \u003Cbr>14) Will is using partial products to multiply. 43 × 14 = (40 × 10) + (40 × 4) + (3 × 10)+ (3 × ___)\u003Cbr>15) 75 × 86 = (70 × 80) + (70 × 6) + (5 × 80) + (5 ×   ) |  |  |  | Answers\u003Cbr>1.  \u003Cbr>2.  \u003Cbr>3.  \u003Cbr>4.  \u003Cbr>5.  \u003Cbr>6.  \u003Cbr>7.  \u003Cbr>8.  \u003Cbr>9.  \u003Cbr>10.  \u003Cbr>11.  \u003Cbr>12.  \u003Cbr>13.  \u003Cbr>14.  \u003Cbr>15.   |  |  |  |  |  |  |  |\n| --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- |\n| \u003Cbr>\u003Cbr>Math\u003Cbr>[www.CommonCoreSheets.com](www.CommonCoreSheets.com)\u003Cbr>4\u003Cbr>1-10\u003Cbr>11-15 | 93 | 87 | 80 |  | 73 | 67 | 60 | 53 | 47 | 40 | 33 |\n|  | 27 | 20 | 13 |  | 7 | 0 |  |  |  |  |  |\n\nFinding Partial Products (Missing Number)  \nName: Answer Key  \n\n| Find the number that makes each equation true.\u003Cbr>1) 91 × 93 = (90 × 90) + (90 × 3) + (1 × 90) + (1 ×   ) |  |  |  |  | Answers\u003Cbr>1.  3  |  |  |  |  |  |  |  |\n| --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- |\n| 2) | A student breaks a multiplication problem into partial products. 531 × 4 = (500 × 4) + (30 × 4) + (___ × 4) |  |  |  | 2.  1  |  |  |  |  |  |  |  |\n| 3) | Henry breaks a multiplication problem into partial products. 761 × 5 = (700 × 5)+ (60 × 5) +   |  |  |  | 3.  5  4. 27 |  |  |  |  |  |  |  |\n| 4) | Debby is using partial products to multiply. 19 × 73 = (10 × 70) + (10 × 3) + (9 × 70) +   |  |  |  | 5.  42  |  |  |  |  |  |  |  |\n| 5) | A student uses place value to break apart a multiplication problem. 566 × 7 =(500 × 7) + (60 × 7) +   |  |  |  | 6.  10  |  |  |  |  |  |  |  |\n| 6) | 42 × 75 = (40 × 70) + (40 × 5) + (2 × 70) +   |  |  |  | 7.  2  |  |  |  |  |  |  |  |\n| 7) | Cody is using partial products to multiply. 15 × 42 = (10 × 40) + (10 × 2) + (5 × 40) + (5 × ___) |  |  |  | 8.  30  9.  6  |  |  |  |  |  |  |  |\n| 8) | 596 × 5 = (500 × 5) + (90 × 5) +   |  |  |  | 10.  45  |  |  |  |  |  |  |  |\n| 9) | Paige uses place value to break apart a multiplication problem. 386 × 5 = (300 × 5) + (80 × 5) + (___ × 5) |  |  |  | 11.  7  |  |  |  |  |  |  |  |\n| 10) | A teacher shows this partial products strategy on the board. 39 × 85 = (30 × 80)+ (30 × 5) + (9 × 80) +   |  |  |  | 12.  1  13. 24 |  |  |  |  |  |  |  |\n| 11) | 327 × 5 = (300 × 5) + (20 × 5) + (___ × 5) |  |  |  | 14.  4  |  |  |  |  |  |  |  |\n| 12) | A teacher shows this partial products strategy on the board. 76 × 41 = (70 × 40)+ (70 × 1) + (6 × 40) + (6 × ___) |  |  |  | 15.  6  |  |  |  |  |  |  |  |\n| 13) | A teacher shows this partial products strategy on the board. 94 × 96 = (90 × 90)+ (90 × 6) + (4 × 90) +   |  |  |  |  |  |  |  |  |  |  |  |\n| 14) | Will is using partial products to multiply. 43 × 14 = (40 × 10) + (40 × 4) + (3 × 10)+ (3 × ___) |  |  |  |  |  |  |  |  |  |  |  |\n| ","cbCain3lclnfSAEd","https://ap.wps.com/l/cbCain3lclnfSAEd","pdf",43735,"English","# Finding Partial Products (Missing Number)\n## Practice Problems (1-15)\n## Answer Key","[{\"question\":\"What does each problem ask you to do?\",\"answer\":\"Find the number that makes each multiplication equation true by filling in the missing value in the partial products expression.\"},{\"question\":\"Which strategies are used in the worksheet?\",\"answer\":\"It uses partial products and place value to break multiplication into sums of tens and ones products.\"},{\"question\":\"Where can the correct answers be found?\",\"answer\":\"The document includes an answer key that lists the missing numbers for problems 1 through 15.\"}]","Finding Partial Products (Missing Number) | PDF",1790804195]