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Each item asks learners to determine the unknown addend so the expanded multiplication is correct, e.g., breaking factors into tens and ones components such as (50 × 30), (50 × 8), and (3 × ___). 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The document includes an answer key that provides the missing number for each of the 15 problems.","https://schema.org",{"og:url":83,"og:type":124,"og:title":65,"og:site_name":95,"og:description":67},"article",{"robots":126,"canonical":83},"index,follow",{"doc_id":128,"site_id":62},485422,1792874552,{"code":4,"msg":5,"data":131},{"doc_id":128,"user_id":132,"nickname":92,"user_avatar":133,"doc_module":4,"category_id":19,"category_name":20,"doc_title":65,"doc_description":67,"doc_content":134,"file_id":135,"file_url":136,"file_type":137,"file_size":138,"view_count":29,"is_deleted":4,"is_public":8,"is_downloadable":8,"audit_status":8,"page_count":81,"language":139,"language_code":63,"site_id":62,"html_lang":63,"table_of_contents":140,"faqs":141,"seo_title":142,"seo_description":67,"update_tm":143,"read_time":39,"preview_page_count":4},5909893218464,"https://ap-avatar.wpscdn.com/davatar_085a072bc5b1113ac321206ff7593b45","Finding Partial Products (Missing Number)  \nName:  \n\n| Find the number that makes each equation true.\u003Cbr>1) John is using partial products to multiply. 53 × 38 = (50 × 30) + (50 × 8) + (3 × 30) + (3 × ___)\u003Cbr>2) Olivia uses place value to break apart a multiplication problem. 652 × 3 = (600 ×\u003Cbr>3) + (50 × 3) + (___ × 3)\u003Cbr>3) 25 × 26 = (20 × 20) + (20 × 6) + (5 × 20) +  \u003Cbr>4) A teacher shows this partial products strategy on the board. 79 × 93 = (70 × 90)+ (70 × 3) + (9 × 90) +  \u003Cbr>5) 522 × 7 = (500 × 7) + (20 × 7) +  \u003Cbr>6) A teacher shows this partial products strategy on the board. 47 × 89 = (40 × 80)+ (40 × 9) + (7 × 80) + (7 × ___)\u003Cbr>7) Maria is using partial products to multiply. 53 × 68 = (50 × 60) + (50 × 8) + (3 ×\u003Cbr>60) +  \u003Cbr>8) 958 × 9 = (900 × 9) + (50 × 9) + (   × 9)\u003Cbr>9) Will breaks a multiplication problem into partial products. 882 × 4 = (800 × 4) +(80 × 4) +  \u003Cbr>10) A student uses place value to break apart a multiplication problem. 528 × 3 =(500 × 3) + (20 × 3) +  \u003Cbr>11) 22 × 44 = (20 × 40) + (20 × 4) + (2 × 40) + (2 ×   )\u003Cbr>12) A student breaks a multiplication problem into partial products. 526 × 9 = (500 × 9) + (20 × 9) + (___ × 9)\u003Cbr>13) A student uses place value to break apart a multiplication problem. 715 × 7 =(700 × 7) + (10 × 7) +  \u003Cbr>14) A teacher shows this partial products strategy on the board. 73 × 24 = (70 × 20)+ (70 × 4) + (3 × 20) +  \u003Cbr>15) Gwen uses place value to break apart a multiplication problem. 768 × 3 = (700 ×\u003Cbr>3) + (60 × 3) + (___ × 3) |  |  |  | Answers\u003Cbr>1.  \u003Cbr>2.  \u003Cbr>3.  \u003Cbr>4.  \u003Cbr>5.  \u003Cbr>6.  \u003Cbr>7.  \u003Cbr>8.  \u003Cbr>9.  \u003Cbr>10.  \u003Cbr>11.  \u003Cbr>12.  \u003Cbr>13.  \u003Cbr>14.  \u003Cbr>15.   |  |  |  |  |  |  |  |\n| --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- |\n| \u003Cbr>\u003Cbr>Math\u003Cbr>[www.CommonCoreSheets.com](www.CommonCoreSheets.com)\u003Cbr>3\u003Cbr>1-10\u003Cbr>11-15 | 93 | 87 | 80 |  | 73 | 67 | 60 | 53 | 47 | 40 | 33 |\n|  | 27 | 20 | 13 |  | 7 | 0 |  |  |  |  |  |\n\nFinding Partial Products (Missing Number)  \nName: Answer Key  \n\n| Find the number that makes each equation true.\u003Cbr>1) John is using partial products to multiply. 53 × 38 = (50 × 30) + (50 × 8) + (3 × 30) + (3 × ___) |  |  |  |  | Answers\u003Cbr>1.  8  |  |  |  |  |  |  |  |\n| --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- |\n| 2) | Olivia uses place value to break apart a multiplication problem. 652 × 3 = (600 × 3) + (50 × 3) + (___ × 3) |  |  |  | 2.  2  |  |  |  |  |  |  |  |\n| 3) | 25 × 26 = (20 × 20) + (20 × 6) + (5 × 20) +   |  |  |  | 3.  30  |  |  |  |  |  |  |  |\n| 4) | A teacher shows this partial products strategy on the board. 79 × 93 = (70 × 90)+ (70 × 3) + (9 × 90) +   |  |  |  | 4.  27  5.  14  |  |  |  |  |  |  |  |\n| 5) | 522 × 7 = (500 × 7) + (20 × 7) +   |  |  |  | 6.  9  |  |  |  |  |  |  |  |\n| 6) | A teacher shows this partial products strategy on the board. 47 × 89 = (40 × 80)+ (40 × 9) + (7 × 80) + (7 × ___) |  |  |  | 7.  24  8. 8 |  |  |  |  |  |  |  |\n| 7) | Maria is using partial products to multiply. 53 × 68 = (50 × 60) + (50 × 8) + (3 × 60) +   |  |  |  | 9.  8  |  |  |  |  |  |  |  |\n| 8) | 958 × 9 = (900 × 9) + (50 × 9) + (___ × 9) |  |  |  | 10.  24  |  |  |  |  |  |  |  |\n| 9) | Will breaks a multiplication problem into partial products. 882 × 4 = (800 × 4) + |  |  |  | 11.  4  |  |  |  |  |  |  |  |\n| 10) | (80 × 4) +  \u003Cbr>A student uses place value to break apart a multiplication problem. 528 × 3 =(500 × 3) + (20 × 3) +   |  |  |  | 12.  6  13. 35 |  |  |  |  |  |  |  |\n| 11) | 22 × 44 = (20 × 40) + (20 × 4) + (2 × 40) + (2 × ___) |  |  |  | 14.  12  |  |  |  |  |  |  |  |\n| 12) | A student breaks a multiplication problem into partial products. 526 × 9 = (500 × 9) + (20 × 9) + (___ × 9) |  |  |  | 15.  8  |  |  |  |  |  |  |  |\n| 13) | A student uses place value to break apart a multiplication problem. 715 × 7 =(700 × 7) + (10 × 7) +   |  |  |  |  |  |  |  |  |  |  |  |\n| 14) | A teacher shows this partial products strategy on the board. 73 × 24 = (70","cbCaitqR7wlgsfe8","https://ap.wps.com/l/cbCaitqR7wlgsfe8","pdf",43663,"English","# Find the number that makes each equation true","[{\"question\":\"What is the skill practiced in this worksheet?\",\"answer\":\"Students practice finding missing numbers in multiplication using partial products and place value to complete expanded equations.\"},{\"question\":\"How do the problems show multiplication?\",\"answer\":\"Each multiplication is rewritten as a sum of partial products, with one term replaced by a blank to solve.\"},{\"question\":\"Is there an answer key for the worksheet?\",\"answer\":\"Yes. The document includes an answer key that provides the missing number for each of the 15 problems.\"}]","Finding Partial Products (Missing Number) | PDF",1790804194]