[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"detail-sidebar-cat-0-en-105":3,"doc-seo-485420-105":59,"doc-detail-485420-en":130},{"code":4,"msg":5,"data":6},0,"success",[7,13,18,23,28,33,38,43,48,51,55],{"id":8,"doc_module":4,"doc_module_name":9,"category_name":10,"show_sort_weight":11,"slug":12},1,"Document","Story & Novel",90,"story-novel",{"id":14,"doc_module":4,"doc_module_name":9,"category_name":15,"show_sort_weight":16,"slug":17},2,"Literature",80,"literature",{"id":19,"doc_module":4,"doc_module_name":9,"category_name":20,"show_sort_weight":21,"slug":22},4,"Exam",70,"exam",{"id":24,"doc_module":4,"doc_module_name":9,"category_name":25,"show_sort_weight":26,"slug":27},5,"Comic",60,"comic",{"id":29,"doc_module":4,"doc_module_name":9,"category_name":30,"show_sort_weight":31,"slug":32},6,"Technology",50,"technology",{"id":34,"doc_module":4,"doc_module_name":9,"category_name":35,"show_sort_weight":36,"slug":37},7,"Healthcare",40,"healthcare",{"id":39,"doc_module":4,"doc_module_name":9,"category_name":40,"show_sort_weight":41,"slug":42},8,"Research & Report",30,"research-report",{"id":44,"doc_module":4,"doc_module_name":9,"category_name":45,"show_sort_weight":46,"slug":47},9,"Religion & Spirituality",20,"religion-spirituality",{"id":46,"doc_module":4,"doc_module_name":9,"category_name":49,"show_sort_weight":46,"slug":50},"World Cup","world-cup",{"id":52,"doc_module":4,"doc_module_name":9,"category_name":53,"show_sort_weight":52,"slug":54},10,"Lifestyle","lifestyle",{"id":56,"doc_module":4,"doc_module_name":9,"category_name":57,"show_sort_weight":24,"slug":58},19,"General","general",{"code":4,"msg":60,"data":61},"ok",{"site_id":62,"language":63,"slug":64,"title":65,"keywords":66,"description":67,"schema_data":68,"social_meta":123,"head_meta":125,"extra_data":127,"updated_unix":129},105,"en","finding-partial-products-missing-number-485420","Finding Partial Products (Missing Number)","","Worksheet focused on finding missing factors in multiplication equations using partial products and place value strategies. Students complete fifteen problems by rewriting each product as a sum of partial products such as tens-times and ones-times components, then fill in the blank factor that makes the equation true. 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The blank is the factor that completes the corresponding partial product.",{"name":119,"@type":110,"acceptedAnswer":120},"Is there an answer key for checking?",{"text":121,"@type":113},"Yes. The document includes a separate “Answer Key” section listing the missing numbers for each problem from 1 to 15.","https://schema.org",{"og:url":83,"og:type":124,"og:title":65,"og:site_name":95,"og:description":67},"article",{"robots":126,"canonical":83},"index,follow",{"doc_id":128,"site_id":62},485420,1790884169,{"code":4,"msg":5,"data":131},{"doc_id":128,"user_id":132,"nickname":92,"user_avatar":133,"doc_module":4,"category_id":19,"category_name":20,"doc_title":65,"doc_description":67,"doc_content":134,"file_id":135,"file_url":136,"file_type":137,"file_size":138,"view_count":34,"is_deleted":4,"is_public":8,"is_downloadable":8,"audit_status":8,"page_count":81,"language":139,"language_code":63,"site_id":62,"html_lang":63,"table_of_contents":140,"faqs":141,"seo_title":142,"seo_description":67,"update_tm":143,"read_time":39,"preview_page_count":4},5909893218464,"https://ap-avatar.wpscdn.com/davatar_085a072bc5b1113ac321206ff7593b45","Finding Partial Products (Missing Number)  \nName:  \n\n| Find the number that makes each equation true.\u003Cbr>1) Tiffany is using partial products to multiply. 54 × 25 = (50 × 20) + (50 × 5) + (4 × 20) +  \u003Cbr>2) 14 × 46 = (10 × 40) + (10 × 6) + (4 × 40) +  \u003Cbr>3) 34 × 24 = (30 × 20) + (30 × 4) + (4 × 20) + (4 ×   )\u003Cbr>4) Edward is using partial products to multiply. 45 × 67 = (40 × 60) + (40 × 7) + (5 ×\u003Cbr>60) + (5 × ___)\u003Cbr>5) Rachel uses place value to break apart a multiplication problem. 394 × 2 = (300 × 2) + (90 × 2) + (___ × 2)\u003Cbr>6) A teacher shows this partial products strategy on the board. 15 × 39 = (10 × 30)+ (10 × 9) + (5 × 30) + (5 × ___)\u003Cbr>7) 911 × 3 = (900 × 3) + (10 × 3) +  \u003Cbr>8) A student uses place value to break apart a multiplication problem. 728 × 3 =(700 × 3) + (20 × 3) +  \u003Cbr>9) Ned breaks a multiplication problem into partial products. 744 × 7 = (700 × 7) +(40 × 7) +  \u003Cbr>10) 467 × 7 = (400 × 7) + (60 × 7) + (   × 7)\u003Cbr>11) A teacher shows this partial products strategy on the board. 54 × 52 = (50 × 50)+ (50 × 2) + (4 × 50) +  \u003Cbr>12) A student breaks a multiplication problem into partial products. 153 × 6 = (100 × 6) + (50 × 6) + (___ × 6)\u003Cbr>13) Debby uses place value to break apart a multiplication problem. 433 × 7 = (400 ×\u003Cbr>7) + (30 × 7) + (___ × 7)\u003Cbr>14) A student uses place value to break apart a multiplication problem. 714 × 5 =(700 × 5) + (10 × 5) +  \u003Cbr>15) Jerry is using partial products to multiply. 44 × 47 = (40 × 40) + (40 × 7) + (4 × 40) + (4 × ___) |  |  |  | Answers\u003Cbr>1.  \u003Cbr>2.  \u003Cbr>3.  \u003Cbr>4.  \u003Cbr>5.  \u003Cbr>6.  \u003Cbr>7.  \u003Cbr>8.  \u003Cbr>9.  \u003Cbr>10.  \u003Cbr>11.  \u003Cbr>12.  \u003Cbr>13.  \u003Cbr>14.  \u003Cbr>15.   |  |  |  |  |  |  |  |\n| --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- |\n| \u003Cbr>\u003Cbr>Math\u003Cbr>[www.CommonCoreSheets.com](www.CommonCoreSheets.com)\u003Cbr>1-10\u003Cbr>11-15 | 93 | 87 | 80 |  | 73 | 67 | 60 | 53 | 47 | 40 | 33 |\n|  | 27 | 20 | 13 |  | 7 | 0 |  |  |  |  |  |\n\nFinding Partial Products (Missing Number)  \nName: Answer Key  \n\n| Find the number that makes each equation true.\u003Cbr>1) Tiffany is using partial products to multiply. 54 × 25 = (50 × 20) + (50 × 5) + (4 × 20) +   |  |  |  |  | Answers\u003Cbr>1.  20  |  |  |  |  |  |  |  |\n| --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- |\n| 2) | 14 × 46 = (10 × 40) + (10 × 6) + (4 × 40) +   |  |  |  | 2.  24  |  |  |  |  |  |  |  |\n| 3) | 34 × 24 = (30 × 20) + (30 × 4) + (4 × 20) + (4 × ___) |  |  |  | 3.  4  |  |  |  |  |  |  |  |\n| 4) | Edward is using partial products to multiply. 45 × 67 = (40 × 60) + (40 × 7) + (5 × 60) + (5 × ___) |  |  |  | 4.  7  5.  4  |  |  |  |  |  |  |  |\n| 5) | Rachel uses place value to break apart a multiplication problem. 394 × 2 = (300 × 2) + (90 × 2) + (___ × 2) |  |  |  | 6.  9  |  |  |  |  |  |  |  |\n| 6) | A teacher shows this partial products strategy on the board. 15 × 39 = (10 × 30)+ (10 × 9) + (5 × 30) + (5 × ___) |  |  |  | 7.  3  8. 24 |  |  |  |  |  |  |  |\n| 7) | 911 × 3 = (900 × 3) + (10 × 3) +   |  |  |  | 9.  28  |  |  |  |  |  |  |  |\n| 8) | A student uses place value to break apart a multiplication problem. 728 × 3 =(700 × 3) + (20 × 3) +   |  |  |  | 10.  7  |  |  |  |  |  |  |  |\n| 9) | Ned breaks a multiplication problem into partial products. 744 × 7 = (700 × 7) +(40 × 7) +   |  |  |  | 11.  8  12. 3 |  |  |  |  |  |  |  |\n| 10) | 467 × 7 = (400 × 7) + (60 × 7) + (___ × 7) |  |  |  | 13. 3 |  |  |  |  |  |  |  |\n| 11) | A teacher shows this partial products strategy on the board. 54 × 52 = (50 × 50)+ (50 × 2) + (4 × 50) +   |  |  |  | 14.  20  |  |  |  |  |  |  |  |\n| 12) | A student breaks a multiplication problem into partial products. 153 × 6 = (100 × 6) + (50 × 6) + (___ × 6) |  |  |  | 15.  7  |  |  |  |  |  |  |  |\n| 13) | Debby uses place value to break apart a multiplication problem. 433 × 7 = (400 × 7) + (30 × 7) + (___ × 7) |  |  |  |  |  |  |  |  |  |  |  |\n| 14) | A student uses place value to break apart a multiplication problem. 714 × 5 =(700 × 5","cbCaiqclnDMpxBHe","https://ap.wps.com/l/cbCaiqclnDMpxBHe","pdf",43660,"English","# Practice Problems\n## Partial Products and Place Value Decomposition","[{\"question\":\"What skill do these problems practice?\",\"answer\":\"They practice writing multiplication using partial products and place value, then finding the missing number that completes each equation.\"},{\"question\":\"How do partial products help solve the equations?\",\"answer\":\"Students break a multiplication problem into a sum of products (for example, tens-part plus ones-part). The blank is the factor that completes the corresponding partial product.\"},{\"question\":\"Is there an answer key for checking?\",\"answer\":\"Yes. The document includes a separate “Answer Key” section listing the missing numbers for each problem from 1 to 15.\"}]","Finding Partial Products (Missing Number) | PDF",1790804193]