[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"detail-sidebar-cat-0-en-105":3,"doc-seo-485419-105":59,"doc-detail-485419-en":130},{"code":4,"msg":5,"data":6},0,"success",[7,13,18,23,28,33,38,43,48,51,55],{"id":8,"doc_module":4,"doc_module_name":9,"category_name":10,"show_sort_weight":11,"slug":12},1,"Document","Story & Novel",90,"story-novel",{"id":14,"doc_module":4,"doc_module_name":9,"category_name":15,"show_sort_weight":16,"slug":17},2,"Literature",80,"literature",{"id":19,"doc_module":4,"doc_module_name":9,"category_name":20,"show_sort_weight":21,"slug":22},4,"Exam",70,"exam",{"id":24,"doc_module":4,"doc_module_name":9,"category_name":25,"show_sort_weight":26,"slug":27},5,"Comic",60,"comic",{"id":29,"doc_module":4,"doc_module_name":9,"category_name":30,"show_sort_weight":31,"slug":32},6,"Technology",50,"technology",{"id":34,"doc_module":4,"doc_module_name":9,"category_name":35,"show_sort_weight":36,"slug":37},7,"Healthcare",40,"healthcare",{"id":39,"doc_module":4,"doc_module_name":9,"category_name":40,"show_sort_weight":41,"slug":42},8,"Research & Report",30,"research-report",{"id":44,"doc_module":4,"doc_module_name":9,"category_name":45,"show_sort_weight":46,"slug":47},9,"Religion & Spirituality",20,"religion-spirituality",{"id":46,"doc_module":4,"doc_module_name":9,"category_name":49,"show_sort_weight":46,"slug":50},"World Cup","world-cup",{"id":52,"doc_module":4,"doc_module_name":9,"category_name":53,"show_sort_weight":52,"slug":54},10,"Lifestyle","lifestyle",{"id":56,"doc_module":4,"doc_module_name":9,"category_name":57,"show_sort_weight":24,"slug":58},19,"General","general",{"code":4,"msg":60,"data":61},"ok",{"site_id":62,"language":63,"slug":64,"title":65,"keywords":66,"description":67,"schema_data":68,"social_meta":123,"head_meta":125,"extra_data":127,"updated_unix":129},105,"en","finding-partial-products-missing-number-485419","Finding Partial Products (Missing Number)","","Worksheet and answer key focused on finding missing numbers in multiplication equations using partial products and place value. Each item guides students to decompose factors into tens and ones (or hundreds, tens, ones), compute partial products, and identify the number that makes the final expanded sum correct. Scenarios describe teacher or student strategies, such as breaking multiplications into addable components to complete the missing factor 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product.","https://schema.org",{"og:url":83,"og:type":124,"og:title":65,"og:site_name":95,"og:description":67},"article",{"robots":126,"canonical":83},"index,follow",{"doc_id":128,"site_id":62},485419,1791300612,{"code":4,"msg":5,"data":131},{"doc_id":128,"user_id":132,"nickname":92,"user_avatar":133,"doc_module":4,"category_id":19,"category_name":20,"doc_title":65,"doc_description":67,"doc_content":134,"file_id":135,"file_url":136,"file_type":137,"file_size":138,"view_count":29,"is_deleted":4,"is_public":8,"is_downloadable":8,"audit_status":8,"page_count":41,"language":139,"language_code":63,"site_id":62,"html_lang":63,"table_of_contents":140,"faqs":141,"seo_title":142,"seo_description":67,"update_tm":143,"read_time":144,"preview_page_count":4},5909893218464,"https://ap-avatar.wpscdn.com/davatar_085a072bc5b1113ac321206ff7593b45","Finding Partial Products (Missing Number)  \nName:  \n\n| Find the number that makes each equation true.\u003Cbr>1) A teacher shows this partial products strategy on the board. 53 × 52 = (50 × 50)+ (50 × 2) + (3 × 50) + (3 × ___)\u003Cbr>2) 18 × 18 = (10 × 10) + (10 × 8) + (8 × 10) +  \u003Cbr>3) A student uses place value to break apart a multiplication problem. 312 × 8 =(300 × 8) + (10 × 8) +  \u003Cbr>4) 473 × 8 = (400 × 8) + (70 × 8) +  \u003Cbr>5) A student breaks a multiplication problem into partial products. 678 × 8 = (600 × 8) + (70 × 8) + (___ × 8)\u003Cbr>6) A teacher shows this partial products strategy on the board. 95 × 16 = (90 × 10)+ (90 × 6) + (5 × 10) +  \u003Cbr>7) Jerry is using partial products to multiply. 55 × 14 = (50 × 10) + (50 × 4) + (5 × 10) + (5 × ___)\u003Cbr>8) Amy is using partial products to multiply. 91 × 84 = (90 × 80) + (90 × 4) + (1 × 80)+  \u003Cbr>9) Emily uses place value to break apart a multiplication problem. 571 × 2 = (500 ×\u003Cbr>2) + (70 × 2) + (___ × 2)\u003Cbr>10) Paul breaks a multiplication problem into partial products. 227 × 8 = (200 × 8) +(20 × 8) +  \u003Cbr>11) 561 × 2 = (500 × 2) + (60 × 2) + (   × 2)\u003Cbr>12) 84 × 34 = (80 × 30) + (80 × 4) + (4 × 30) + (4 ×   )\u003Cbr>13) 718 × 7 = (700 × 7) + (10 × 7) +  \u003Cbr>14) A student breaks a multiplication problem into partial products. 233 × 3 = (200 × 3) + (30 × 3) + (___ × 3)\u003Cbr>15) A teacher shows this partial products strategy on the board. 98 × 33 = (90 × 30)+ (90 × 3) + (8 × 30) +   |  |  |  | Answers\u003Cbr>1.  \u003Cbr>2.  \u003Cbr>3.  \u003Cbr>4.  \u003Cbr>5.  \u003Cbr>6.  \u003Cbr>7.  \u003Cbr>8.  \u003Cbr>9.  \u003Cbr>10.  \u003Cbr>11.  \u003Cbr>12.  \u003Cbr>13.  \u003Cbr>14.  \u003Cbr>15.   |  |  |  |  |  |  |  |\n| --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- |\n| \u003Cbr>\u003Cbr>Math\u003Cbr>[www.CommonCoreSheets.com](www.CommonCoreSheets.com)\u003Cbr>1\u003Cbr>1-10\u003Cbr>11-15 | 93 | 87 | 80 |  | 73 | 67 | 60 | 53 | 47 | 40 | 33 |\n|  | 27 | 20 | 13 |  | 7 | 0 |  |  |  |  |  |\n\nFinding Partial Products (Missing Number)  \nName: Answer Key  \n\n| Find the number that makes each equation true.\u003Cbr>1) A teacher shows this partial products strategy on the board. 53 × 52 = (50 × 50)+ (50 × 2) + (3 × 50) + (3 × ___) |  |  |  |  | Answers\u003Cbr>1.  2  |  |  |  |  |  |  |  |\n| --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- |\n| 2) | 18 × 18 = (10 × 10) + (10 × 8) + (8 × 10) +   |  |  |  | 2.  64  |  |  |  |  |  |  |  |\n| 3) | A student uses place value to break apart a multiplication problem. 312 × 8 =(300 × 8) + (10 × 8) +   |  |  |  | 3.  16  4. 24 |  |  |  |  |  |  |  |\n| 4) | 473 × 8 = (400 × 8) + (70 × 8) +   |  |  |  | 5.  8  |  |  |  |  |  |  |  |\n| 5) | A student breaks a multiplication problem into partial products. 678 × 8 = (600 × 8) + (70 × 8) + (___ × 8) |  |  |  | 6.  30  |  |  |  |  |  |  |  |\n| 6) | A teacher shows this partial products strategy on the board. 95 × 16 = (90 × 10)+ (90 × 6) + (5 × 10) +   |  |  |  | 7.  4  8. 4 |  |  |  |  |  |  |  |\n| 7) | Jerry is using partial products to multiply. 55 × 14 = (50 × 10) + (50 × 4) + (5 × 10) + (5 × ___) |  |  |  | 9.  1  |  |  |  |  |  |  |  |\n| 8) | Amy is using partial products to multiply. 91 × 84 = (90 × 80) + (90 × 4) + (1 × 80)+   |  |  |  | 10.  56  |  |  |  |  |  |  |  |\n| 9) | Emily uses place value to break apart a multiplication problem. 571 × 2 = (500 × 2) + (70 × 2) + (___ × 2) |  |  |  | 11.  1  |  |  |  |  |  |  |  |\n| 10) | Paul breaks a multiplication problem into partial products. 227 × 8 = (200 × 8) +(20 × 8) +   |  |  |  | 12.  4  13. 56 |  |  |  |  |  |  |  |\n| 11) | 561 × 2 = (500 × 2) + (60 × 2) + (   × 2) |  |  |  | 14.  3  |  |  |  |  |  |  |  |\n| 12) | 84 × 34 = (80 × 30) + (80 × 4) + (4 × 30) + (4 × ___) |  |  |  | 15.  24  |  |  |  |  |  |  |  |\n| 13) | 718 × 7 = (700 × 7) + (10 × 7) +   |  |  |  |  |  |  |  |  |  |  |  |\n| 14) | A student breaks a multiplication problem into partial products. 233 × 3 = (200 × 3) + (30 × 3) + (___ × 3) |  |  |  |  |  |  |  |  |  |  |  |\n| 15) | A teacher shows this partial products strategy on the board. 98 × 33 = (90","cbCaid0NogfkvyKr","https://ap.wps.com/l/cbCaid0NogfkvyKr","pdf",443726,"English","# Find the number that makes each equation true\n## Partial products strategy examples\n## Place value decomposition examples","[{\"question\":\"What is the goal of the worksheet?\",\"answer\":\"Find the missing number that makes each multiplication equation true when the product is written using partial products or place value.\"},{\"question\":\"How do students complete problems on this sheet?\",\"answer\":\"They break the multiplication into partial products (expanded tens/ones or hundreds/tens/ones), then determine the missing factor that completes the final term.\"},{\"question\":\"What strategies are shown in the examples?\",\"answer\":\"Examples reference both partial products and place value, with scenarios describing how teachers or students decompose numbers to build the product.\"}]","Finding Partial Products (Missing Number) | PDF",1790804191,76]