[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"doc-seo-300348-105":3,"detail-sidebar-cat-0-en-105":81,"doc-detail-300348-en":131},{"code":4,"msg":5,"data":6},0,"ok",{"site_id":7,"language":8,"slug":9,"title":10,"keywords":11,"description":12,"schema_data":13,"social_meta":74,"head_meta":76,"extra_data":78,"updated_unix":80},105,"en","fe-exam-review-fluid-mechanicsdynamics-manometers-reynolds-number-drag-force-head-loss-energy-equation-mach-number","FE exam review - Fluid Mechanics/Dynamics - Manometers - Reynolds Number - Drag Force - Head Loss - Energy Equation - Mach Number","","FE exam review material covering core fluid mechanics and related dynamics topics, presented as practice problems and key formulae. Content addresses pressure in static liquids and pressure-field relations, absolute versus gage pressure, and barometer/manometer interpretation. It includes Reynolds-number concepts for laminar versus turbulent flow, drag force and drag coefficient correlations for flat plates, Darcy-Weisbach head loss and friction-factor notation, and the steady-flow energy and pump power equations. Compressible-flow coverage includes Mach number and continuity-based density evaluation.",{"@graph":14,"@context":73},[15,34,56],{"@type":16,"itemListElement":17},"BreadcrumbList",[18,23,27,31],{"item":19,"name":20,"@type":21,"position":22},"https://docshare.wps.com","Home","ListItem",1,{"item":24,"name":25,"@type":21,"position":26},"https://docshare.wps.com/document/","Document",2,{"item":28,"name":29,"@type":21,"position":30},"https://docshare.wps.com/document/exam/","Exam",3,{"item":32,"name":10,"@type":21,"position":33},"https://docshare.wps.com/document/fe-exam-review-fluid-mechanicsdynamics-manometers-reynolds-number-drag-force-head-loss-energy-equation-mach-number/300348/",4,{"url":32,"name":10,"@type":35,"image":36,"author":41,"headline":10,"publisher":44,"fileFormat":47,"inLanguage":8,"description":12,"dateModified":48,"datePublished":49,"encodingFormat":47,"isAccessibleForFree":50,"interactionStatistic":51},"DigitalDocument",{"url":37,"@type":38,"width":39,"height":40},"https://docshare.wps.com/thumbnails/fe-exam-review-fluid-mechanicsdynamics-manometers-reynolds-number-drag-force-head-loss-energy-equation-mach-number/300348.png","ImageObject",300,407,{"name":42,"@type":43},"Eliana","Person",{"url":19,"name":45,"@type":46},"DocShare","Organization","application/pdf","2026-10-29","2026-09-18",true,{"@type":52,"interactionType":53,"userInteractionCount":55},"InteractionCounter",{"@type":54},"ViewAction",11,{"@type":57,"mainEntity":58},"FAQPage",[59,65,69],{"name":60,"@type":61,"acceptedAnswer":62},"How is absolute pressure related to atmospheric and gage pressure?","Question",{"text":63,"@type":64},"Absolute pressure is expressed as atmospheric pressure plus the gage pressure reading, and alternatively as atmospheric pressure minus the vacuum gage pressure reading.","Answer",{"name":66,"@type":61,"acceptedAnswer":67},"What does the Reynolds number indicate in this review?",{"text":68,"@type":64},"The critical Reynolds number is the minimum Reynolds number at which a flow will turn turbulent, separating laminar assumptions from turbulent behavior.",{"name":70,"@type":61,"acceptedAnswer":71},"Which equations are used for head loss and pumping power?",{"text":72,"@type":64},"Head loss uses the Darcy-Weisbach equation with the Darcy friction factor. Pumping power uses W = Qrh/η, with forms involving Q, p, g, and efficiency.","https://schema.org",{"og:url":32,"og:type":75,"og:title":10,"og:site_name":45,"og:description":12},"article",{"robots":77,"canonical":32},"index,follow",{"doc_id":79,"site_id":7},300348,1790747889,{"code":4,"msg":82,"data":83},"success",[84,88,92,95,100,105,110,115,120,123,127],{"id":22,"doc_module":4,"doc_module_name":25,"category_name":85,"show_sort_weight":86,"slug":87},"Story & Novel",90,"story-novel",{"id":26,"doc_module":4,"doc_module_name":25,"category_name":89,"show_sort_weight":90,"slug":91},"Literature",80,"literature",{"id":33,"doc_module":4,"doc_module_name":25,"category_name":29,"show_sort_weight":93,"slug":94},70,"exam",{"id":96,"doc_module":4,"doc_module_name":25,"category_name":97,"show_sort_weight":98,"slug":99},5,"Comic",60,"comic",{"id":101,"doc_module":4,"doc_module_name":25,"category_name":102,"show_sort_weight":103,"slug":104},6,"Technology",50,"technology",{"id":106,"doc_module":4,"doc_module_name":25,"category_name":107,"show_sort_weight":108,"slug":109},7,"Healthcare",40,"healthcare",{"id":111,"doc_module":4,"doc_module_name":25,"category_name":112,"show_sort_weight":113,"slug":114},8,"Research & Report",30,"research-report",{"id":116,"doc_module":4,"doc_module_name":25,"category_name":117,"show_sort_weight":118,"slug":119},9,"Religion & Spirituality",20,"religion-spirituality",{"id":118,"doc_module":4,"doc_module_name":25,"category_name":121,"show_sort_weight":118,"slug":122},"World Cup","world-cup",{"id":124,"doc_module":4,"doc_module_name":25,"category_name":125,"show_sort_weight":124,"slug":126},10,"Lifestyle","lifestyle",{"id":128,"doc_module":4,"doc_module_name":25,"category_name":129,"show_sort_weight":96,"slug":130},19,"General","general",{"code":4,"msg":82,"data":132},{"doc_id":79,"user_id":133,"nickname":42,"user_avatar":134,"doc_module":4,"category_id":33,"category_name":29,"doc_title":10,"doc_description":12,"doc_content":135,"file_id":136,"file_url":137,"file_type":138,"file_size":139,"view_count":55,"is_deleted":4,"is_public":22,"is_downloadable":22,"audit_status":22,"page_count":140,"language":141,"language_code":8,"site_id":7,"html_lang":8,"table_of_contents":142,"faqs":143,"seo_title":144,"seo_description":12,"update_tm":145,"read_time":108,"preview_page_count":4},4398048949847,"https://ap-avatar.wpscdn.com/avatar/400002536579ef2da7f?_k=1778318612642679267","# FE exam review\n\nFluid Mechanics/DynamicsNoriaki Ohara  \nCivil and Architectural Engineering  \nChemical:8-12 problemsCivil:4-6(+8-12)problemsEnvironmental:9-14 problemsMechanical:9-14 problemsOther:8-12(+4-6)problemsout of 110 problems  \nAcknowledgement:This material was mainly basedon Olia(2008).  \nOlia,M.(2008).Barron's FE Fundamentals ofEngineering Exam.Barron's Educational Series.  \nWhat is the pressure at a point 18,000 ft below1the surface of the ocean?  \n(γ=64.01b/ft³)  \nThe Pressure Field in a Static LiquidP2·hZ2P1·Z1  \n(A)1,150,000 psig  \n(B)250 psig  \n(C)8,000 psig  \n(D)258,000 psig  \nThe difference in pressure between two different points is  \nP₂-P₁=-Y(z₂-z₁)=-yh=-pgh  \nAbsolute pressure=atmospheric pressure+gage pressurereading  \nAbsolute pressure =atmospheric pressure-vacuum gagepressure reading  \n2  \nFor the barometer shown in the figure,what isthe atmospheric pressure if hm=20 cm,Pm=  \n13,550kg/m³,and pv=0kPa?  \n(A)128 kPa  \n(B)26.6 kPa  \n(C)4.36 kPa  \n(D)82.4kPa  \nIn the figure,what is the absolute pressure (PA)in vessel A?  \nManometers  \nP₂FLUID 1、  \nFLUID 2P₀  \nh₁P,一Y₂  \n(A)15.8 psia  \n(B)18.4 psia  \nFor a simple manometer,  \n(D)11.0 psia  \n(C)13.6 psia  \nP₀=P₂+Y₂h₂-Y₁h₁=P₂+g(P₂h₂-P₁h₁)If h₁=h₂=hP₀=P₂+(Y₂-Y₁)h=P₂+(P₂-P₁)gh  \nNote that the difference between the two densities is used.  \nP =pressure  \nY =specific weight of fluidh =height  \ng =acceleration of gravityP =fluid density  \n4Water flows through a 20-cm-diameter pipe.Ifthe critical Reynolds number is 2,300,what is themaximum value of the average velocity forwhich laminar flow can be assumed?(A)0.047 m/s  \nReynolds Number(B)1.2 m/s  \nRe =vDp/μ=vD/U(C)0.0092 m/s(D)0.75 m/siaep =the mass density  \nD =the diameter of the pipe,dimension of the fluidstreamline,or characteristic lengthμ =the dynamic viscosityU =the kinematic viscosity  \nRe =the Reynolds number(Newtonian fluid)Re′=the Reynolds number(Power law fluid)  \nKand n are defined in the Stress,Pressure,and Viscositysection.  \nThe critical Reynolds number(Re)is defined to be theminimum Reynolds number at which a flow will turnturbulent.  \nWhat is the coefficient of drag for a flow of air5  \n(p=1.225 kg/m³,μ=1.8×10-⁵N·s/m²)over a flat plate that is 93 cm long,ifV。=86m/s?  \n(A)3.38×10-³(B)5.70×10-³(C)2.19×10-3The drag force FDon objects immersed in a large body offlowing fluid or objects moving through a stagnant fluid is(D)8.27×10-³  \nDrag Force  \n,whereCD=the drag coefficient,  \nV =the velocity(m/s)of the flowing fluid or movingobject,and  \nA =the projected area(m²)of blunt objects such asspheres,ellipsoids,disks,and plates,cylinders,ellipses,and air foils with axes perpendicular to theflow.  \np =fluid density  \nFor flat plates placed parallel with the flow:CD=1.33/Re⁰.5(10⁴\u003CRe\u003C5×10⁵)CD=0.031/Re¹7(10⁶\u003CRe\u003C10⁹)  \n6Water flows through a 17-cm-diameter horizon-  \ntal pipe(f=0.017)at a rate of 0.34 m³/s.Whatis the frictional head loss per meter of pipelength?(A)1.31m(B)1.14 m(C)0.02 m(D)0.78m  \n## Head Loss Due to Flow\n\nThe Darcy-Weisbach equation iswhere  \nf =f(Re,ε/D),the Moody,Darcy,or Stanton frictionfactor  \nD =diameter of the pipe  \nL =length over which the pressure drop occursε =roughness factor for the pipe,and other symbolsare defined as before  \n.What is the pumping power required for the sys-tem shown in the figure?(Neglect friction in thepipes.)  \n7  \n## The Energy Equation\n\nThe energy equation for steady incompressible flow with noshaft device is  \n(A)58,900kW  \n(B)65,400kW  \n(C)82,300 kW  \n(D)53,000kW  \nhg =the head loss,considered a friction effect,and allremaining terms are defined above.  \n## Pump Power Equation\n\nW=Qrh/η=Qpgh/m;,whereQ =volumetric flow(m³/s or cfs)h =head(m or ft)the fluid has to be liftedη,=total efficiency(npump×1motor)W=power(kg.m²/sec³or ft-lbf/sec)  \n8  \nWhat is the Mach number of a fluid stream flow-ing at a velocity of 370 ft/sec?(c=1,080 ft/sec)(A)0.66(B)2.92(C)0.34(D)3.4  \nMach Number  \nThe local speed of sound in an ideal gas is given by:c=√kRT,wherec=local speed ","cbCaivSEJPYnwSK9","https://ap.wps.com/l/cbCaivSEJPYnwSK9","pdf",3764824,16,"English","# FE exam review\n## Pressure in static liquids\n## Manometers and barometers\n## Reynolds number and flow regime\n## Drag force and drag coefficient\n## Head loss due to flow\n## The energy equation\n## Pump power equation\n## Mach number and compressible flow","[{\"question\":\"How is absolute pressure related to atmospheric and gage pressure?\",\"answer\":\"Absolute pressure is expressed as atmospheric pressure plus the gage pressure reading, and alternatively as atmospheric pressure minus the vacuum gage pressure reading.\"},{\"question\":\"What does the Reynolds number indicate in this review?\",\"answer\":\"The critical Reynolds number is the minimum Reynolds number at which a flow will turn turbulent, separating laminar assumptions from turbulent behavior.\"},{\"question\":\"Which equations are used for head loss and pumping power?\",\"answer\":\"Head loss uses the Darcy-Weisbach equation with the Darcy friction factor. Pumping power uses W = Qrh/η, with forms involving Q, p, g, and efficiency.\"}]","FE exam review - Fluid Mechanics/Dynamics - Manometers - Reynolds Number - Drag Force - Head Loss - Energy Equation - Mach Number | PDF",1789773929]