[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"detail-sidebar-cat-0-en-105":3,"doc-seo-203994-105":59,"doc-detail-203994-en":130},{"code":4,"msg":5,"data":6},0,"success",[7,13,18,23,28,33,38,43,48,51,55],{"id":8,"doc_module":4,"doc_module_name":9,"category_name":10,"show_sort_weight":11,"slug":12},1,"Document","Story & Novel",90,"story-novel",{"id":14,"doc_module":4,"doc_module_name":9,"category_name":15,"show_sort_weight":16,"slug":17},2,"Literature",80,"literature",{"id":19,"doc_module":4,"doc_module_name":9,"category_name":20,"show_sort_weight":21,"slug":22},4,"Exam",70,"exam",{"id":24,"doc_module":4,"doc_module_name":9,"category_name":25,"show_sort_weight":26,"slug":27},5,"Comic",60,"comic",{"id":29,"doc_module":4,"doc_module_name":9,"category_name":30,"show_sort_weight":31,"slug":32},6,"Technology",50,"technology",{"id":34,"doc_module":4,"doc_module_name":9,"category_name":35,"show_sort_weight":36,"slug":37},7,"Healthcare",40,"healthcare",{"id":39,"doc_module":4,"doc_module_name":9,"category_name":40,"show_sort_weight":41,"slug":42},8,"Research & Report",30,"research-report",{"id":44,"doc_module":4,"doc_module_name":9,"category_name":45,"show_sort_weight":46,"slug":47},9,"Religion & Spirituality",20,"religion-spirituality",{"id":46,"doc_module":4,"doc_module_name":9,"category_name":49,"show_sort_weight":46,"slug":50},"World Cup","world-cup",{"id":52,"doc_module":4,"doc_module_name":9,"category_name":53,"show_sort_weight":52,"slug":54},10,"Lifestyle","lifestyle",{"id":56,"doc_module":4,"doc_module_name":9,"category_name":57,"show_sort_weight":24,"slug":58},19,"General","general",{"code":4,"msg":60,"data":61},"ok",{"site_id":62,"language":63,"slug":64,"title":65,"keywords":66,"description":67,"schema_data":68,"social_meta":123,"head_meta":125,"extra_data":127,"updated_unix":129},105,"en","drilled-shaft-homework-questions-cbt","Drilled Shaft Homework Questions CBT","","A set of drilled shaft installation review questions for CBT exam preparation, covering classification of auger bits, drilled shaft installation methods, slurry functions, bucket types, pilot hole sequencing, and required contractor submittals. Additional questions address core recovery, Rock Quality Designation (RQD) calculations, adjustments for casing wall thickness affecting effective shaft diameter and pay quantities, and geometric computations for casing and theoretical volumes, rock socket length, and side spacer quantity for concrete cover requirements.",{"@graph":69,"@context":122},[70,84,105],{"@type":71,"itemListElement":72},"BreadcrumbList",[73,77,79,82],{"item":74,"name":75,"@type":76,"position":8},"https://docshare.wps.com","Home","ListItem",{"item":78,"name":9,"@type":76,"position":14},"https://docshare.wps.com/document/",{"item":80,"name":20,"@type":76,"position":81},"https://docshare.wps.com/document/exam/",3,{"item":83,"name":65,"@type":76,"position":19},"https://docshare.wps.com/document/drilled-shaft-homework-questions-cbt/203994/",{"url":83,"name":65,"@type":85,"image":86,"author":91,"headline":65,"publisher":94,"fileFormat":97,"inLanguage":63,"description":67,"dateModified":98,"datePublished":99,"encodingFormat":97,"isAccessibleForFree":100,"interactionStatistic":101},"DigitalDocument",{"url":87,"@type":88,"width":89,"height":90},"https://docshare.wps.com/thumbnails/drilled-shaft-homework-questions-cbt/203994.png","ImageObject",300,407,{"name":92,"@type":93},"Levi","Person",{"url":74,"name":95,"@type":96},"DocShare","Organization","application/pdf","2026-10-07","2026-09-04",true,{"@type":102,"interactionType":103,"userInteractionCount":29},"InteractionCounter",{"@type":104},"ViewAction",{"@type":106,"mainEntity":107},"FAQPage",[108,114,118],{"name":109,"@type":110,"acceptedAnswer":111},"Which installation methods are NOT included in the drilled shaft choices?","Question",{"text":112,"@type":113},"The question asks which option is NOT a drilled shaft installation method. Choose the one that does not match the listed installation types (Permanent Casing, Vibratory, Wet, Dry, Temporary Casing).","Answer",{"name":115,"@type":110,"acceptedAnswer":116},"How are percent core recovery (%REC) and RQD computed in the provided problem?",{"text":117,"@type":113},"%REC is calculated as (core recovered length / core run length) × 100. RQD is calculated similarly using the recovered core fragments length (greater than the specified cutoff) divided by the core run length, then multiplied by 100.",{"name":119,"@type":110,"acceptedAnswer":120},"What additional shaft length is required when the provided casing changes the effective internal diameter?",{"text":121,"@type":113},"Compute the effective internal diameter from the nominal specified diameter minus 2×wall thickness, then convert the diameter difference into an equivalent additional length using the given shaft depth below ground.","https://schema.org",{"og:url":83,"og:type":124,"og:title":65,"og:site_name":95,"og:description":67},"article",{"robots":126,"canonical":83},"index,follow",{"doc_id":128,"site_id":62},203994,1789976472,{"code":4,"msg":5,"data":131},{"doc_id":128,"user_id":132,"nickname":92,"user_avatar":133,"doc_module":4,"category_id":19,"category_name":20,"doc_title":65,"doc_description":67,"doc_content":134,"file_id":135,"file_url":136,"file_type":137,"file_size":138,"view_count":29,"is_deleted":4,"is_public":8,"is_downloadable":8,"audit_status":8,"page_count":52,"language":139,"language_code":63,"site_id":62,"html_lang":63,"table_of_contents":140,"faqs":141,"seo_title":142,"seo_description":67,"update_tm":143,"read_time":144},7971461740909,"https://ap-avatar.wpscdn.com/davatar_155a257f0dc6eb9ab79c44ca47cae57d","Drilled Shaft Homework Questions CBT  \nIntroduction  \nThis section contains review questions for you that will help you prepare for the exam. The Review is divided in two parts. The first part of your work consist of simple questions. The second part of the review work consists of problems. Have ready with you a calculator, pencil, paper, ruler, and your notes.  \nQuestion 1.  \nAuger bits are generally classified as what two types?  \nSoil and Rock  \nQuestion 2. Multiple Choice  \nWhich of the following is NOT a method of Drilled Shaft installation?  \nA. Permanent Casing Method  \nB. Vibratory Method  \nC. Wet Method  \nD. Dry Method  \nE. Temporary Casing method  \nQuestion 3. True or False  \nThe Contractor is required to use temporary/surface casing.  \nTrue  \nQuestion 4. Multiple Choice  \nWhich of the following purposes does slurry serve?  \nA. Maintains a stable borehole  \nB. Facilitates the removal of cuttings  \nC. Maintains high effective stress in the soil to retard softening or loosening  \nD. All of the above  \nQuestion 5.  \nWhen using earth augers, which has superior removal capacity, single or double flight?  \nDouble  \nQuestion 6.  \nWhich type of bucket is the image below?  \nDigging  \nQuestion 7. True or False  \nWhen Pilot Holes are shown in the plans, they are to be performed prior to shaft excavation.  \nTrue  \nQuestion 8.  \nWhich type of bucket is the image below?  \nCleanout or Bailing  \nQuestion 9.  \nWhich document is the Contractor to prepare and submit to the Engineer at the preconstruction conference?  \nDrilled Shaft Installation Plan  \nQuestion 10.  \nWhich type of tool is the image below?  \nOverreaming tool  \nQuestion 11.  \nIn accordance with the project requirements, the contractor has obtained a 4” diameter core from below the shaft bottom. The core run was 5.0’ and the total rock recovered was 4. 2’. A total of 3 .7’ of the recovered core consisted of core fragments greater than 4”. Calculate the percent core recovery (%REC) and Rock Quality Designation (RQD) .  \nRecovery is equal to 4.2 ft divided by 5 feet times 100 equals to 84% . Now please compute the RQD.  \nRQD Is equal to 3.7 feet divided by 5 feet times 100 equals to 74%  \nQuestion 12.  \nThe plans for a bridge specify that the drilled shaft diameter be 48”. However, the contractor supplied a temporary casing with an outside diameter equal to the specified shaft diameter (O. D. casing) . The authorized shaft length below ground was 68’ and the casing supplied had a wall thickness of ½”. What additional length of shaft is required?  \nD1 = 4.0’ = 48”  \nD2 = D1 – 2 (t) = 48” – 2 ( .5”) = 47”t = 0.5”  \nL = 68.0’  \nThe required diameter is D1 equals to 4 feet equals to 48 inches.  \nThe actual diameter to be provided is the internal diameter D2 which is equals to D1 minus 2 times the thickness of the wall. This is equal to 48 inches minus 2 times 0.5 equals to 47 inches.  \n(shows the t=0.5”)  \nL= 68 feet. This is the depth below ground because it is a temporary casing.  \nThe Additional length is 48 inches minus 47 inches divided by 47 inches times 68 feet.  \nQuestion 13.  \nFor the situation presented in Problem \\#2, determine the factor (F) to adjust pay quantities to compensate for smaller shafts.  \nThe factor F is equal to 2 times 47 inches minus 48 inches divided by 47 inches equals to 0.9787  \nQuestion 14.  \nPlease calculate the values asked in this slide.  \nLength 50Item 1. Calculate length of casing below ground:  \nBased on the figure the top of the casing is 3.5 feet above ground. Therefore, to compute the casing length below ground we just need to deduct 3.5 feet from the total casing length. Therefore:  \n50 minus 3.5 equals to 46.5 feet.  \nItem 2. Compute the elevation at bottom of casing.  \nThe bottom of casing elevation is equals to plus 55 minus 50 equal to plus 5 feet. Item 3. Elevation at bottom of shaft:  \nThe bottom of shaft elevation is plus 55 minus 72 equals to minus 17 feet. Item 4 Theoretical volume:  \nThe theoretical volume is computed as area ","cbCaicu8TK4eyW8m","https://ap.wps.com/l/cbCaicu8TK4eyW8m","pdf",314880,"English","# Introduction\n# Review Questions\n## Multiple Choice and True/False\n## Calculations and Engineering Parameters","[{\"question\":\"Which installation methods are NOT included in the drilled shaft choices?\",\"answer\":\"The question asks which option is NOT a drilled shaft installation method. Choose the one that does not match the listed installation types (Permanent Casing, Vibratory, Wet, Dry, Temporary Casing).\"},{\"question\":\"How are percent core recovery (%REC) and RQD computed in the provided problem?\",\"answer\":\"%REC is calculated as (core recovered length / core run length) × 100. RQD is calculated similarly using the recovered core fragments length (greater than the specified cutoff) divided by the core run length, then multiplied by 100.\"},{\"question\":\"What additional shaft length is required when the provided casing changes the effective internal diameter?\",\"answer\":\"Compute the effective internal diameter from the nominal specified diameter minus 2×wall thickness, then convert the diameter difference into an equivalent additional length using the given shaft depth below ground.\"}]","Drilled Shaft Homework Questions CBT | PDF",1788565431,25]