[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"doc-seo-314912-105":3,"detail-sidebar-cat-0-en-105":81,"doc-detail-314912-en":130},{"code":4,"msg":5,"data":6},0,"ok",{"site_id":7,"language":8,"slug":9,"title":10,"keywords":11,"description":12,"schema_data":13,"social_meta":74,"head_meta":76,"extra_data":78,"updated_unix":80},105,"en","chemistry-free-response-questions-section-ii-constructed-response-questions","Chemistry Free-Response Questions - Section II - Constructed-Response Questions","","Chemistry Section II provides seven long-and short constructed-response questions emphasizing clear, well-organized explanations and accurate, relevant data. The questions cover nonpolar-solvent paper chromatography of dyes, conductivity during titration of Ba(OH)2 with H2SO4 including precipitation of BaSO4 with given Ksp, and solubility and lattice-energy reasoning for Ca(OH)2 and Mg(OH)2 using equilibrium and particle-representation concepts.",{"@graph":14,"@context":73},[15,34,56],{"@type":16,"itemListElement":17},"BreadcrumbList",[18,23,27,31],{"item":19,"name":20,"@type":21,"position":22},"https://docshare.wps.com","Home","ListItem",1,{"item":24,"name":25,"@type":21,"position":26},"https://docshare.wps.com/document/","Document",2,{"item":28,"name":29,"@type":21,"position":30},"https://docshare.wps.com/document/exam/","Exam",3,{"item":32,"name":10,"@type":21,"position":33},"https://docshare.wps.com/document/chemistry-free-response-questions-section-ii-constructed-response-questions/314912/",4,{"url":32,"name":10,"@type":35,"image":36,"author":41,"headline":10,"publisher":44,"fileFormat":47,"inLanguage":8,"description":12,"dateModified":48,"datePublished":49,"encodingFormat":47,"isAccessibleForFree":50,"interactionStatistic":51},"DigitalDocument",{"url":37,"@type":38,"width":39,"height":40},"https://docshare.wps.com/thumbnails/chemistry-free-response-questions-section-ii-constructed-response-questions/314912.png","ImageObject",300,407,{"name":42,"@type":43},"supergirl","Person",{"url":19,"name":45,"@type":46},"DocShare","Organization","application/pdf","2026-10-22","2026-09-20",true,{"@type":52,"interactionType":53,"userInteractionCount":55},"InteractionCounter",{"@type":54},"ViewAction",10,{"@type":57,"mainEntity":58},"FAQPage",[59,65,69],{"name":60,"@type":61,"acceptedAnswer":62},"What formatting and scoring guidance is given for Section II responses?","Question",{"text":63,"@type":64},"Responses are scored for accuracy and relevance. Explanations should be clear, well organized, and focused, and calculations should show the method and steps for potential partial credit.","Answer",{"name":66,"@type":61,"acceptedAnswer":67},"How is the conductivity behavior explained during titration of Ba(OH)2 with H2SO4?",{"text":68,"@type":64},"The problem states conductivity decreases as more H2SO4 is added from 0.0 mL to 30.0 mL, and it asks identify the conducting species first and then explain the decrease using the neutralization and precipitation net-ionic equations.",{"name":70,"@type":61,"acceptedAnswer":71},"What thermodynamic quantity is used to compare Mg(OH)2 and Sr(OH)2, and what reasoning is required?",{"text":72,"@type":64},"The questions use lattice energy values and ask for an explanation based on periodic properties and Coulomb’s law for why Sr(OH)2 has lower lattice energy than Mg(OH)2.","https://schema.org",{"og:url":32,"og:type":75,"og:title":10,"og:site_name":45,"og:description":12},"article",{"robots":77,"canonical":32},"index,follow",{"doc_id":79,"site_id":7},314912,1789902135,{"code":4,"msg":82,"data":83},"success",[84,88,92,95,100,105,110,115,120,123,126],{"id":22,"doc_module":4,"doc_module_name":25,"category_name":85,"show_sort_weight":86,"slug":87},"Story & Novel",90,"story-novel",{"id":26,"doc_module":4,"doc_module_name":25,"category_name":89,"show_sort_weight":90,"slug":91},"Literature",80,"literature",{"id":33,"doc_module":4,"doc_module_name":25,"category_name":29,"show_sort_weight":93,"slug":94},70,"exam",{"id":96,"doc_module":4,"doc_module_name":25,"category_name":97,"show_sort_weight":98,"slug":99},5,"Comic",60,"comic",{"id":101,"doc_module":4,"doc_module_name":25,"category_name":102,"show_sort_weight":103,"slug":104},6,"Technology",50,"technology",{"id":106,"doc_module":4,"doc_module_name":25,"category_name":107,"show_sort_weight":108,"slug":109},7,"Healthcare",40,"healthcare",{"id":111,"doc_module":4,"doc_module_name":25,"category_name":112,"show_sort_weight":113,"slug":114},8,"Research & Report",30,"research-report",{"id":116,"doc_module":4,"doc_module_name":25,"category_name":117,"show_sort_weight":118,"slug":119},9,"Religion & Spirituality",20,"religion-spirituality",{"id":118,"doc_module":4,"doc_module_name":25,"category_name":121,"show_sort_weight":118,"slug":122},"World Cup","world-cup",{"id":55,"doc_module":4,"doc_module_name":25,"category_name":124,"show_sort_weight":55,"slug":125},"Lifestyle","lifestyle",{"id":127,"doc_module":4,"doc_module_name":25,"category_name":128,"show_sort_weight":96,"slug":129},19,"General","general",{"code":4,"msg":82,"data":131},{"doc_id":79,"user_id":132,"nickname":42,"user_avatar":133,"doc_module":4,"category_id":33,"category_name":29,"doc_title":10,"doc_description":12,"doc_content":134,"file_id":135,"file_url":136,"file_type":137,"file_size":138,"view_count":55,"is_deleted":4,"is_public":22,"is_downloadable":22,"audit_status":22,"page_count":106,"language":139,"language_code":8,"site_id":7,"html_lang":8,"table_of_contents":140,"faqs":141,"seo_title":142,"seo_description":12,"update_tm":80,"read_time":143,"preview_page_count":4},962088121634,"https://ap-avatar.wpscdn.com/davatar_9964176cb1d06d4a9deccf72a44ae3dc","Nonpolar Solvent  \nChromatography Chambers  \n4.A student investigates various dyes using paper chromatography.The student has samples of three pure dyes,labeled A,B,and C,and an unknown sample that contains one of the three dyes.The student prepares thechromatography chambers shown above on the left by putting a drop of each dye at the indicated position onthe chromatography paper(a polar material)and standing the paper in a nonpolar solvent.The developedchromatograms are shown above on the right.  \n(a):Which dye(A,B,or C)is the least polar?Justify your answer in terms of the interactions between the dyesand the solvent or between the dyes and the paper.  \n(b)Which dye is present in the unknown sample?Justify your answer.  \nHEMISTRY FREE-RESPONSE QUESTIONS  \nDeveloped Chromatograms  \nCHEMISTRY  \nSection II  \n# 7 Constructed-Response Questions(Time—90 minutes)YOU MAY USE YOUR CALCULATOR FOR SECTIONII\n\nDirections:Questions 1,2,and 3 are long constructed-response questions that should require about  \n20 minutes each to answer.Questions 4,5,6,and 7 are short constructed-response questions that should requireabout seven minutes each to answer.Read each question carefully and write your response in the space providedfollowing each question.Your responses to these questions will be scored on the basis of the accuracy and relevanceof the information cited.Explanations should be clear and well organized.Specific answers are preferable to broad,diffuse responses.For calculations,clearly show the method used and the steps involved in arriving at your answers.It is to your advantage to do this,since you may obtain partial credit if you do and you will receive little or no creditif you do not.  \nVolume of 0.10MH₂SO₄Added(mL)  \n1.A student performs an experiment in which the conductivity of a solution of Ba(OH)₂is monitored as thesolution is titrated with 0.10M H₂SO₄.The original volume of the Ba(OH)₂solution is 25.0mL.A precipitateof BaSO₄(Ksp=1.0×10-10)formed during the titration.The data collected from the experiment are plotted inthe graph above.  \n(a)As the first 30.0mL of 0.10M H₂SO₄are added to the Ba(OH)₂solution,two types of chemical reactionsoccur simultaneously.On the lines provided below,write the balanced net-ionic equations for (i)theneutralization reaction and (ii)the precipitation reaction.  \n(i)Equation for neutralization reaction:                             \nO  \n0  \n(b)The conductivity of the Ba(OH)₂solution decreases as the volume of added 0.10MH₂SO₄changes from  \n0.0mL to 30.0 mL.  \n(i)Identify the chemical species that enable the solution to conduct electricity as the first 30.0 mL of  \n0.10MH₂SO₄are added.  \n(ii)On the basis of the equations you wrote in part(a),explain why the conductivity decreases.  \n(c)Using the information in the graph,calculate the molarity of the original Ba(OH)₂solution.  \n(d)Calculate the concentration of Ba²+(aq)in the solution at the equivalence point(after exactly 30.0mL of  \n0.10M H₂SO₄are added).  \n(e)The concentration of Ba²+(aq)in the solution decreases as the volume of added 0.10MH₂SO₄increasesfrom 30.0 mL to 31.0 mL.Explain.  \n'HEMISTRY FREE-RESPONSE QUESTIONS  \n4.Answer the following questions about the solubility of Ca(OH)₂(Kp=1.3×10-⁶).  \n(a)Write a balanced chemical equation for the dissolution of Ca(OH)₂(s)in pure water.  \n(b)Calculate the molar solubility of Ca(OH)₂in 0.10M Ca(NO₃)2.  \n(c)Inthe box below,complete a particle representation diagram that includes four water molecules with properorientation around the Ca²+ion.  \n   \nRepresent water molecules as○  \nQ  \nCHEMISTRY FREE-RESPONSE QUESTIONS  \n6.Answer the following questions about Mg(OH)₂.At 25°℃,the value of the solubility product constant,Ksp,forMg(OH)₂(s)is 1.8×10-11.  \n(a)Calculate the number of grams of Mg(OH)₂(molar mass 58.32 g/mol)that is dissolved in 100.mL of asaturated solution of Mg(OH)₂at 25℃.  \n(b)The energy required to separate the ions in the Mg(OH)₂crystal latice into individual Mg²+(8)and OH(8)ions,as r","cbCaimcVPAjFyjd7","https://ap.wps.com/l/cbCaimcVPAjFyjd7","pdf",1717146,"English","# 7 Constructed-Response Questions (Time—90 minutes)\n## Directions and scoring expectations\n## Question 1: Conductivity titration of Ba(OH)2 with H2SO4\n## Question 4: Solubility of Ca(OH)2\n## Question 6: Solubility and lattice energy of Mg(OH)2","[{\"question\":\"What formatting and scoring guidance is given for Section II responses?\",\"answer\":\"Responses are scored for accuracy and relevance. Explanations should be clear, well organized, and focused, and calculations should show the method and steps for potential partial credit.\"},{\"question\":\"How is the conductivity behavior explained during titration of Ba(OH)2 with H2SO4?\",\"answer\":\"The problem states conductivity decreases as more H2SO4 is added from 0.0 mL to 30.0 mL, and it asks identify the conducting species first and then explain the decrease using the neutralization and precipitation net-ionic equations.\"},{\"question\":\"What thermodynamic quantity is used to compare Mg(OH)2 and Sr(OH)2, and what reasoning is required?\",\"answer\":\"The questions use lattice energy values and ask for an explanation based on periodic properties and Coulomb’s law for why Sr(OH)2 has lower lattice energy than Mg(OH)2.\"}]","Chemistry Free-Response Questions - Section II - Constructed-Response Questions | PDF",18]