[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"detail-sidebar-cat-0-en-105":3,"doc-seo-657112-105":59,"doc-detail-657112-en":130},{"code":4,"msg":5,"data":6},0,"success",[7,13,18,23,28,33,38,43,48,51,55],{"id":8,"doc_module":4,"doc_module_name":9,"category_name":10,"show_sort_weight":11,"slug":12},1,"Document","Story & Novel",90,"story-novel",{"id":14,"doc_module":4,"doc_module_name":9,"category_name":15,"show_sort_weight":16,"slug":17},2,"Literature",80,"literature",{"id":19,"doc_module":4,"doc_module_name":9,"category_name":20,"show_sort_weight":21,"slug":22},4,"Exam",70,"exam",{"id":24,"doc_module":4,"doc_module_name":9,"category_name":25,"show_sort_weight":26,"slug":27},5,"Comic",60,"comic",{"id":29,"doc_module":4,"doc_module_name":9,"category_name":30,"show_sort_weight":31,"slug":32},6,"Technology",50,"technology",{"id":34,"doc_module":4,"doc_module_name":9,"category_name":35,"show_sort_weight":36,"slug":37},7,"Healthcare",40,"healthcare",{"id":39,"doc_module":4,"doc_module_name":9,"category_name":40,"show_sort_weight":41,"slug":42},8,"Research & Report",30,"research-report",{"id":44,"doc_module":4,"doc_module_name":9,"category_name":45,"show_sort_weight":46,"slug":47},9,"Religion & Spirituality",20,"religion-spirituality",{"id":46,"doc_module":4,"doc_module_name":9,"category_name":49,"show_sort_weight":46,"slug":50},"World Cup","world-cup",{"id":52,"doc_module":4,"doc_module_name":9,"category_name":53,"show_sort_weight":52,"slug":54},10,"Lifestyle","lifestyle",{"id":56,"doc_module":4,"doc_module_name":9,"category_name":57,"show_sort_weight":24,"slug":58},19,"General","general",{"code":4,"msg":60,"data":61},"ok",{"site_id":62,"language":63,"slug":64,"title":65,"keywords":66,"description":67,"schema_data":68,"social_meta":123,"head_meta":125,"extra_data":127,"updated_unix":129},105,"en","chem-104a-midterm-ii-total-exam-score","Chem 104A - Midterm II - Total Exam Score","","Chem 104A Midterm II includes a closed-notes, no-calculators exam focused on molecular structure and quantum chemistry concepts. It covers general true/false statements, resonance and Lewis diagrams for NO3-, vibrational spectroscopy of XeF4 including IR/Raman activity, MO theory bond energy reasoning and MO diagrams for F2-family ions, Walsh diagram analysis for an MH2 molecule, and matching items tying theorists to key contributions. The exam totals 100 points and provides time-management advice.",{"@graph":69,"@context":122},[70,84,105],{"@type":71,"itemListElement":72},"BreadcrumbList",[73,77,79,82],{"item":74,"name":75,"@type":76,"position":8},"https://docshare.wps.com","Home","ListItem",{"item":78,"name":9,"@type":76,"position":14},"https://docshare.wps.com/document/",{"item":80,"name":20,"@type":76,"position":81},"https://docshare.wps.com/document/exam/",3,{"item":83,"name":65,"@type":76,"position":19},"https://docshare.wps.com/document/chem-104a-midterm-ii-total-exam-score/657112/",{"url":83,"name":65,"@type":85,"image":86,"author":91,"headline":65,"publisher":94,"fileFormat":97,"inLanguage":63,"description":67,"dateModified":98,"datePublished":99,"encodingFormat":97,"isAccessibleForFree":100,"interactionStatistic":101},"DigitalDocument",{"url":87,"@type":88,"width":89,"height":90},"https://docshare.wps.com/thumbnails/chem-104a-midterm-ii-total-exam-score/657112.png","ImageObject",300,407,{"name":92,"@type":93},"dbqoiu","Person",{"url":74,"name":95,"@type":96},"DocShare","Organization","application/pdf","2026-10-30","2026-10-26",true,{"@type":102,"interactionType":103,"userInteractionCount":19},"InteractionCounter",{"@type":104},"ViewAction",{"@type":106,"mainEntity":107},"FAQPage",[108,114,118],{"name":109,"@type":110,"acceptedAnswer":111},"What rules are given for the exam if a student is stuck on a problem?","Question",{"text":112,"@type":113},"If stumped, move on to finish other problems and come back later if time permits. Students may use the whole class period.","Answer",{"name":115,"@type":110,"acceptedAnswer":116},"How many vibrational modes should XeF4 have, according to the exam question?",{"text":117,"@type":113},"The exam uses the relation 3N-6 = 9, so XeF4 has 9 vibrational modes.",{"name":119,"@type":110,"acceptedAnswer":120},"What technique is suggested for observing the mode that is neither Raman nor IR active?",{"text":121,"@type":113},"The exam suggests inelastic neutron scattering and discusses whether NRVS using the Xe nucleus would be an option, concluding it is not because the vibration does not include any Xe motion.","https://schema.org",{"og:url":83,"og:type":124,"og:title":65,"og:site_name":95,"og:description":67},"article",{"robots":126,"canonical":83},"index,follow",{"doc_id":128,"site_id":62},657112,1793136817,{"code":4,"msg":5,"data":131},{"doc_id":128,"user_id":132,"nickname":92,"user_avatar":133,"doc_module":4,"category_id":19,"category_name":20,"doc_title":65,"doc_description":67,"doc_content":134,"file_id":135,"file_url":136,"file_type":137,"file_size":138,"view_count":19,"is_deleted":4,"is_public":8,"is_downloadable":8,"audit_status":8,"page_count":44,"language":139,"language_code":63,"site_id":62,"html_lang":63,"table_of_contents":140,"faqs":141,"seo_title":142,"seo_description":67,"update_tm":143,"read_time":144},3985747862462,"https://ap-avatar.wpscdn.com/davatar_3d24733baf745e90a7e4bdd5f77d97b2","Your name   Grade this page    \nChem 104A-Midterm II Total Exam Score  \n____  \nclosed text, closed notes, no calculators  \nThere are 100 total points. General advice-if you are stumped by one problem, move on to finish other problems and come back later if time permits. You may use the whole class period.  \nA. General (10 points) 2 Points Each   True or false (Enter T or F on line) next to statement:  \n_T_ 1. A linear molecule has 3N-5 normal modes, where N is the number of atoms._T_ 2. Nuclear excitations often involve gamma rays.  \n_T_ 3. Vibrations of molecules with inversion centers are not both Raman & IR active._F_ 4. Molecules are free to rotate at any velocity.  \n_T_ 5. Electronic excitations often involve energies of several eV.  \nB. Lewis Diagrams (10 points) 2 Points Each    \n1. Complete a Lewis diagram for one resonance structure of NO3-(include a double bond, and identify formal charges):  \nelectrons = 5 + 3(6) = 24  \n2. Do more resonance structures make for greater or less stability? _greater_  \n3. Draw a resonance structure with all single bonds, and identify the formal charges.  \n4. Is this structure more or less likely than the first structure you drew?  \nless  \n5. Why? The first structure minimizes the number of non-zero formal charges  \nYour name   Grade this page    \nC. Vibrational Spectroscopy (30 points) 2 Points each answer   Shown below are some vibrational modes for XeF4.  \na . b.  \nc. d.  \n1. How many vibrational modes will this molecule have? _3N-6 = 9_  \n2. What is the point group for this molecule? _D4h_  \n3. Based on the character table supplied in the appendix, what are the irreducible representations for the above modes ?  \na. _A 1g  b. _A2u  c. _B 1g  d. _B2u   \n4. For each mode, fill in IR, R, or ‘both’ on the adjacent line, depending on whether the mode is IR-active, Raman-active, or IR-and Raman-active.  \na   R  b  IR  c   R  d  neither_  \n5. It turns out one of the above modes is neither Raman nor IR active.  \na. Which one do you think it is? (insert letter on line)  d (B2u)   \nb. Why? The character table shows no IR or Raman activity for vibrations with a B2u representation.  \nc. Suggest another technique to see this mode: inelastic neutron scattering  \nd. Would NRVS using the Xe nucleus be an option? Why or why not? No, because vibration d. does not include any Xe motion.  \nYour name   Grade this page    \nD. MO Theory 30 Points    \n1. (4 points each) In MO theory, we know that the bond energy depends on two things--overlap (S) between the atomic orbitals and the atomic orbital energy difference ( E): bond energy µ ~~ ~~SD2E  \nFor the sketches below, circle the case with the higher bond energy, and briefly state why (in the margin).  \na.  \nor  \nH 1s  \n13.6  \nF2pz  \n18.6  \nb.  \nmore overlap (big S)  \nH 1s  \n13.6 F2s 40.2  \nor  \nAtomic orbital energies are closer (small  \nE)  \nc.  \nor  \nF2pz  \n18.6  \neV  \nF2pz  \n18.6  \neV  \ns bonds have better overlap than p bonds (big S)  \nYour name   Grade this page    \n2. In class we frequently discussed the O2 molecular orbital diagram. F2 has a similar diagram, but of course with 2 more electrons.  \na. (10 points) Draw a MO energy level diagram for F2 , including the atomic orbitals. You need not include the core electrons. Be sure to draw an energy axis and draw in arrows for the electrons. Include labels for s , p , bonding, and antibonding.  \nb. (10 points) Using the MO from part a, fill in this table of bond orders and number of electrons for molecules similar to F2.  \n\n| Molecule | F2- | F2 | F2+ | F2+2 | F2+3 |\n| --- | --- | --- | --- | --- | --- |\n| Total number of electrons | 15 | 14 | 13 | 12 | 11 |\n| Bond order | 1/2 | 1 | 3/2 | 2 | 5/2 |\n\nYour name   Grade this page    \nc. (2 points) Which molecule in part b has the shortest bond and why?  \nF 2 +3 because it has the highest bond order (least antibonding of any choice)  \nd. (2 points) Which molecule in part b has the weakest bond and why?  \nF 2- because the bond order is the lowest, so the ato","cbCainwFvYBoESSU","https://ap.wps.com/l/cbCainwFvYBoESSU","pdf",507217,"English","# General\n# Lewis Diagrams\n# Vibrational Spectroscopy\n# MO Theory\n# Walsh diagram\n# Matching Problems","[{\"question\":\"What rules are given for the exam if a student is stuck on a problem?\",\"answer\":\"If stumped, move on to finish other problems and come back later if time permits. Students may use the whole class period.\"},{\"question\":\"How many vibrational modes should XeF4 have, according to the exam question?\",\"answer\":\"The exam uses the relation 3N-6 = 9, so XeF4 has 9 vibrational modes.\"},{\"question\":\"What technique is suggested for observing the mode that is neither Raman nor IR active?\",\"answer\":\"The exam suggests inelastic neutron scattering and discusses whether NRVS using the Xe nucleus would be an option, concluding it is not because the vibration does not include any Xe motion.\"}]","Chem 104A - Midterm II - Total Exam Score | PDF",1792974286,23]