[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"doc-detail-207863-en":3,"doc-seo-207863-105":30,"detail-sidebar-cat-0-en-105":91},{"code":4,"msg":5,"data":6},0,"success",{"doc_id":7,"user_id":8,"nickname":9,"user_avatar":10,"doc_module":4,"category_id":11,"category_name":12,"doc_title":13,"doc_description":14,"doc_content":15,"file_id":16,"file_url":17,"file_type":18,"file_size":19,"view_count":20,"is_deleted":4,"is_public":20,"is_downloadable":20,"audit_status":20,"page_count":21,"language":22,"language_code":23,"site_id":24,"html_lang":23,"table_of_contents":25,"faqs":26,"seo_title":27,"seo_description":14,"update_tm":28,"read_time":29},207863,1099523885336,"Taylor Morgan","https://ap-avatar.wpscdn.com/davatar_276721f389ce27ea32af1340a28f341c",4,"Exam","AQA GCSE Physics - 5.5 Pressure - 5.5.1 Pressure","Revision notes for AQA GCSE Physics topic 5.5 on pressure in fluids, focusing on what pressure is, how it acts in liquids and gases, and why smaller contact areas create larger pressure. Includes real-life examples such as drawing pins, tractors, and nails, plus explanation of forces exerted at right angles to surfaces when objects are immersed in fluids. Provides the pressure equation, unit of measurement, and a worked calculation example with unit guidance and significant-figure rounding.","Head to www.savemyexams. com for more awesome resources  \n AQA GCSE Physics  \n5 .5 Pressure & Pressure Diyerences in Fluids  \nContents  \n 5.5.1 Pressure  \n 5.5.2 Atmospheric Pressure  \n 5.5.3 Pressure in a Liquid  \n 5.5.4 Upthrust  \nPage 1 of 20  \n© 2015 − 2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers  \nYour notes  \nHead to www.savemyexams. com for more awesome resources  \n5.5.1 Pressure  \nPressure in a Fluid  \n A }uid is either a liquid or a gas  \n Pressure is de|ned as  \nThe concentration of a force orthe force per unit area  \n For example, when a drawing pin is pushed downwards:  \n It is pushed into the surface, rather than up towards the |nger  \n This is because the sharp point is more concentrated (a small area) creating a larger pressure  \nWhen you push a drawing pin, it goes into the surface (rather than your |nger)  \n Example 1: Tractors  \n Tractors have large tyres  \n This spreads the weight (force) of the tractor over a large area  \n This reduces the pressure which prevents the heavy tractor from sinking into the mud  \n Example 2: Nails  \n Nails have sharp pointed ends with avery small area  \n This concentrates the force, creating a large pressure over a small area  \n This allows the nail to be hammered into a wall  \n When an object is immersed in a liquid, the liquid will exert pressure, squeezing the object  \nPage 2 of 20  \n© 2015 − 2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers  \nYour notes  \nHead to www.savemyexams. com for more awesome resources  \n The pressure exerted on objects in }uids creates forces against surfaces  \n These forces act at 90 degrees (at right angles) to the surface  \nThe pressure of a }uidonan object creates a force normal (at right angles) to the surface  \nPage 3 of 20  \n© 2015 − 2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers  \nYour notes  \nHead to www.savemyexams. com for more awesome resources  \nCalculating Pressure  \n The pressure atthe surface of a }uid can be calculated using the equation:  \nPressure is measured in the units Pascals (Pa)  \n The area should always bethe cross-sectional area of the object  \n This means the area where the force is at right angles to it  \n This equation can be rearranged with the help of a formula triangle:  \nPage 4 of 20  \n© 2015 − 2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers  \nYour notes  \nHead to www.savemyexams. com for more awesome resources  \nThis equation means:  \n If a force is spread over a large area it will result in a small pressure  \n If it is spread over a small area itwill result in a large pressure  \nPage 5 of 20  \n© 2015 − 2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers  \nYour notes  \nHead to www.savemyexams. com for more awesome resources  \nHigh heels produce a higher pressure on the ground because of their smaller area, compared to }at  \nshoes  \nPage 6 of 20  \n© 2015 − 2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers  \nYour notes  \nHead to www.savemyexams. com for more awesome resources  \n Worked example  \nThe diagram below shows the parts of the lifting machine used to move the platform up and down.  \nThe pump creates pressure in the liquid of 5 .28 × 105 Pato move the platform upwards. Calculate the force that the liquid applies to the piston.  \nStep 1: List the known quantities  \n Cross-sectional area = 2 .73 × 10-2 m2  \n Pressure = 5 .28 × 105 Pa  \nStep 2: Write down the relevant equation  \nStep 3: Rearrange for the force, F  \nF = p × A  \nStep 4: Substitute the values into the equation  \nPage 7 of 20  \n© 2015 − 2024 Save My Exams, Ltd. · Revision Notes, Topic Questions, Past Papers  \nYour notes  \nHead to www.savemyexams. com for more awesome resources  \nF = (5 .28 × 105) × (2 .73 × 10-2) = 14 414 .4  \nStep 5: Round to the appropriate number of signi|cant |guresand quote the correct unit  \nF = 14 400 N = 14 .4 kN (3 s.f )  \n Examiner Tip  \nLook out for the units for the force!Large press","cbCais4IT77fE5S5","https://ap.wps.com/l/cbCais4IT77fE5S5","pdf",3017123,1,20,"English","en",105,"# 5.5 Pressure & Pressure Differences in Fluids\n## 5.5.1 Pressure\n## 5.5.2 Atmospheric Pressure","[{\"question\":\"What does pressure mean in the context of fluids?\",\"answer\":\"Pressure is defined as the force per unit area. In fluids, that pressure acts on surfaces and can create forces.\"},{\"question\":\"Why does a drawing pin produce a larger pressure when pushed down?\",\"answer\":\"The sharp point has a very small area, so the same force is concentrated over a smaller area, creating larger pressure.\"},{\"question\":\"How is pressure calculated and measured?\",\"answer\":\"Pressure can be calculated using Pressure = force ÷ area (F = p × A when rearranged). Pressure is measured in Pascals (Pa).\"}]","AQA GCSE Physics - 5.5 Pressure - 5.5.1 Pressure | PDF",1788601475,50,{"code":4,"msg":31,"data":32},"ok",{"site_id":24,"language":23,"slug":33,"title":13,"keywords":34,"description":14,"schema_data":35,"social_meta":86,"head_meta":88,"extra_data":90,"updated_unix":28},"aqa-gcse-physics-55-pressure-551-pressure","",{"@graph":36,"@context":85},[37,53,68],{"@type":38,"itemListElement":39},"BreadcrumbList",[40,44,48,51],{"item":41,"name":42,"@type":43,"position":20},"https://docshare.wps.com","Home","ListItem",{"item":45,"name":46,"@type":43,"position":47},"https://docshare.wps.com/document/","Document",2,{"item":49,"name":12,"@type":43,"position":50},"https://docshare.wps.com/document/exam/",3,{"item":52,"name":13,"@type":43,"position":11},"https://docshare.wps.com/document/aqa-gcse-physics-55-pressure-551-pressure/207863/",{"url":52,"name":13,"@type":54,"author":55,"headline":13,"publisher":57,"fileFormat":60,"inLanguage":23,"description":14,"dateModified":61,"datePublished":62,"encodingFormat":60,"isAccessibleForFree":63,"interactionStatistic":64},"DigitalDocument",{"name":9,"@type":56},"Person",{"url":41,"name":58,"@type":59},"DocShare","Organization","application/pdf","2026-09-07","2026-09-05",true,{"@type":65,"interactionType":66,"userInteractionCount":20},"InteractionCounter",{"@type":67},"ViewAction",{"@type":69,"mainEntity":70},"FAQPage",[71,77,81],{"name":72,"@type":73,"acceptedAnswer":74},"What does pressure mean in the context of fluids?","Question",{"text":75,"@type":76},"Pressure is defined as the force per unit area. In fluids, that pressure acts on surfaces and can create forces.","Answer",{"name":78,"@type":73,"acceptedAnswer":79},"Why does a drawing pin produce a larger pressure when pushed down?",{"text":80,"@type":76},"The sharp point has a very small area, so the same force is concentrated over a smaller area, creating larger pressure.",{"name":82,"@type":73,"acceptedAnswer":83},"How is pressure calculated and measured?",{"text":84,"@type":76},"Pressure can be calculated using Pressure = force ÷ area (F = p × A when rearranged). 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