[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"doc-seo-456952-105":3,"doc-detail-456952-en":81,"detail-sidebar-cat-0-en-105":98},{"code":4,"msg":5,"data":6},0,"ok",{"site_id":7,"language":8,"slug":9,"title":10,"keywords":11,"description":12,"schema_data":13,"social_meta":74,"head_meta":76,"extra_data":78,"updated_unix":80},105,"en","apstat-chapter-10-test","APstat Chapter 10 Test","","Practice and assessment questions on statistical inference for comparing population parameters. Covers selecting appropriate tests for differences in means and proportions, interpreting one-sided P-values, computing sampling variability for differences in sample proportions, and using confidence intervals to judge evidence for treatment effects. Includes SAS-style output for a two-sample comparison of means from two varieties, calculations of t-test statistics and P-values, and applied problems involving nitrites and nicotine cessation with hypothesis tests and confidence intervals.",{"@graph":14,"@context":73},[15,34,56],{"@type":16,"itemListElement":17},"BreadcrumbList",[18,23,27,31],{"item":19,"name":20,"@type":21,"position":22},"https://docshare.wps.com","Home","ListItem",1,{"item":24,"name":25,"@type":21,"position":26},"https://docshare.wps.com/document/","Document",2,{"item":28,"name":29,"@type":21,"position":30},"https://docshare.wps.com/document/exam/","Exam",3,{"item":32,"name":10,"@type":21,"position":33},"https://docshare.wps.com/document/apstat-chapter-10-test/456952/",4,{"url":32,"name":10,"@type":35,"image":36,"author":41,"headline":10,"publisher":44,"fileFormat":47,"inLanguage":8,"description":12,"dateModified":48,"datePublished":49,"encodingFormat":47,"isAccessibleForFree":50,"interactionStatistic":51},"DigitalDocument",{"url":37,"@type":38,"width":39,"height":40},"https://docshare.wps.com/thumbnails/apstat-chapter-10-test/456952.png","ImageObject",300,407,{"name":42,"@type":43},"Mabel","Person",{"url":19,"name":45,"@type":46},"DocShare","Organization","application/pdf","2026-10-23","2026-09-30",true,{"@type":52,"interactionType":53,"userInteractionCount":55},"InteractionCounter",{"@type":54},"ViewAction",10,{"@type":57,"mainEntity":58},"FAQPage",[59,65,69],{"name":60,"@type":61,"acceptedAnswer":62},"Which test should be used to compare two means from two independent normally distributed populations when variances are unknown?","Question",{"text":63,"@type":64},"The questions target the choice of the appropriate two-sample method for means; among the provided options, it asks for the correct category of procedure for independent samples.","Answer",{"name":66,"@type":61,"acceptedAnswer":67},"How should a one-sided P-value from a two-sample t test be interpreted?",{"text":68,"@type":64},"The P-value is the probability of observing a result at least as extreme as the one obtained in the direction specified by the alternative, assuming the null hypothesis is true.",{"name":70,"@type":61,"acceptedAnswer":71},"How can confidence intervals be used to conclude whether a drug decreases or increases an effect?",{"text":72,"@type":64},"If a confidence interval for the difference includes zero, there is insufficient evidence of a difference at the stated confidence level; if it excludes zero, there is evidence of an effect consistent with the interval’s direction.","https://schema.org",{"og:url":32,"og:type":75,"og:title":10,"og:site_name":45,"og:description":12},"article",{"robots":77,"canonical":32},"index,follow",{"doc_id":79,"site_id":7},456952,1791130784,{"code":4,"msg":82,"data":83},"success",{"doc_id":79,"user_id":84,"nickname":42,"user_avatar":85,"doc_module":4,"category_id":33,"category_name":29,"doc_title":10,"doc_description":12,"doc_content":86,"file_id":87,"file_url":88,"file_type":89,"file_size":90,"view_count":55,"is_deleted":4,"is_public":22,"is_downloadable":22,"audit_status":22,"page_count":91,"language":92,"language_code":8,"site_id":7,"html_lang":8,"table_of_contents":93,"faqs":94,"seo_title":95,"seo_description":12,"update_tm":96,"read_time":97},7971474920318,"https://ap-avatar.wpscdn.com/avatar/74000ee537e6b0ca360?x-image-process=image/resize,m_fixed,w_180,h_180&k=1788430171632181674","Directions: Submit these answers to the Google Form.  \nPart 1: Multiple Choice. Circle the letter corresponding to the best answer.  \n1. Suppose we have two independent SRSs from two distinct populations, and we measure the same variable for both samples. Suppose both populations are known to be Normally distributed but the means and standard deviations are unknown. For purposes of comparing the two means, we use  \n(a) Matched pairs t procedures (b) Two-sample t procedures (c) Two-proportion z procedures (d) The least-squares regression line  \n2. We wish to test if a new feed increases the mean weight gain compared to an old feed. At the conclusion of the experiment it was found that the new feed gave a 10 kg bigger gain than the old feed. A two-sample t test with the proper one-sided alternative was done and the resulting P-value was 0.082. This means that  \n(a) there was only an 8.2% chance of observing an increase greater than 10 kg (if the null hypothesis is false) .  \n(b) there was only an 8.2% chance of observing an increase greater than 10 kg (if the null hypothesis is true) .  \n(c) there is an 8.2% chance the null hypothesis is true.  \n(d) there is an 8.2% chance the alternative hypothesis is true.  \n3. An SRS of size 100 is taken from a population having proportion 0.8 successes. An independent SRS of size 400 is taken from a population having proportion 0.5 successes. What is the standard deviation of the sampling distribution of the difference in sample proportions?  \n(a) 0.15  \n(b) 0.30  \n(c) 0.047  \n(d) 0.053  \n(e) None of the above. The answer is   .  \n4. A study was conducted to investigate the effectiveness of a new drug for treating Stage 4 AIDS patients. A group of AIDS patients was randomly divided into two groups. One group received the new drug; the other group received a placebo. The difference in mean subsequent survival (those with drugs – those without drugs) was found to be 1.04 years, and a 95% confidence interval was found to be 1.04 ± 2.37 years. Based upon this information, we can conclude that  \n(a) the drug was effective since those taking the drug lived, on average, 1.04 years longer.  \n(b) the drug was ineffective since those taking the drug lived, on average, 1.04 years less.  \n(c) there is not enough evidence the drug is effective since the 95% CI covers zero.  \n(d) there is enough evidence the drug is effective since the 95% CI does not cover zero.  \nThe next two questions refer to this scenario:  \nYou are doing a test to compare the mean carbohydrate content of two different varieties of baby food made from different kinds of peaches. The data were analyzed with SAS computer software, and the following output was obtained:  \nVARIETY N MEAN STD DEV STD ERROR MIN MAX  \n1 5 33.6 3.781 1.691 29.000 38.000  \n2 7 25.0 10.392 3.927 2.000 33.000  \nVARIANCES T DF PROB > |T|  \nUNEQUAL 2.0110 8.0 0.0791  \nEQUAL 1.7490 10.0 0.1109  \n5. We wish to test if the two varieties of baby food have different mean carbohydrate contents. The null and alternative hypotheses for this test should be which of these?  \n(a) H0 : µ1 = µ2 ; Ha : µ1 \u003C µ2  \n(b) H0 : µ1 = µ2 ; Ha : µ1 > µ2  \n(c) H0 : µ1 = µ2 ; Ha : µ1 ≠ µ2  \n(d) H0 : x1 = x2 ; Ha : x1 \u003C x2  \n(e) H0 : x1 = x2 ; Ha : x1 ≠ x2  \n6. Which of these pairs of numbers are the correct test statistic and P-value for this test?  \n(a) 1.7490; 0.0318 (b) 1.7490; 0.0554 (c) 2.0110; 0.1109 (d) 2.0110; 0.0791  \n(e) 2.0110; 0.0396  \n7. In Company A, 35 workers from a random sample of 125 workers admitted to calling out sick when they weren’t really ill. In Company B, 17 employees from a random sample of 68 workers admitted to calling out sick when they weren’t really ill. A 95% Confidence Interval for the difference in the proportions of workers at the two companies who would admit to calling out sick when they weren’t really ill is  \n(a) 0.03 ± 1.96&%$ ~~ ~~1125 + ~~ ~~618 \\#\"! (0.269 )(0.731)  \n(b) 0.03 ± 1.645$&% ~~ ~~1125 + ~~ ~~618 \\#\"!(0.269 )(0.731)  \n(c) 0.03 ± (0.2","cbCaiuSlY5FpPV0y","https://ap.wps.com/l/cbCaiuSlY5FpPV0y","pdf",293084,5,"English","# Part 1: Multiple Choice\n## Questions 1-7\n# Part 2: Free Response\n## Questions 8-10","[{\"question\":\"Which test should be used to compare two means from two independent normally distributed populations when variances are unknown?\",\"answer\":\"The questions target the choice of the appropriate two-sample method for means; among the provided options, it asks for the correct category of procedure for independent samples.\"},{\"question\":\"How should a one-sided P-value from a two-sample t test be interpreted?\",\"answer\":\"The P-value is the probability of observing a result at least as extreme as the one obtained in the direction specified by the alternative, assuming the null hypothesis is true.\"},{\"question\":\"How can confidence intervals be used to conclude whether a drug decreases or increases an effect?\",\"answer\":\"If a confidence interval for the difference includes zero, there is insufficient evidence of a difference at the stated confidence level; if it excludes zero, there is evidence of an effect consistent with the interval’s direction.\"}]","APstat Chapter 10 Test | PDF",1790747700,13,{"code":4,"msg":82,"data":99},[100,104,108,111,115,120,125,130,135,138,141],{"id":22,"doc_module":4,"doc_module_name":25,"category_name":101,"show_sort_weight":102,"slug":103},"Story & Novel",90,"story-novel",{"id":26,"doc_module":4,"doc_module_name":25,"category_name":105,"show_sort_weight":106,"slug":107},"Literature",80,"literature",{"id":33,"doc_module":4,"doc_module_name":25,"category_name":29,"show_sort_weight":109,"slug":110},70,"exam",{"id":91,"doc_module":4,"doc_module_name":25,"category_name":112,"show_sort_weight":113,"slug":114},"Comic",60,"comic",{"id":116,"doc_module":4,"doc_module_name":25,"category_name":117,"show_sort_weight":118,"slug":119},6,"Technology",50,"technology",{"id":121,"doc_module":4,"doc_module_name":25,"category_name":122,"show_sort_weight":123,"slug":124},7,"Healthcare",40,"healthcare",{"id":126,"doc_module":4,"doc_module_name":25,"category_name":127,"show_sort_weight":128,"slug":129},8,"Research & Report",30,"research-report",{"id":131,"doc_module":4,"doc_module_name":25,"category_name":132,"show_sort_weight":133,"slug":134},9,"Religion & Spirituality",20,"religion-spirituality",{"id":133,"doc_module":4,"doc_module_name":25,"category_name":136,"show_sort_weight":133,"slug":137},"World Cup","world-cup",{"id":55,"doc_module":4,"doc_module_name":25,"category_name":139,"show_sort_weight":55,"slug":140},"Lifestyle","lifestyle",{"id":142,"doc_module":4,"doc_module_name":25,"category_name":143,"show_sort_weight":91,"slug":144},19,"General","general"]