[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"doc-seo-665569-105":3,"detail-sidebar-cat-0-en-105":80,"doc-detail-665569-en":130},{"code":4,"msg":5,"data":6},0,"ok",{"site_id":7,"language":8,"slug":9,"title":10,"keywords":11,"description":12,"schema_data":13,"social_meta":73,"head_meta":75,"extra_data":77,"updated_unix":79},105,"en","ap-chemistry-pes-sample-questions-electron-configurations-and-binding-energy","AP® Chemistry: PES - Sample Questions - Electron Configurations and Binding Energy","","AP Chemistry practice questions centered on photoelectron spectroscopy (PES) interpretation. Problems ask students to identify elements from given PES spectra, determine electron configurations, and explain peak positions and intensities across sublevels such as 2s, 2p, 3s, and 3p. Additional items connect spectral features to effective nuclear charge, electron shielding, electron-electron repulsions, binding energy differences, and common ion formation, including a drawing task for a related element. An answer key is provided.",{"@graph":14,"@context":72},[15,34,55],{"@type":16,"itemListElement":17},"BreadcrumbList",[18,23,27,31],{"item":19,"name":20,"@type":21,"position":22},"https://docshare.wps.com","Home","ListItem",1,{"item":24,"name":25,"@type":21,"position":26},"https://docshare.wps.com/document/","Document",2,{"item":28,"name":29,"@type":21,"position":30},"https://docshare.wps.com/document/exam/","Exam",3,{"item":32,"name":10,"@type":21,"position":33},"https://docshare.wps.com/document/ap-chemistry-pes-sample-questions-electron-configurations-and-binding-energy/665569/",4,{"url":32,"name":10,"@type":35,"image":36,"author":41,"headline":10,"publisher":44,"fileFormat":47,"inLanguage":8,"description":12,"dateModified":48,"datePublished":49,"encodingFormat":47,"isAccessibleForFree":50,"interactionStatistic":51},"DigitalDocument",{"url":37,"@type":38,"width":39,"height":40},"https://docshare.wps.com/thumbnails/ap-chemistry-pes-sample-questions-electron-configurations-and-binding-energy/665569.png","ImageObject",300,407,{"name":42,"@type":43},"Boyslovefans","Person",{"url":19,"name":45,"@type":46},"DocShare","Organization","application/pdf","2026-10-30","2026-10-29",true,{"@type":52,"interactionType":53,"userInteractionCount":33},"InteractionCounter",{"@type":54},"ViewAction",{"@type":56,"mainEntity":57},"FAQPage",[58,64,68],{"name":59,"@type":60,"acceptedAnswer":61},"How do these PES questions ask you to identify elements?","Question",{"text":62,"@type":63},"They provide PES spectra and ask which option matches the element represented by the spectrum. You then infer the element based on characteristic peak positions and energy levels.","Answer",{"name":65,"@type":60,"acceptedAnswer":66},"What concepts are used to explain differences in PES peak positions (e.g., 2s and 2p)?",{"text":67,"@type":63},"The questions emphasize effective nuclear charge, electron shielding, and electron-electron repulsions. These factors affect binding energy and therefore shift peaks left or right on the horizontal axis.",{"name":69,"@type":60,"acceptedAnswer":70},"How is signal intensity on a PES spectrum interpreted in these problems?",{"text":71,"@type":63},"The questions focus on how electron arrangement and shielding influence the measured signal intensity for specific sublevels, such as the 3s electrons for Na and K.","https://schema.org",{"og:url":32,"og:type":74,"og:title":10,"og:site_name":45,"og:description":12},"article",{"robots":76,"canonical":32},"index,follow",{"doc_id":78,"site_id":7},665569,1793304992,{"code":4,"msg":81,"data":82},"success",[83,87,91,94,99,104,109,114,119,122,126],{"id":22,"doc_module":4,"doc_module_name":25,"category_name":84,"show_sort_weight":85,"slug":86},"Story & Novel",90,"story-novel",{"id":26,"doc_module":4,"doc_module_name":25,"category_name":88,"show_sort_weight":89,"slug":90},"Literature",80,"literature",{"id":33,"doc_module":4,"doc_module_name":25,"category_name":29,"show_sort_weight":92,"slug":93},70,"exam",{"id":95,"doc_module":4,"doc_module_name":25,"category_name":96,"show_sort_weight":97,"slug":98},5,"Comic",60,"comic",{"id":100,"doc_module":4,"doc_module_name":25,"category_name":101,"show_sort_weight":102,"slug":103},6,"Technology",50,"technology",{"id":105,"doc_module":4,"doc_module_name":25,"category_name":106,"show_sort_weight":107,"slug":108},7,"Healthcare",40,"healthcare",{"id":110,"doc_module":4,"doc_module_name":25,"category_name":111,"show_sort_weight":112,"slug":113},8,"Research & Report",30,"research-report",{"id":115,"doc_module":4,"doc_module_name":25,"category_name":116,"show_sort_weight":117,"slug":118},9,"Religion & Spirituality",20,"religion-spirituality",{"id":117,"doc_module":4,"doc_module_name":25,"category_name":120,"show_sort_weight":117,"slug":121},"World Cup","world-cup",{"id":123,"doc_module":4,"doc_module_name":25,"category_name":124,"show_sort_weight":123,"slug":125},10,"Lifestyle","lifestyle",{"id":127,"doc_module":4,"doc_module_name":25,"category_name":128,"show_sort_weight":95,"slug":129},19,"General","general",{"code":4,"msg":81,"data":131},{"doc_id":78,"user_id":132,"nickname":42,"user_avatar":133,"doc_module":4,"category_id":33,"category_name":29,"doc_title":10,"doc_description":12,"doc_content":134,"file_id":135,"file_url":136,"file_type":137,"file_size":138,"view_count":33,"is_deleted":4,"is_public":22,"is_downloadable":22,"audit_status":22,"page_count":100,"language":139,"language_code":8,"site_id":7,"html_lang":8,"table_of_contents":140,"faqs":141,"seo_title":142,"seo_description":12,"update_tm":79,"read_time":143},1374410101428,"https://ap-avatar.wpscdn.com/davatar_3d24733baf745e90a7e4bdd5f77d97b2","1  \nAP® Chemistry: PES  \nAnalyzing data from PES  \n1. Which of the following elements might this spectrum represent?  \n(A) He (B) N  \n(C) Ne  \n(D) Ar  \n2. Given the spectrum above, identify the element and its electron configuration:(A) B  \n(B) Al  \n(C) Si  \n(D) Na  \n© 2013 The College Board.  \n2  \nSample Questions  \n1. Which element could be represented by the complete PES spectrum below?  \na. Li  \nb. B  \nc. N  \nd. Ne  \n2. Which of the following best explains the relative positioning and intensity of the 2s peaks in the following spectra?  \na. Be has a greater nuclear charge than Li and more electrons in the 2s orbital  \nb. Be electrons experience greater electron-electron repulsions than Li electrons  \nc. Li has a greater pull from the nucleus on the 2s electrons, so they are harder to remove  \nd. Li has greater electron shielding by the 1s orbital, so the 2s electrons are easier to remove  \n© 2013The College Board.  \n3  \n3. Given the photoelectron spectra above for phosphorus, P, and sulfur, S, which of the following best explains why the 2p peak for S is further to the left than the 2p peak for P, but the 3p peak for S is further to the right than the 3p peak for P?  \na. S has a greater effective nuclear charge than P, and the 3p sublevel in S has greater electron repulsions than in P.  \nb. S has a greater effective nuclear charge than P, and the 3p sublevel is more heavily shielded in S than in P.  \nc. S has a greater number of electrons than P, so the third energy level is further from the nucleus in S than in P.  \nd. S has a greater number of electrons than P, so the Coulombic attraction between the electron cloud and the nucleus is greater in S than in P.  \n4. Looking at the spectra for Na and K above, which of the following would best explain the difference in binding energy for the 3s electrons?  \na. K has a greater nuclear charge than Na  \nb. K has more electron-electron repulsions than Na  \nc. Na has one valence electron  \nd. Na has less electron shielding than K  \n© 2013The College Board.  \n4  \n5. Looking at the spectra for Na and K above, which of the following would best explain the difference in signal intensity for the 3s electrons?  \na. K has a greater nuclear charge than Na  \nb. K has more electron-electron repulsions than Na  \nc. Na has one valence electron  \nd. Na has less electron shielding than K  \n6. Given the photoelectron spectrum above, which of the following best explains the relative positioning of the peaks on the horizontal axis?  \na. O has more valence electrons than Ti or C, so more energy is required to remove them  \nb. O has more electron-electron repulsions in the 2p sublevel than Ti and C  \nc. Ti atoms are present in a greater quantity than O than C in the mixture.  \nd. Ti has a greater nuclear charge, but the 2p sublevel experiences greater shielding than the 1s sublevel.  \n© 2013The College Board.  \n5  \n7. Given the photoelectron spectrum of Scandium above, which of the following best explains why Scandium commonly makes a 3+ ion as opposed to a 2+ ion?  \na. Removing 3 electrons releases more energy than removing 2 electrons.  \nb. Scandium is in Group 3, and atoms only lose the number of electrons that will result in a noble gas electron configuration  \nc. The amount of energy required to remove an electron from the 3d sublevel is close to that for the 4s sublevel, but significantly more energy is needed to remove electrons from the 3p sublevel.  \nd. Removing 2 electrons alleviates the spin-pairing repulsions in the 4s sublevel, so it isnot as energetically favorable as emptying the 4s sublevel completely.  \n8. On the photoelectron spectrum for magnesium given above, draw the spectrum for aluminum.  \n© 2013The College Board.  \n6  \nAnswer Key  \n1. C 2. A 3. A 4. A 5. C 6. D 7. C  \n© 2013The College Board.","cbCaip74e0kQRlPW","https://ap.wps.com/l/cbCaip74e0kQRlPW","pdf",364311,"English","# Sample Questions\n## Element identification and electron configuration\n## Interpreting peak positions and intensities\n## Explaining binding energy and ion formation","[{\"question\":\"How do these PES questions ask you to identify elements?\",\"answer\":\"They provide PES spectra and ask which option matches the element represented by the spectrum. You then infer the element based on characteristic peak positions and energy levels.\"},{\"question\":\"What concepts are used to explain differences in PES peak positions (e.g., 2s and 2p)?\",\"answer\":\"The questions emphasize effective nuclear charge, electron shielding, and electron-electron repulsions. These factors affect binding energy and therefore shift peaks left or right on the horizontal axis.\"},{\"question\":\"How is signal intensity on a PES spectrum interpreted in these problems?\",\"answer\":\"The questions focus on how electron arrangement and shielding influence the measured signal intensity for specific sublevels, such as the 3s electrons for Na and K.\"}]","AP® Chemistry: PES - Sample Questions - Electron Configurations and Binding Energy | PDF",15]