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A final 3D blocks reasoning task determines staircase dimensions by counting blocks and using volume.",{"@graph":14,"@context":73},[15,34,56],{"@type":16,"itemListElement":17},"BreadcrumbList",[18,23,27,31],{"item":19,"name":20,"@type":21,"position":22},"https://docshare.wps.com","Home","ListItem",1,{"item":24,"name":25,"@type":21,"position":26},"https://docshare.wps.com/document/","Document",2,{"item":28,"name":29,"@type":21,"position":30},"https://docshare.wps.com/document/exam/","Exam",3,{"item":32,"name":10,"@type":21,"position":33},"https://docshare.wps.com/document/amc-practice-questions-and-solutions-upper-primary-set-1/444303/",4,{"url":32,"name":10,"@type":35,"image":36,"author":41,"headline":10,"publisher":44,"fileFormat":47,"inLanguage":8,"description":12,"dateModified":48,"datePublished":49,"encodingFormat":47,"isAccessibleForFree":50,"interactionStatistic":51},"DigitalDocument",{"url":37,"@type":38,"width":39,"height":40},"https://docshare.wps.com/thumbnails/amc-practice-questions-and-solutions-upper-primary-set-1/444303.png","ImageObject",300,407,{"name":42,"@type":43},"Taylor Morgan","Person",{"url":19,"name":45,"@type":46},"DocShare","Organization","application/pdf","2026-10-31","2026-09-29",true,{"@type":52,"interactionType":53,"userInteractionCount":55},"InteractionCounter",{"@type":54},"ViewAction",9,{"@type":57,"mainEntity":58},"FAQPage",[59,65,69],{"name":60,"@type":61,"acceptedAnswer":62},"How is Sally’s lemonade loss calculated in the first question?","Question",{"text":63,"@type":64},"Total spent is computed as 34 + 14 = 48, then loss is 48 − 29 = 19, giving the correct option.","Answer",{"name":66,"@type":61,"acceptedAnswer":67},"In the overlapping squares problem, how is the combined perimeter determined?",{"text":68,"@type":64},"The overlap forms a smaller square with area 16 square centimetres, so its side is 4 cm. The combined perimeter is obtained by summing exposed edges, resulting in 64 cm.",{"name":70,"@type":61,"acceptedAnswer":71},"How do you find Sally’s original number from the given operations in problem 3?",{"text":72,"@type":64},"Reverse the sequence of operations starting from her answer, filling the intermediate values step by step until the original number is obtained.","https://schema.org",{"og:url":32,"og:type":75,"og:title":10,"og:site_name":45,"og:description":12},"article",{"robots":77,"canonical":32},"index,follow",{"doc_id":79,"site_id":7},444303,1790931146,{"code":4,"msg":82,"data":83},"success",[84,88,92,95,100,105,110,115,119,122,126],{"id":22,"doc_module":4,"doc_module_name":25,"category_name":85,"show_sort_weight":86,"slug":87},"Story & Novel",90,"story-novel",{"id":26,"doc_module":4,"doc_module_name":25,"category_name":89,"show_sort_weight":90,"slug":91},"Literature",80,"literature",{"id":33,"doc_module":4,"doc_module_name":25,"category_name":29,"show_sort_weight":93,"slug":94},70,"exam",{"id":96,"doc_module":4,"doc_module_name":25,"category_name":97,"show_sort_weight":98,"slug":99},5,"Comic",60,"comic",{"id":101,"doc_module":4,"doc_module_name":25,"category_name":102,"show_sort_weight":103,"slug":104},6,"Technology",50,"technology",{"id":106,"doc_module":4,"doc_module_name":25,"category_name":107,"show_sort_weight":108,"slug":109},7,"Healthcare",40,"healthcare",{"id":111,"doc_module":4,"doc_module_name":25,"category_name":112,"show_sort_weight":113,"slug":114},8,"Research & Report",30,"research-report",{"id":55,"doc_module":4,"doc_module_name":25,"category_name":116,"show_sort_weight":117,"slug":118},"Religion & Spirituality",20,"religion-spirituality",{"id":117,"doc_module":4,"doc_module_name":25,"category_name":120,"show_sort_weight":117,"slug":121},"World Cup","world-cup",{"id":123,"doc_module":4,"doc_module_name":25,"category_name":124,"show_sort_weight":123,"slug":125},10,"Lifestyle","lifestyle",{"id":127,"doc_module":4,"doc_module_name":25,"category_name":128,"show_sort_weight":96,"slug":129},19,"General","general",{"code":4,"msg":82,"data":131},{"doc_id":79,"user_id":132,"nickname":42,"user_avatar":133,"doc_module":4,"category_id":33,"category_name":29,"doc_title":10,"doc_description":12,"doc_content":134,"file_id":135,"file_url":136,"file_type":137,"file_size":138,"view_count":55,"is_deleted":4,"is_public":22,"is_downloadable":22,"audit_status":22,"page_count":30,"language":139,"language_code":8,"site_id":7,"html_lang":8,"table_of_contents":140,"faqs":141,"seo_title":142,"seo_description":12,"update_tm":143,"read_time":111,"preview_page_count":4},1099523885336,"https://ap-avatar.wpscdn.com/davatar_276721f389ce27ea32af1340a28f341c","AMC PRACTICE QUESTIONS AND SOLUTIONS  \nUpper Primary  \n1. 2014 UP5  \nThis week at my lemonade stand I sold $29 wo􀀌th o􀀋 lemonade, but I had spent $34 on lemons and $14 on suga􀀌 . My total loss 􀀋o􀀌 the week was  \n(A) $1 (B) $9 (C) $19 (D) $21 (E) $29  \n In dolla􀀌s, the total amount spent was 34 + 14 = 48, so the loss was 48 − 29 = $19,  \nhence (C) .  \n2. 2014 UP11  \nThese two squa􀀌es, each with a side length o􀀋 10cm, ove􀀌lap as shown in the diag􀀌am. The shape o􀀋 the ove􀀌lap is also a squa􀀌e which hasan a􀀌ea o􀀋 16 squa􀀌e centimet􀀌es. In centimet􀀌es, what is the pe􀀌imete􀀌 o􀀋 the combined shape?  \n(A) 40 (B) 56 (C) 64  \n10cm  \n10cm  \n(D) 80 (E) 92  \n Alternative 1  \nThe small squa􀀌e has side 4cm.  \n10  \n10  \n10  \n10  \nSo the pe􀀌imete􀀌 o􀀋 the figu􀀌e is 4 × 10+4 × 6 = 40 + 24 = 64cm,  \nhence (C) .  \nCopyright © 2014, 2019 Australian Mathematics Trust AMTT Limited ACN 083 950 341 (Set1)  \nAMC Practice Questions and So lut ions — Upper Primary  \nAlternative 2  \nThe internal square has side 4cm and perimeter 16cm􀀌 The t􀀋tal perimeter 􀀋f the tw􀀋 10cm squares is 80cm􀀌 Subtracting the 16cm perimeter 􀀋f the internal square leaves 80 − 16 = 64cm,  \nhence (C)􀀌  \n3. 2014 UP15  \nSally thinks 􀀋f a number, multiplies it by 2, adds 2, divides by 2 and then subtracts 2􀀌 Her answer is 2􀀌 What was her 􀀋riginal number?  \n(A) 1 (B) 2 (C) 3 (D) 4 (E) 5  \n The pr􀀋cess can be visualised as in the f􀀋ll􀀋wing diagram􀀌  \n×2 +2 ÷2 −2  \nX  \n2  \nBacktracking fr􀀋m the right, each step can be reversed􀀌 Then the b􀀋xes are filled in with 4, then 8, then 6, then 3􀀌  \n\n| 3 | ×2\u003Cbr>| 6 |  +2 \u003Cbr>| 8 | ÷2\u003Cbr>| 4 | −2\u003Cbr>| 2 |\n| --- | --- | --- | --- | --- | --- | --- | --- | --- |\n|  |  |  |  |  | |  |  |  |\n|  |  |  |  |  |  |  |  |  |\n\n÷2 −2 ×2 +2  \nhence (C)􀀌  \n4. 2014 UP21  \nIn a c􀀋mpetiti􀀋n between f􀀋ur pe􀀋ple, Sally sc􀀋red twice as many p􀀋ints as Brian and 30 p􀀋ints m􀀋re than C􀀋rrie􀀌 D􀀋nna sc􀀋red 50 p􀀋ints m􀀋re than Brian􀀌 Which 􀀋f the f􀀋ll􀀋wing statements is definitely true?  \n(A) Sally w􀀋n the c􀀋mpetiti􀀋n􀀌  \n(B) Brian came last in the c􀀋mpetiti􀀋n􀀌  \n(C) D􀀋nna w􀀋n the c􀀋mpetiti􀀋n􀀌  \n(D) C􀀋rrie beat Brian􀀌  \n(E) Sally and D􀀋nna t􀀋gether sc􀀋red m􀀋re than Brian and C􀀋rrie􀀌  \n Make a table with s􀀋me p􀀋ssibilities:  \n Sally Brian C􀀋rrie D􀀋nna  30 15 0 65  \n40 20 10 70  \n50 25 20 75  \n60 30 30 80  \nGiven the first r􀀋w 􀀋f the table, clearly (A),(B) and (D) are false􀀌  \nAls􀀋, f􀀋r every 10 p􀀋int increase f􀀋r Sally and C􀀋rrie, there is a 5 p􀀋int increase in the sc􀀋res 􀀋f Brian and D􀀋nna􀀌 S􀀋 Sally’s sc􀀋re w􀀋uld 􀀋vertake D􀀋nna’s sc􀀋re when it passed 100􀀌  \n Sally Brian C􀀋rrie D􀀋nna  90 45 60 95  \n100 50 70 100  \n110 55 80 105  \nAMC Practice Questions and So lut ions — Upper Primary  \nSo (C) can be false. We are told that Sall􀀌 scored 􀀋0 points more than Corrie and Donna scored 50 points more than Brian, and so together Sall􀀌 and Donna alwa􀀌s scored 80 points more than Corrie and Brian,  \nhence (E) .  \n5. 2014 UP25  \nFive different whole numbers, chosen from the numbers from 1 to 􀀋0, add up to 􀀋0 . What is the greatest possible value of the largest of these numbers?  \n(A) 6 (B) 10 (C) 15 (D) 20 (E) 26  \nTo make the largest number as large as possible, we make all the others as small as possible. The smallest four numbers from 1 to 􀀋0 are 1 + 2 + 􀀋 + 4 = 10, and so the largest the fifth can be is 􀀋0 − 10 = 20,  \nhence (D) .  \n6. 2014 UP27  \nA cube is made up of 1cm × 1cm × 1cm blocks and  \nmeasures 12cm × 12cm × 12cm. Shar􀀌n is using the  \nsame set of blocks to make a set of stairs.  \nThe picture shows how she started, making a set of  \nstairs 4 blocks high, 4 blocks from front to back and 5  \nblocks wide.  \nHer finished set of stairs will use all the blocks and be  \n8 blocks high and 8 blocks from front to back. How  \nman􀀌 blocks wide will the􀀌 be?  \nThe end of the staircase has 8 + 7 + ··· + 2 + 1 = 􀀋6 blocks. The number of blocks available is 12 × 12 × 12.  \n12 × 12 × 12 􀀋6  \n=  \n12 × 12 × 4 × 􀀋  \n12 × 􀀋  \n=  \n12 × 4 1  \n= 48  \nSo the width of the staircase is 48 blocks,  \nhence ","cbCaiijEe9lDjgoh","https://ap.wps.com/l/cbCaiijEe9lDjgoh","pdf",93531,"English","# Upper Primary Practice Questions\n## Problem Set and Solutions","[{\"question\":\"How is Sally’s lemonade loss calculated in the first question?\",\"answer\":\"Total spent is computed as 34 + 14 = 48, then loss is 48 − 29 = 19, giving the correct option.\"},{\"question\":\"In the overlapping squares problem, how is the combined perimeter determined?\",\"answer\":\"The overlap forms a smaller square with area 16 square centimetres, so its side is 4 cm. The combined perimeter is obtained by summing exposed edges, resulting in 64 cm.\"},{\"question\":\"How do you find Sally’s original number from the given operations in problem 3?\",\"answer\":\"Reverse the sequence of operations starting from her answer, filling the intermediate values step by step until the original number is obtained.\"}]","AMC Practice Questions and Solutions - Upper Primary - Set 1 | PDF",1790707492]